C# post file to WEB API

Question

0.00/5 (No votes)

See more:

I use te POSTMAN application to upload a file to an API,
now I want to actually do a POST commando in c#, how can I do this in the most efficient way?

url "192.168.0.1/api/files"

Header
key= Authorization, value = "123456"

Formdata
key= files, value = <file>
key= Info, value = <{"DocName": "Test"}>

if status == 200
Console.WriteLine("OK");
else
Console.WriteLine( "ERROR" + response.StatusCode + " : Message - " + response.ReasonPhrase);

What I have tried:

HttpClient client = new HttpClient();
client.BaseAddress = new Uri("https:///api.ontriz.com/files");
client.DefaultRequestHeaders.TryAddWithoutValidation("Authorization", "123456");

but then??

Posted 18-Jan-17 0:14am

MaikelO1

Updated 18-Jan-17 9:06am

v2

Add a Solution

Comments

F-ES Sitecore 18-Jan-17 6:26am

Google "c# post file web api" and I'm sure you'll find the code

MaikelO1 18-Jan-17 8:11am

thanks for your comment. not tried that but unfortunately with an error result

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Richard Deeming · Answer 1 · 2017-01-18T09:06:00

Use the MultipartFormDataContent class[^]:

C#

using (var form = new MultipartFormDataContent())
using (var stream = File.OpenRead(@"Path\To\Your\File.ext"))
using (var streamContent = new StreamContent(stream))
{
    form.Add(streamContent, "files");
    form.Add(new StringContent("<{\"DocName\": \"Test\"}>"), "Info");
    response = await client.PostAsync(null, form);
}