How to get a unique number in SQL as in the mentioned format?

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I want to get a unique number in sql.
Format is as below:
DDMMYYXXXX
where DDMMYY (Current Date in DDMMYY Format) and
XXXX a 4 digit recurring number

What I have tried:

select @test=REPLACE(CONVERT(CHAR(10), GETDATE() , 103), '/', '')

Posted 23-Aug-16 4:57am

Ema112

Updated 23-Aug-16 8:58am

v2

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Maciej Los · Answer 1 · 2016-08-23T08:58:00

Check this: sql server - How to autoincrement a varchar - Stack Overflow[^]

[EDIT]
A table definition should look like (replace YourTableName with the name you want to use):

SQL

CREATE TABLE YourTableName
(
    ID INT IDENTITY(1,1),
    CurrDate DATE,
    CID INT,
    VCID VARCHAR(10)
)

Let's insert sample data:

SQL

--insert sample data
INSERT INTO YourTableName(CurrDate, CID, VCID)
VALUES('2016-08-23', 5, '2308160005'),
('2016-08-23', 6, '2308160006'),
('2016-08-23', 7, '2308160007')

Then you have to create stored procedure[^]

SQL

CREATE STORED PROCEDURE cspInsertMyData
AS
BEGIN
    --declare variables
    DECLARE @d DATE = GETDATE()
    --max of CID
    DECLARE @nextcid INT = 0
    --initiate variable
    SELECT @nextcid = COALESCE(MAX(CID), 0) + 1 FROM YourTableName

    INSERT INTO YourTableName (CurrDate, CID, VCID)
    VALUES(@d, @nextcid, FORMAT(@d, 'ddMMyy') + RIGHT('0000' + CONVERT(VARCHAR(4), @nextcid), 4))

END;

A result:

C#

ID	CurrDate	CID	VCID
1	2016-08-23	5	2308160005
2	2016-08-23	6	2308160006
3	2016-08-23	7	2308160007
4	2016-08-23	8	2308160008

[/EDIT]