How to match the following line with regular expression?

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Input line=REVISION_LOCATION:../setup/projects/DEMO/space

The below code not works for me .It is not considering the ..

How can i do it?

What I have tried:

if ($input_line=/^REVISION_LOCATION:\s*(\S+)/) {
    $input_line = $1;

}

Posted 23-Mar-17 20:04pm

example file

Updated 23-Mar-17 23:45pm

v2

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Jochen Arndt 24-Mar-17 3:45am

Where is the problem?
$1 will be "../setup/projects/DEMO/space" for your example.

example file 24-Mar-17 4:48am

actually ../setup/projects/DEMO/space.Here .. reperesents previous directory.Will the above code will consider .. as previous directory

Jochen Arndt 24-Mar-17 5:16am

It is just a string with a relative path. If you want to access that you had to know the base path. But that is not related to the regex.

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Richard MacCutchan · Answer 1 · 2017-03-23T23:30:00

Solution 1

See RegExr: Learn, Build, & Test RegEx[^].

Posted 23-Mar-17 23:30pm

Richard MacCutchan

Member 10886371 · Answer 2 · 2017-03-23T23:45:00

Solution 2

Regex regex = new Regex(@"REVISION_LOCATION:\s*(\S+)/");
           Match match = regex.Match("REVISION_LOCATION:../setup/projects/DEMO/space");
           if (match.Success)
           {
               Console.WriteLine(match.Value);
           }

Posted 23-Mar-17 23:45pm

Member 10886371