How to count P & a in sqlserver

Question

0.00/5 (No votes)

See more:

SQL-Server-2008R2

, +

Please help someone!
I have a table in name of Mark_Attendance which contains columns like

[Class] | [S_Adm_No] |  [Alias], | [DateTime]

To get my result I am using a sql query like

SELECT * FROM(SELECT [Class] ,[S_Adm_No], [Alias],DATENAME(M, [DateTime])as [Month],
DAY([DateTime]) as [DayValue] FROM [Mark_Attendance]) as Composite PIVOT (MAX([Alias]) 
FOR [DayValue] IN ([1], [2], [3], [4],[5], [6], [7], [8], [9],[10], [11], [12], [13], [14],[15], 
[16], [17], [18], [19],[20], [21], [22], [23], [24],[25], [26], [27], [28], [29],[30],[31])) 
AS PivotTable where [Month] = 'May' and Class ='Nur-A'

This query is showing value like

Class | S_Adm_NO | Month | 1 | 2 | 3 | 4 | 5 | 6 | 7 | and so on 
Nur-A | 1101     | April | A | P | P | P | P | A | A | 
Nur-A | 1102     | April | P | P | P | P | P | A | A | 
Nur-A | 1103     | April | A | P | A | P | P | P | P |

My question is how can I count P and A separately like.

Class | S_Adm_NO | Month | 1 | 2 | 3 | 4 | 5 | 6 | 7 | Total_P  | Total_A 
Nur-A | 1101     | April | A | P | P | P | P | A | A |  4       | 3
Nur-A | 1102     | April | P | P | P | P | P | A | A |  5       | 2
Nur-A | 1103     | April | A | P | A | P | P | A | A |  3       | 4

What I have tried:

SQL

SELECT * FROM(
                               SELECT [Class] ,
                                      [S_Adm_No], 
                                      [Alias],
                                      DATENAME(M, [DateTime])as [Month],
                                      DAY([DateTime]) as [DayValue] 
                               FROM [View_SMS_Mark_Attendance]) as Composite PIVOT (MAX([Alias]) 
                               FOR [DayValue] IN ([1], [2], [3], [4],[5], [6], [7],
                                                  [8], [9],[10], [11], [12], [13],
                                                  [14],[15],[16], [17], [18], [19],
                                                  [20], [21], [22], [23], [24],[25],
                                                  [26], [27], [28], [29],[30],[31])
            ) 
AS PivotTable 
where [Month] = 'May' and Class ='Nur-A'

Posted 1-Jul-17 3:43am

nityanand NCR

Updated 2-Jul-17 22:25pm

Ehsan Sajjad

v4

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Maciej Los · Accepted Answer · 2017-07-02T22:25:00

Try to join a table with

SQL

SELECT pt.[Class], pt.[S_Adm_No], pt.[1], pt.[2], ..., pt.[31], at.[SumOfP], at.[SumOfA]
    FROM (
        SELECT [Class], [S_Adm_No], [Alias],DATENAME(M, [DateTime])as [Month], DAY([DateTime]) as [DayValue] 
        FROM [View_SMS_Mark_Attendance]) as Composite
        WHERE [Month] = 'May' and Class ='Nur-A'
        PIVOT (MAX([Alias]) FOR [DayValue] IN ([1], [2], [3], [4],[5], [6], [7],
                                                  [8], [9],[10], [11], [12], [13],
                                                  [14],[15],[16], [17], [18], [19],
                                                  [20], [21], [22], [23], [24],[25],
                                                  [26], [27], [28], [29],[30],[31])
            ) AS pt LEFT JOIN (
       SELECT [Class], [S_Adm_No], SUM(CASE WHEN [Alias] = 'P' THEN 1 ELSE 0 END) AS SumOfP, SUM(CASE WHEN [Alias] = 'A' THEN 1 ELSE 0 END) AS SumOfA
       FROM  [View_SMS_Mark_Attendance] 
       GROUP BY [Class], [S_Adm_No]
           ) AS at ON pt.[Class] = at.[Class] AND pt.[S_Adm_No] = at.[S_Adm_No]

For further details, please see: Visual Representation of SQL Joins[^]