How can I read individual characters in a string and determine if they are certain characters from the ascii table?

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I'm trying to have the user input a 6-character password. The first 3 characters should be capital letters and the last 3 characters should be numbers. If it's wrong, they have to re-enter the password. Finally, the password should be turned into a "secret password" by increasing the 6 characters by 2 (in the ascii table), and then have that new password printed out. I'm getting a run-time error and I don't understand why. Can anyone solve this?

String password = "", newPassword = password + 2;
		char char1 = password.charAt(1), char2 = password.charAt(2), char3 = password.charAt(3), char4 = password.charAt(4),
				char5 = password.charAt(5), char6 = password.charAt(6);
		
		System.out.println("Enter a 6-character password. The first three characters should be capital letters of "
				+ "the alphabet\nand the last three should be numbers from 1 to 9.");
		password = keyboard.next();
		
		if((char1 != 65 && !(char1 < 90)) || (char2 != 65 && !(char2 < 90)) || (char3 != 65 && !(char3 < 90)))
			System.out.println("Incorrect characters. Re-enter password.");
		password = keyboard.next();
		
		if((char4 != 1 && !(char4 < 9)) || (char5 != 1 && !(char5 < 9)) || (char6 != 1 && !(char6 < 9)))
			System.out.println("Incorrect characters. Re-enter password.");
		password = keyboard.next();
		
			System.out.print(password + "\n" + newPassword);

What I have tried:

I have tried changing the character variable declaration and getting rid of the password.charAt(1). I think that's what's giving me the issue, but I'm not sure how to make it read each character.

Posted 9-Feb-18 11:18am

Member 13670663

Updated 9-Feb-18 23:06pm

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PIEBALDconsult 9-Feb-18 18:21pm

Might be good if you provided the error text and the input that led to it.
I don't think you need to read each character on its own.

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Maciej Los · Answer 1 · 2018-02-09T22:46:00

Solution 1

Java well knows toCharArray() Method[^]

Java

String password = "password123456";
char[] characters = password.toCharArray();
for(int i=0;i<characters.length;i++)
{
    System.out.println(characters[i]);
}

Note: array index starts from 0 to count of elements in array -1.

See: Java Arrays[^]

Posted 9-Feb-18 22:46pm

Maciej Los

Updated 9-Feb-18 22:47pm

v2