I am new with the arrays terminator concept is it posible to get -1 as an array terminator

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i need to add a array terminator but dont have an idea how to swap my loops to it if its a terminator how do i print it in the next available slot to certify is correct?

#include <stdio.h>
#include <stdlib.h>

/* run this program using the console pauser or add your own getch, system("pause") or input loop */

int main(int argc, char *argv[]) {

    int arr[100]; 
    int i;  
    int x;
    printf("how many values would you like to imput :\n");
	scanf("%d", &x); 
	
    for(i=0; i<x; i++)  
    {  
	    printf("values array number %d : ",i);
        scanf("%d", &arr[i]);  
    }  
  
    printf("\n values inside the array arr: ");  
    for(i=0; i<x; i++)  
    {  
        printf("%d  ", arr[i]);  
    } 
    printf("\n");
	
return 0;
}

What I have tried:

i tried creating a rule with if and else but just come up error

Posted 30-Nov-17 12:50pm

Member 13550518

Updated 30-Nov-17 21:52pm

KarstenK

v2

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Patrice T 30-Nov-17 22:42pm

You should ask where you have found that 'array terminator concept'.

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KarstenK · Answer 1 · 2017-11-30T21:22:00

Solution 1

In your code you must check that x is less than 100 like:

C++

for(i=0; (i<x) && (i<100); i++)

Another and better option is:

C++

int *arr = new int[x];//dynamic allocation
//your code
delete arr;//cleanup

Posted 30-Nov-17 21:22pm

KarstenK

Richard MacCutchan · Answer 2 · 2017-11-30T21:37:00

Remember to check the value of x is less than 100 when it is first entered.

C++

for(i=0; i<x; i++)
{
    printf("values array number %d : ",i);
    scanf("%d", &arr[i]);
}
arr[i] = -1; // set end of values marker. NB this only works if no values could be -1

printf("\n values inside the array arr: ");
for(i=0; arr[i] != -1; i++)  // use the marker as the loop terminator
{
    printf("%d  ", arr[i]);
}
printf("\n");

CPallini · Answer 3 · 2017-11-30T21:52:00

Array terminator for an int array, generally speaking, is NOT a good idea, because you use a valid item value (e.g. -1) for a different purpose (hence, in your code you have to be consistent. Moreover, if others use your code, then they must be well aware of such a convention). Anyway

C

#include <stdio.h>

#define SIZE 100

int main(int argc, char *argv[]) {

    int arr[SIZE];
    int i;
    printf("insert values (-1 to finish):\n");

    for (i=0; i<(SIZE-1); ++i)
    {
      printf("values array number %d : ",i);
      scanf("%d", &arr[i]);
      if ( arr[i] == -1) break;
    }

    arr[i] = -1; // the i==(SIZE-1) corner case

    printf("\n values inside the array arr: ");

    for (i=0; arr[i] != -1; ++i)
    {
        printf("%d  ", arr[i]);
    }
    printf("\n");

    return 0;
}
~

I am new with the arrays terminator concept is it posible to get -1 as an array terminator

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