Why this is different?

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3.00/5 (1 vote)

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C#

string text = "aaaaaa";
float width1 = e.Graphics.MeasureString(
    text,
    new Font("calibri", 12, GraphicsUnit.Pixel)).Width;

float width2 = 0;
for (int i = 0; i < text.Length; i++)
{
    width2 += e.Graphics.MeasureString(
        text[i].ToString(),
        new Font("calibri", 12, GraphicsUnit.Pixel)).Width;
}

i want to measure size of Chracter.
why width2 and width1 is not exactly same?
and how can i measure Character rightway?

What I have tried:

this is my best idea... i guess.

Posted 21-Aug-16 0:42am

brockeu

Updated 21-Aug-16 2:22am

Konstantin A. Magg

v2

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Comments

Ralf Meier 21-Aug-16 6:51am

You are not meassuring the width of each character inside the string - for that you should use the sub-method .SubString from your string-variable ...

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OriginalGriff · Accepted Answer · 2016-08-21T01:11:00

Because the width of a string is not the sum of the widths of all teh characters, except in non-proportional (or fixed width) fonts.
In a fixed width font all characters are the same width, so the string is the width of a character times the number of characters:
WIIIIILL
12222234
But in a proportional font:
WIIIIILL
12222234
The characters aren't the same width.
That doesn't cause your problem, but it starts to indicate why it's a problem - becuase proportional fonts can have other features, such as pair-kerning:
WAWAWA
121212
WAWAWA
121212
What happens here is that the W and the A are "tucked together" because part of the A "fits" under the W instead of waiting for it to finish and a small gap added:
WAWANAWA
(there are other effects as well, but that is the easiest to show)
So you can't just measure each character and assume the string will be the same length!

[edit]line breaks added for readbility[/edit]