To calculate using the COUNT() a percentage from a select statement

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SQL-Server-2008R2

Dear Expert,

Need to calculate using the COUNT() for the Whole and for a conditional COUNT()

as depicted below.

name age
-------------
amy 6
pam 8
joe 10
pet 16
jon 2
ana 12

A single Select statement to calculate the percentage of children who are above 10 using the
COUNT() function

in MS SQL SERVER 2008

Thanks

What I have tried:

I am able to calculate them separately, but I need One select statement

Posted 24-Jan-18 0:30am

Member 12770648

Updated 24-Jan-18 0:56am

OriginalGriff

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OriginalGriff · Accepted Answer · 2018-01-24T00:53:00

Solution 1

Try

SQL

SELECT COUNT(*) AS Total, SUM(CASE WHEN age > 10 THEN 1 ELSE 0 END) * 100 / COUNT(*) AS Percent FROM MyTable

Posted 24-Jan-18 0:53am

OriginalGriff

debasish mishra · Accepted Answer · 2018-01-24T00:56:00

Solution 2

Select Count (*) * 100 / (Select Count(*) From YourTable) as Score
From YourTable where age>10

Running Copy:SQL Fiddle[^]
Please don't directly copy and paste the sql.

Posted 24-Jan-18 0:56am

debasish mishra

Updated 24-Jan-18 1:17am

v6