How to I concatenate a string to a result set

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var query=" SELECT * FROM measurements WHERE project_type=? AND project_id= ? AND subproject=? LIMIT 1";



$cordovaSQLite.execute(db, query, ['SMBH',$scope.proj1,'DRILLING AND COMPLETION OF 5 INCH DIAMETER BOREHOLE BASEMENT']).then(function(result) {

$scope.results=[]; 

if(result.rows.length >0){

for(var i=0; i<result.rows.length; i++){
   //alert("items exists");
sub["add"] = result.rows.item(i).address;
sub["award"] = result.rows.item(i).date_awarded;
sub["rep"] = result.rows.item(i).reporter_id;
sub["contr"]= result.rows.item(i).contractor_id;
for(var m=1; m<=49;m++){
var l="l";
sub["l"+m] = result.rows.item(i).l1;//FETCHES THE RESULT
sub["l"+m] = result.rows.item(i)+l+m;//DOESN'T FETCH THE RESULT

sub["b"+m] = result.rows.item(i).b1;//FETCHES THE RESULT
sub["d"+m] = result.rows.item(i).d+m;//DOESN't FETCH THE RESULT
sub["num"+m] = result.rows.item(i).num1;//FETCHES THE RESULT
sub["cr"+m] = result.rows.item(i).certified_rate1;//FETCHES THE RESULT

What I have tried:

sub["d"+m] = result.rows.item(i).d+m;
sub["d"+m] = result.rows.item(i)."d"+m;
sub["d"+m] = result.rows.item(i).d+[m];
sub["d"+m] = result.rows.item(i)+"."+d+[m];

Posted 6-Aug-17 0:47am

Member 13348179

Updated 6-Aug-17 1:28am

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Kornfeld Eliyahu Peter · Accepted Answer · 2017-08-06T01:28:00

JavaScript

sub["l"+m] = result.rows.item(i).l1;//FETCHES THE RESULT
sub["l"+m] = result.rows.item(i)+l+m;//DOESN'T FETCH THE RESULT

This first line gets the member called 'l1' of the item, while the second gets the item object and try to add to it 'l' and '1', that's really not the same...
You may use here the fact that members in JavaScript can be accessed in two ways...
The . (dot) operator - as you do it in the first line
and [] - as you use with arrays (it works because JavaScript represents object like a hash table, where member name is the key)
So you may write the second line like this:

JavaScript

sub[l + m] = result.rows.item(i)[l + m];