Write the output of the following C++ program?

Question

1.00/5 (3 votes)

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Note: Assume all required header files are already included in the program.

C++

typedef	char TEXT[80];

void JumbleUp(TEXT T)
{
    int L=strlen(T);
    for (int C=0; C<L-1; C+=2)
    {
        char CT=T[C];

        T[C]=T[C+1];
        T[C+1]=CT;
    }

    for (C=1; C<L; C+=2)
        if (T[C]>=’M’ && T[C]<=’U’)
            T[C]=’@’;
}

void main()
{
    TEXT Str="HARMONIOUS";
    JumbleUp(Str);

    cout<<Str<<end1;
}

What I have tried:

I solved the program but the second loop i cannot understand. The answer is -AHM@N@OIS@

Plz mail me on - [EMAIL REMOVED] with the explanation of the second loop.

Thanks in advance

Posted 21-Mar-17 7:46am

Member 13074746

Updated 21-Mar-17 9:07am

Dave Kreskowiak

v4

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Comments

[no name] 21-Mar-17 13:51pm

You would see the explanation yourself if you learned how to use the debugger.

Richard MacCutchan 21-Mar-17 16:25pm

It's fairly clear: for every odd numbered character replace all letters between 'M' and 'U' with '@'.

Member 13074746 22-Mar-17 7:29am

Thank you

2 solutions

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OriginalGriff · Answer 1 · 2017-03-21T08:29:00

Solution 1

We do not do your homework: it is set for a reason. It is there so that you think about what you have been told, and try to understand it. It is also there so that your tutor can identify areas where you are weak, and focus more attention on remedial action.

Try it yourself, you may find it is not as difficult as you think!

If you meet a specific problem, then please ask about that and we will do our best to help. But we aren't going to do it all for you!

Try using the debugger and see if you can follow what is going on...

Posted 21-Mar-17 8:29am

OriginalGriff

Comments

Member 13074746 21-Mar-17 16:16pm

Well first thing is its not my homework. I was just sitting at home feeling boared so i started to search for questions and from those i didnot understand this.

CHill60 21-Mar-17 18:40pm

If it's not your homework then it's best to avoid "homework season" when you are self-learning. You can tell it's homework season by the number of C or C++ questions in QA worded similarly to yours.

Patrice T · Answer 2 · 2017-03-21T09:07:00

Quote:
I solved the program but the second loop i cannot understand. The answer is -AHM@N@OIS@

The debugger will help you ti understand the code.
When you don't understand what your code is doing or why it does what it does, the answer is debugger.
Use the debugger to see what your code is doing. Just set a breakpoint and see your code performing, the debugger allow you to execute lines 1 by 1 and to inspect variables as it execute, it is an incredible learning tool.

Debugger - Wikipedia, the free encyclopedia[^]
Mastering Debugging in Visual Studio 2010 - A Beginner's Guide[^]
Basic Debugging with Visual Studio 2010 - YouTube[^]

The debugger is here to show you what your code is doing and your task is to compare with what it should do.
There is no magic in the debugger, it don't find bugs, it just help you to. When the code don't do what is expected, you are close to a bug.

Quote:
Write the output of the following C++ program?

We do not do your HomeWork.
HomeWork is not set to test your skills at begging other people to do your work, it is set to make you think and to help your teacher to check your understanding of the courses you have taken and also the problems you have at applying them.
Any failure of you will help your teacher spot your weaknesses and set remedial actions.
So, give it a try, reread your lessons and start working. If you are stuck on a specific problem, show your code and explain this exact problem, we might help.

As programmer, your job is to create algorithms that solve specific problems and you can't rely on someone else to eternally do it for you, so there is a time where you will have to learn how to. And the sooner, the better.
When you just ask for the solution, it is like trying to learn to drive a car by having someone else training.
Creating an algorithm is basically finding the maths and make necessary adaptation to fit your actual problem.