How do I execute a windows batch file using environment variable in Python?

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Hi,

I am working on a python code and require to open an executable which is located in my C drive. I dont want to code something like, 

    file = open("C:\\Documents\\CodeRepo...\\codeplay.exe)

I want to use the environment variable called LOCATION_HOME to point to this exe location.

I dont know when do i set this environment variable. Do i set it in my python code or using the terminal in Windows?

I am still having some issues. 

The thing is I provide some extra things in the Popen like shown below.

output = subprocess.Popen(('path -testroot C:\\....\Configuration -projectfile ProjectFilewithTags -environment'
), stdout=subprocess.PIPE).stdout

What I have tried:

<pre>
As of now, I did  <pre>path = os.environ["LOCATION_HOME"]
path += "\\binaries\\codeplay.exe" + "-testroot C:\\....\Configuration -projectfile ProjectFilewithTags -environment"

.

I PRINT OUT THE PATH IN PYTHON AND IT LOOKS CORRECT. but when I do the opening of the file in the output = .... the system cannot find the file.

output = subprocess.Popen((path
), stdout=subprocess.PIPE).stdout

Posted 8-Mar-17 5:48am

Member 13046390

Updated 8-Mar-17 6:41am

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Jochen Arndt · Answer 1 · 2017-03-08T06:41:00

I guess this has been already solved within the comments of the previous question.

This might fail when the environment variable HOME_LOCATION has a trailing backslash.

To handle this os.path.join can be used which takes care of the directory separators:

Python

path = os.environ["LOCATION_HOME"]
os.path.join(path, "binaries\\codeplay.exe")
path + " -testroot ..."