How to spread out the column in SQL

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Hi,

I have a table like this below.

TaskId StatusId StatusName TypeId
1         189       New       1
2         199       New1      2
3         189       New       1
4         199       New1      3
5         190       new2      4
6         190       new2      4

I need output as below

TypeId   New  New1  New2
1         2    0     0
2         0    1     0
3         0    1     0
4         0    0     2

Thanks in advance.

What I have tried:

SQL

CREATE TABLE #TaskTable
(TaskId INT, StatusId INT, StatusName VarChar(50), TypeId INT);
GO
 
INSERT INTO #TaskTable VALUES(1,189,'New',1);
INSERT INTO #TaskTable VALUES(2,199,'New1',2);
INSERT INTO #TaskTable VALUES(3,189,'New',1);
INSERT INTO #TaskTable VALUES(4,199,'New1',3);
INSERT INTO #TaskTable VALUES(5,190,'New2',4);
INSERT INTO #TaskTable VALUES(6,190,'New2',4);

SELECT *
FROM #TaskTable

SELECT *
FROM #TaskTable
  PIVOT(Count(StatusId)  
  FOR StatusName IN([New], [New1],[New2]) 
  ) P;

But result is not as expected.

Posted 31-Jul-17 1:47am

Member 8478234

Updated 3-Aug-17 23:00pm

Kornfeld Eliyahu Peter

v2

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2 solutions

Solution 2

select * from (
SELECT TypeId,
StatusId,
StatusName FROM #TaskTable
)as gg

PIVOT(
Count(StatusId)
FOR StatusName IN(
[New],
[New1],
[New2])
) P;

Posted 3-Aug-17 23:00pm

Santosh kumar Pithani

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Kornfeld Eliyahu Peter · Accepted Answer · 2017-07-31T02:04:00

Solution 1

You have to group the result by typeid...

SQL

WITH PIVOTED
AS (
	SELECT *
	FROM #TASKTABLE
		PIVOT(COUNT(STATUSID)  
			FOR STATUSNAME IN([NEW], [NEW1],[NEW2]) 
		) P
)
SELECT 
	TYPEID,
	SUM(NEW) AS NEW,
	SUM(NEW1) AS NEW1,
	SUM(NEW2) AS NEW2
FROM PIVOTED
GROUP BY TYPEID

Posted 31-Jul-17 2:04am

Kornfeld Eliyahu Peter