Java thread synchronization

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i want to display my first name and last name using 2 threads. Once user click ctrl with some key programe should be terminate. Please advice me to begin this. here is my code and it is display only one tome. but i want to display this into until user press some key.

Java

 class Thread_Ex11{
public static void main(String[] args) {
        Thread t1 = new Thread(new MyRunnable(), "gayan");
        Thread t2 = new Thread(new MyRunnable(), "suranga");
        t1.start();
        try {
            t1.join(2000);
            t2.join(2000); 
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
          
            t2.start();
            t1.start();  

        try {
            t1.join();
            t2.join();
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
      
        }

}

class MyRunnable implements Runnable{

    @Override
    public void run() {
       while(true){
        System.out.println(Thread.currentThread().getName());
             
       }  
  }
    
}

What I have tried:

my out put of this programme compiling
this is one
this is two

but i want out put is
this is one
this is two
this is one
this is two
etc....
terminated

Posted 29-Sep-16 20:31pm

nuke_infer

Updated 29-Sep-16 23:25pm

v4

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2 solutions

Solution 1

You need to add loops into your two threads so they keep printing the same text over and over. You may also need to add some form of delay so they do not run away with the system. And in your main method after starting the threads it needs to wait for a keypress or console input. At that point it should terminate the two threads.

Posted 29-Sep-16 22:34pm

Richard MacCutchan

Comments

nuke_infer 30-Sep-16 4:41am

yes i insert the while loop to execute the result. here the code that i inserted while loop
class Thread_Ex11{
public static void main(String[] args) {
Thread t1 = new Thread(new MyRunnable(), "one");
Thread t2 = new Thread(new MyRunnable(), "two");
t1.start();
try {
t1.join(2000);
t2.join(2000);
} catch (InterruptedException e) {
e.printStackTrace();
}
t2.start();
t1.start();
try {
t1.join();
t2.join();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
class MyRunnable implements Runnable{
@Override
public void run() {
while(true){
System.out.println(Thread.currentThread().getName());
}
}
}
out put is showing
one,one, one,one,one,two,two,two,one,two,etc...

but i want answer is
one,two,one,two,one,two,etc...

Richard MacCutchan 30-Sep-16 4:48am

Sorry I do not understand the question. Threads run independently so the order of any output from them will be random.

When adding details about your code please edit your question and add it there.

nuke_infer 30-Sep-16 5:09am

please check it now. i have edited the above code.actual result and expected result of my code.

Richard MacCutchan 30-Sep-16 5:25am

See my new solution below

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Richard MacCutchan · Accepted Answer · 2016-09-29T23:25:00

Try this, it works for me.

Java

public class Thread_Ex {
    public static void main(String [] args) {
        Thread t1 = new Thread(new MyRunnable(), "gayan");
        Thread t2 = new Thread(new MyRunnable(), "suranga");
        
        t1.start();
        t2.start();
        while (true) {
            try {
                System.in.read();
                t1.interrupt();
                t2.interrupt();
            }
            catch (Exception eee) {
                //
            }
        }
    }
}

class MyRunnable implements Runnable {
    @Override
    public void run() {
        while(true) {
            System.out.println(Thread.currentThread().getName());
            try {
                Thread.sleep(200);
            }
            catch (InterruptedException zz) {
                //
            }
            
            if (Thread.interrupted()) {
                System.out.println("interrupted");
                break;
            }
        } 
    }
}