Dynamic create datagridview column name

Question

1.00/5 (1 vote)

See more:

the column name configured in the database.

C# windows form

What I have tried:

DataTable dt = new DataTable();

DataColumn col = new DataColumn();
 col.DataType = typeof(string);
col.Caption = "displayname"  
col.ColumnName = "fieldname";
dt.Columns.Add(col); 

gv.datasource = dt;

the column still shows "fieldname"

Posted 26-Sep-17 22:08pm

855

Updated 26-Sep-17 22:33pm

Add a Solution

Comments

Graeme_Grant 27-Sep-17 4:16am

What is the question?

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Karthik_Mahalingam · Answer 1 · 2017-09-26T22:33:00

try HeaderText [^] property

DataTable dt = new DataTable();
           DataColumn col = new DataColumn();
           col.DataType = typeof(string);
           col.ColumnName = "fieldname";
           dt.Columns.Add(col);
           dt.Rows.Add(1);
           gv.DataSource = dt;
           gv.Columns[0].HeaderText = "displayname";