How do I call a function defined with in a another function expression in js?

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could not call a function that is defined in another

What I have tried:

var func1 = (function() {
function func2() {
console.log("wrkng");
};
})();
how can i call func2()???
func1.func2(); gives error saying func1 is undefined..

Posted 22-Aug-16 10:02am

moyna coder

Updated 22-Aug-16 19:02pm

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Karthik_Mahalingam · Answer 1 · 2016-08-22T19:02:00

Solution 2

You Cannot! since it is a private function, use Module pattern[^] to expose it outside as

JavaScript

var func1 = (function () {
           func2 =  function() {
                console.log("wrkng");
           };
           return {func2:func2}

        })();

JavaScript

func1.func2()

Posted 22-Aug-16 19:02pm

Karthik_Mahalingam

v2

Dave Kreskowiak · Answer 2 · 2016-08-22T17:09:00

Solution 1

AFAIK, you can't. The visibility scope of the inner function is limited to the function it is defined in.

Posted 22-Aug-16 17:09pm

Dave Kreskowiak