How do I call main function part in other function?

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here is m code where i want to re-call main function in tabletfind(). what can i do for this?

What I have tried:

C++

#include <iostream>
#include <string>
using namespace std;


int tabletfind(int x){
	if(x%2==0)
	{
		cout<<"Searching for a solution within 21 moves..."<<endl;
		cout<<"No solution found within 21 moves. Sorry."<<endl;
		string ans;
	cout<<"Would you like to try again [Y/N]?";
      cin>>ans;
     if(ans=="y" || ans=="Y"){

    //here i need to call main function part again what should i do? i can't understand
      }
	  	else if (ans=="n" || ans=="N"){
		
            exit;}
           }
}

}
	int main() {
	int number;
	
	tryagain:
	cout<<"How many tablets are you starting with ? ";
	cin>>number;
	 
	if(number>0 && number<=10000){
	 tabletfind(number);
    }
        
else   {cout<<"Number of Tablets must be greater than 0 and no more than 10000"<<endl;
	              goto tryagain;}
    	return 0;
}

Posted 19-Apr-17 9:37am

Member 13139035

Updated 19-Apr-17 9:49am

Patrice T

v3

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Patrice T · Answer 1 · 2017-04-19T09:43:00

Solution 1

Quote:
here is m code where i want to re-call main function in tabletfind(). what can i do for this?

A C program never call the main function, no matter what.
You have to organize your another way.

You should think about using a loop, anf avoid the goto.

Posted 19-Apr-17 9:43am

Patrice T

Updated 19-Apr-17 10:30am

v2

CHill60 · Answer 2 · 2017-04-19T09:49:00

Organise your program so that main() calls another function which you can then call again from anywhere else e.g.

C++

#include <iostream>
#include <string>
using namespace std;

int aFunction()
{
	int number;

	tryagain:
	cout<<"How many tablets are you starting with ? ";
	cin>>number;

	if(number>0 && number<=10000)
	{
		tabletfind(number);
	}
	else {cout<<"Number of Tablets must be greater than 0 and no more than 10000"<<endl;
	goto tryagain;
	}
	return 0;
}

int tabletfind(int x)
{
	if(x%2==0)
	{
		cout<<"Searching for a solution within 21 moves..."<<endl;
		cout<<"No solution found within 21 moves. Sorry."<<endl;
		string ans;
		cout<<"Would you like to try again [Y/N]?";
		cin>>ans;
		if(ans=="y" || ans=="Y")
		{

		        x = AFunction()		}
		else if (ans=="n" || ans=="N")
		{
			exit;
		}
	}
 }
 
 int main() 
 {
	int number;
	number = aFunction();
 }

Please note I have not tested any of the above and I may have let a tear fall from my eye as I copied the goto.