How do I get comparative records from table?

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SQL-Server-2008R2

I want to get the comparative records from table in which I am recording the purchase details of different items. Let say an Item "ABC" which has a unique ID "111" purchased many time for a client now the question is it that how to retrieve the latest and previous record for this item for this specific client in sql query?

Example:
ItemCode Date Amount ClientID
111 01/01/2017 999 ABC
111 10/03/2017 1050 ABC
111 12/04/2017 1020 ABC

how to get

For ClientID=ABC
ItemCode Date Amount LastPurchase LastAmount
111 12/04/2017 1020 10/03/2017 1050

What I have tried:

Different queries but no luck. Tried different forums but did not found any result.

Posted 30-May-17 20:52pm

Member 13232347

Updated 31-May-17 11:35am

OriginalGriff

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Richard Deeming · Answer 1 · 2017-05-31T11:35:00

Something like this should work:

SQL

WITH cteSortedData As
(
    SELECT
        ItemCode,
        Date,
        Amount,
        ClientID,
        ROW_NUMBER() OVER (PARTITION BY ClientID, ItemCode ORDER BY Date DESC) As RN
    FROM
        YourTable
)
SELECT
    ItemCode,
    MAX(CASE RN WHEN 1 THEN Date ELSE Null END) As Date,
    MAX(CASE RN WHEN 1 THEN Amount ELSE Null END) As Amount,
    MAX(CASE RN WHEN 2 THEN Date ELSE Null END) As LastPurchase,
    MAX(CASE RN WHEN 2 THEN Amount ELSE Null END) As LastAmount,
    ClientID
FROM
    cteSortedData
WHERE
    RN In (1, 2)
GROUP BY
    ItemCode,
    ClientID
;