How do I creat a print function for structure?

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I try to make a print function for structure but meet a errow I have not seem before
this is my cod:

C++

   #include<stdio.h>
   struct point{
	int x;
	int y;
   }p;
   
    int main()
   {
        struct point scan(struct point *p);
	void print(struct point *p);
	
		
	scan(&p);
	print(&p);
	
	 
	
	return 0;
}
     struct point scan(struct point *p)
{
	scanf("%d%d",p->x,p->y); 
}

      void print(struct point *p)
{
	printf("%d%d",p->x,p->y);
}

What I have tried:

I have searched google but nothing found nothing.
By the way,if you think my question is stupid,please recommend some book for me, I will appreciate that.

Posted 5-Nov-16 19:07pm

ANCIFresh

Updated 5-Nov-16 21:44pm

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Michael_Davies 6-Nov-16 1:55am

Which line gives the error and what does the error message say?

Definitions should be outside functions so

struct point scan(struct point *p);
void print(struct point *p);

Should not be inside Main.

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OriginalGriff · Answer 1 · 2016-11-05T21:41:00

You cannot declare function prototypes inside the body of a function. Move these lines above the definition of main:

C++

struct point scan(struct point *p);
	void print(struct point *p);

And do yourself a favour, and don't use single character names: use "proper" names and your code becomes a lot easier to read.

C++

#include<stdio.h>
struct point
   {
   int x;
   int y;
   } myPoint;

struct point scan(struct point *p);
void print(struct point *p);
   
int main()
   {
   scan(&myPoint);
   print(&myPoint);
   return 0;
   }
   
struct point scan(struct point *p)
   {
   scanf("%d%d",p->x,p->y); 
   }
void print(struct point *p)
   {
   printf("%d%d",p->x,p->y);
   }