How do I filter pass an argument to substring() that will filter out a character?

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Example of Column I'm trying to modify:

|   Column 1                                                                        |
 asdf sixsix =IWantToReturnThisIn1Column; asdfasd seven12=IWantToReturnThisInColumn2

I want to capture the contents between = and ; for col1a and capture everything to the right of the second = in col 2.

Rookie question, I'm sure but it's stumping me.

My desired out put would look as follows:

| Col1                      | Col2                       |
 IWantToReturnThisIn1Column | IWantToReturnThisInColumn2 |

What I have tried:

SELECT
col1 = substring(d.column1,13,20)

Posted 30-Aug-16 11:59am

Member 11820531

Updated 31-Aug-16 3:07am

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Comments

Richard Deeming 31-Aug-16 10:53am

This is why you don't try to store multiple values in a single column. :)

Member 11820531 31-Aug-16 14:48pm

Agreed, but not quite the answer I need :)

2 solutions

Solution 2

I guess the text length is variable, so you need to build a little complicated formula.
I let you deal with details like declaring the intermediate variables or combining all this in large formulas without formulas.

SQL

SC= INSTR(d.column1, ";") -- position of ';'
EQ1= INSTR(d.column1, "=") -- position of first '='
Col1= SUBSTRING(d.column1, EQ1+1, SQ-EQ1-1)
EQ2= INSTR(d.column1, "=", SC) -- position of second '='
Col2= SUBSTRING(d.column1, EQ2+1)

Good tuto site:
SQL Tutorial[^]

Posted 31-Aug-16 3:07am

Patrice T

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Member 11114915 - Tanvi · Accepted Answer · 2016-08-30T19:46:00

C#

SELECT
  SUBSTRING(col1, 14, 26) AS Col1,
  SUBSTRING(col2, 17, 26) AS Col2
FROM col

This query will bring the desired result.

Query Result:

Col1	                  Col2
IWantToReturnThisIn1Column	IWantToReturnThisInColumn2

Above can also be achieved by using CHARINDEX in case straing between "=" and ";" is required for different rows.

C#

SELECT
  SUBSTRING(Col1, (CHARINDEX('=', col1, 1) + 1), (CHARINDEX(';', col1) - (CHARINDEX('=', col1, 1) + 1))),
  SUBSTRING(Col2, (CHARINDEX('=', col2, 1) + 1), (LEN(col2) - (CHARINDEX('=', col2, 1))))
FROM col

I hope this will fulfill the requirement.