Anyone know mips code?

Question

0.00/5 (No votes)

See more:

Hi
I have a project from my college to program in mips code. But the content of register doesn't increse
.I must program in mips to print if sum of digits of numbers from 1 to 1000 is divisible by 5 and 7 and not by 3 print
Sorry for my English

What I have tried:

.data
x: .word 1
.space 4000
li $v0,5
la $a0,x
syscall 
.data 


loop:
sw $t0,$a0
addi $t1,$zero,10
add $t4,$zero,$zero
rem $t4,$t0,$t1
div $t0,$t0,$t1
bne $t0,$zero,loop

rem $t5,$t4,5
bnez $t5,label
rem $t6,$t4,7
bnez $t6,label
rem $t7,$t4,3
beqz $t7,label

li $v0,1
move $a0,$t4

syscall 
j label

label:
add $a0,$a0,1

ble $t0,1000,loop
#li $v0,5
#la $a0,$t0
#syscall

Posted 18-Jan-18 7:32am

Member 13618628

Updated 18-Jan-18 10:20am

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

CPallini · Answer 1 · 2018-01-18T10:20:00

Yes, of course :-)

Well, my MIPS assembly is rusty. The following code, however, produces the correct result (tested on a simulator)

ASM

    li t0, 1	# t0 is the index of the loop (1..1000)	  
    li t1, 0    # t1 is the sum of the selected numbers
                # t2 is a temporary
    li t3, 3    # t3 holds the constant number 3
    li t5, 5    # t5 holds the constant number 5
    li t7, 7    # t7 holds the constant number 7
loop:
    rem t2, t0, t3
    beq t2, zero, skipadd
    nop
    rem t2, t0, t5
    bne t2, zero, skipadd
    nop
    rem t2, t0, t7
    bne t2, zero, skipadd
    nop
    addu t1, t1, t0
skipadd:
    addiu t0,t0, 1
    li t2,1001
    bne t0,t2, loop
    nop
    nop		 # here t1 contains the result