How to calculate Circle Vertical Line intersect

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I have following formulas to find intersect points of Line and Circle

x = {-B + sqrt[((B^2) - 4AC)]} / 2A

where B = 2mc
A = 1 + m^2
C = c^2 - r^2

m means slop
c means Constant of line formula

after finding x I find value of y by putting x in (y = mx + c)
but what we have to do when slop is infinite (means vertical line)
?

Posted 4-Oct-10 0:31am

Khaniya

Updated 4-Oct-10 0:34am

v2

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CPallini · Accepted Answer · 2010-10-04T01:33:00

Solution 1

A vertical line as equation

x = K

where K is a const.
Hence, you've to solve the original equation for y, namely:

(K-a)^2 + (y-b)^2 = r^2

That is, again, just a quadratic equation.
:)

Posted 4-Oct-10 1:33am

CPallini

v2