How to aggregate rows in SQL database based on date - fortnightly basis

declare @startdate datetime
set @startdate = '2016-10-17 00:00:00.000' --starting point date

declare @result table 
(
	fromdate datetime,
	todate datetime,
	totalhours decimal(18, 2)
)

while @startdate <= '2020-12-31 00:00:00.000'
begin
        --insert a row for the current fortnight
    	insert into @result
		select		@startdate, dateadd(D, 13, @startdate), sum(wh.Hours)
		from		dbo.UserWorkingHours wh
		where		wh.WorkingDate between @startdate and dateadd(D, 13, @startdate)
		and			wh.UserID = 1209
	
        --set the start date as the next fortnight
	set @startdate = dateadd(D, 14, @startdate)
		
end

--declare the final result table
declare @fresult table 
(
	fromdate datetime,
	todate datetime,
	totalhours decimal(18, 2),
	id int
)

--declare a variable to set ID in the final result table rows which are having the same fortnightly hours as the previous one
declare @id int
set @id = 1

--declare cursor and related variables
declare @fd datetime
declare @td datetime
declare @th decimal(18, 2)

declare rc cursor for
select r.fromdate, r.todate, r.totalhours from @result r order by r.fromdate

open rc
fetch next from rc into @fd, @td, @th
while @@FETCH_STATUS <> -1
begin
	
        --if there are no rows in the final result table then insert the first from from the previous result table 
        --it will be the starting row because the cursor is ordered by from date ascending
	if not exists (select 1 from @fresult)
	begin

		insert into @fresult
			select @fd, @td, @th, @id
	end
	else
	begin
		--there are rows in the final result table 
                --so fetch the last row total hours and compare it with the current row total hours in the cursor
		if (select top 1 totalhours from @fresult order by fromdate desc) <> @th
		begin
                        --the hours comparison failed i.e. current fortnightly hours are different than the previous fortnight
                        --increase the ID and insert the row in the final table
			set @id = @id + 1
			insert into @fresult
				select @fd, @td, @th, @id
		end
		else
		begin
                        --current fortnightly hours are same as the previous fortnightly hours 
                        --insert the row in the final result table with the previous ID
			insert into @fresult
				select @fd, @td, @th, @id
		end

	end
	fetch next from rc into @fd, @td, @th
end
close rc
deallocate rc

--select * from @fresult

--select the distinct result along with MIN 'from date' and MAX 'to date' and the hours
select			distinct
				(select min(fromdate) from @fresult where id = fr.id) as FROMDATE,
				(select max(todate) from @fresult where id = fr.id) as TODATE, 
				fr.totalhours
from			@fresult fr

FROMDATE	TODATE	HOURS_PER_FORTNIGHT
2016-10-17 00:00:00.000	2016-10-30 00:00:00.000	6.00
2016-10-31 00:00:00.000	2016-12-11 00:00:00.000	75.00
2016-12-12 00:00:00.000	2016-12-25 00:00:00.000	10.00
2016-12-26 00:00:00.000	2020-12-20 00:00:00.000	75.00
2020-12-21 00:00:00.000	2021-01-03 00:00:00.000	67.50