I have one XML file and have to convert into class object

Question

0.00/5 (No votes)

See more:

I have to create class of these xml file.

<Type>Label</Type>
          <Name>Label1</Name>
          <Text>label</Text>
          <X>20</X>
          <Y>30</Y>
          <Width>35</Width>
          <Height>13</Height>
          <Visible>True</Visible>
          <Enable>True</Enable>
  </control>

<control>
         <Type>TextBox</Type>
         <Name>textbox1</Name>
         <Text></Text>
         <X>93</X>
         <Y>30</Y>
         <Width>100</Width>
         <Height>20</Height>
         <Visible>True</Visible>
         <Enable>True</Enable>  </control>

What I have tried:

I don't have any singal idea. How to do this. Even I searched on google. Not getting result

Posted 13-Mar-17 23:20pm

Pragya Nagwanshi

Updated 13-Mar-17 23:30pm

v2

Add a Solution

Comments

F-ES Sitecore 14-Mar-17 5:22am

google "deserialize xml to object" and you'll find lots of examples.

CHill60 14-Mar-17 5:23am

What do you mean by "create class of these xml file"? Explain your problem in more detail

Pragya Nagwanshi 14-Mar-17 5:25am

I have to convert this xml into class

d.gierse 14-Mar-17 5:27am

if you want to get an object you have to define a class in C# and then you can use XmlSerializer.Desrialize()

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

CHill60 · Accepted Answer · 2017-03-13T23:30:00

Solution 1

This CP article should help you along: XML Serialization and Deserialization: Part-2[^]

Posted 13-Mar-17 23:30pm

CHill60

Comments

Karthik_Mahalingam 14-Mar-17 5:36am

5

Pragya Nagwanshi 14-Mar-17 7:24am

Thanks. I got it.

CHill60 14-Mar-17 7:34am

:thumbsup: