Help convert a tiny line of C# code to VB ?

Question

4.00/5 (1 vote)

See more:

Does anybody can help me to convert this tiny line of C Code to VB ?
this code was from :
Screen Brightness Control for Laptops and Tablets[^]

What I have tried:

Original Code in C:

//Form1_Shown:
if (Array.FindIndex(arguments, item => item.Contains("%") ) > -1)

//startup_brightness:
string sPercent = arguments[Array.FindIndex(arguments, item => item.Contains("%"))];

And these is my attempt to convert to VB:

//Form1_Shown: 
If Array.FindIndex(arguments, (Function(item) item.Contains("%"))) > -1 Then

//startup_brightness:
Dim sPercent As String = arguments(Array.FindIndex(arguments, Function(item) item.Contains("%")))

And my attempt just returning an error :

System.ArgumentNullException: 'Value cannot be null.'

Any help would be Wonderful! :)

Cheers,
Joe

Posted 12-Dec-17 7:53am

InfinityJoe

Updated 13-Dec-17 5:19am

v3

Add a Solution

Comments

F-ES Sitecore 12-Dec-17 14:06pm

The problem is the data\variables you're using, not the code. You need to use the debugger to find out what is evaluating to null.

InfinityJoe 13-Dec-17 11:20am

Hi Mate, thanks for your advice, really appreciate it! :)

Cheers,
Joe

Dave Kreskowiak 12-Dec-17 15:51pm

That's not C, that's C# code. You can use any of the online conversion tools to convert between C# and VB.NET. Just Google for "Convert C# to VB.NET" to find them.

InfinityJoe 13-Dec-17 11:27am

Hi Mate, thanks for your advice, really appreciate it!, and yes forgot to put "#" on the title last time, but actually i've already added C# for this thread tagline at beginning, btw just fix the title today :)

Cheers,
Joe

Richard Deeming 13-Dec-17 10:47am

The code you're starting from is flawed - it should cache the value returned from FindIndex, rather than calling the method twice.

int index = Array.FindIndex(arguments, item => item.Contains("%"));
if (index >= 0)
{
    string sPercent = arguments[index];
    ...
}

The ArgumentNullException would suggest that the arguments array has not been initialized.

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)