Convert code C++ to C

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Hello, I want to convert this line to C. This line is basically assigning each element in the array a value. Can anybody help me? Thank you so much

C++

char *arr = new char[10] {'A', 'K', 'U', 'E', 'B', 'Z', 'D', 'O', 'M', 'Q'};

What I have tried:

I wanted to do this but it is not working.

Objective-C

char *arr=(char *)malloc(11*sizeof(char)){'A', 'K', 'U', 'E', 'B', 'Z', 'D', 'O', 'M', 'Q'};

Posted 23-Sep-17 18:12pm

Member 13426140

Updated 23-Sep-17 20:07pm

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OriginalGriff · Answer 1 · 2017-09-23T20:07:00

Solution 1 is correct, and will work: however do remember that that code will generate a local variable: the array of chars will be on the stack, not the heap: it will only exist until you return from the current function, and cannot be returned to the calling function in any way without causing a "hanging reference". If the array is needed outside the current function, you must use malloc and copy that array into the heap based area it returns.

RAMASWAMY EKAMBARAM · Answer 2 · 2017-09-23T19:31:00

Solution 1

C++

char arr[] = {'A', 'K', 'U', 'E', 'B', 'Z', 'D', 'O', 'M', 'Q'};

That is all you need to do.
You can even test the code using sizeof(arr) and you will get 10

Posted 23-Sep-17 19:31pm

RAMASWAMY EKAMBARAM