As per the conceptual understanding pointer is pointing to the memory location after incrementing the array by 12 bytes in gcc compiler.

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C

#include<stdio.h>
int main()
{
	int a[3]={1,2,3};
	int *p;
	p=&a+2;
	*p=50;

	printf("p = %d\n",p);

	printf("*p = %u\n",*p);

	printf("z = %u\n",&a+1);

	printf("y = %u\n",*(&a+1));

	}

What I have tried:

I am getting the output on particular memory location only by using double pointer. Why I am unable to get the value using single pointer. I am getting the value on *p but unable to get the same value using *(&a+1).kindly help.

Posted 20-Dec-17 20:11pm

Member 13587774

Updated 20-Dec-17 21:11pm

CPallini

v2

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CPallini · Answer 1 · 2017-12-20T21:07:00

Always compile with the -Wall switch.
As matter of fact GCC warns on

Quote:
p=&a+2;

That shoud be instead

C

p = a + 2;

Try

C

#include <stdio.h>

int main()
{
  int a[3]={1,2,3};
  int *p;
  p=(a+2);
  *p=50;

  int n=0;

  for (n=0; n<3; ++n)
    printf("at address %p value is %d\n", (a+n), *(a+n));

  return 0;
}

Jochen Arndt · Answer 2 · 2017-12-20T21:11:00

Solution 2

The compiler shows

warning: assignment from incompatible pointer type

for the line

C

p=&a+2;

That is because a is an array and therefore already an int* pointer.

So it must be

C

p = a + 2;
// or
p = &a[2];

and similar in the printf calls.

Posted 20-Dec-17 21:11pm

Jochen Arndt