Why increment can not be work in logic?

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why k variable can not be increase in the given program?

What I have tried:

#include <stdio.h>
void main()
{
int k = 8;
int x = 0 == 1 && k++;
printf("%d %d\n", x, k);
}
OUTPUT:0 8

Posted 24-Dec-17 2:20am

Venkatesh Pyla

Updated 24-Dec-17 2:33am

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2 solutions

Solution 2

Read and learn: C++ Built-in Operators, Precedence and Associativity[^]

Posted 24-Dec-17 2:33am

Richard MacCutchan

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Thomas Daniels · Accepted Answer · 2017-12-24T02:26:00

This is because of a phenomenon called short-circuiting. This means that the right-hand of the && operator will not be evaluated if the result is already decided from the left-hand. 0 == 1 is 0/false. So, it doesn't matter what the right-hand (k++) would evaluate to, the final result is always 0/false (false && true is false, just like false && false). This means that the right-hand k++ never gets evaluated, so k doesn't get incremented.