Code fails to link with report

Question

0.00/5 (No votes)

See more:

My code fails to link to my report. I need to pass the parameter "T-ID" to the report but for some reason I cant get any data when I click the button.

In Crystal Reports I can get data after inputting the parameter, but it fails to generate when run from my program. How can I fix this?

ASP.NET

<asp:TextBox ID="TextBox1" runat="server"></asp:TextBox>
<asp:Button ID="Button1" runat="server" Text="Button" OnClick="Button1_Click" />
<CR:CrystalReportViewer ID="CrystalReportViewer1"  runat="server" AutoDataBind="true" />

C#

protected void Button1_Click(object sender, EventArgs e)
{
    ReportDocument test = new ReportDocument();
    test.Load(Server.MapPath("On Job Training 1.rpt"));
    test.SetParameterValue("T-ID", TextBox1.Text);
    CrystalReportViewer1.ReportSource = test;
    CrystalReportViewer1.DataBind();
    CrystalReportViewer1.ReportSource = test;
}

What I have tried:

My code fails to link to my report. I need to pass the parameter "T-ID" to the report but for some reason I can't get any data when I click the button.

In Crystal Reports I can get data after inputting the parameter, but it fails to generate when run from my program. How can I fix this?

Posted 11-Aug-16 14:37pm

KyLim0211

Updated 11-Aug-16 15:17pm

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

an0ther1 · Answer 1 · 2016-08-11T15:17:00

I would suggest that the report is not using appropriate credentials to connect to the DB.
This needs to be set and passed to the report else it will run via the current context which is dependent on the account the Application Pool is running under.
The below code creates a Crystal ConnectionInfo & applies it to the Report

C#

CrystalDecisions.Shared.ConnectionInfo connCrystal = new CrystalDecisions.Shared.ConnectionInfo();
connCrystal.ServerName = "MyServername";
connCrystal.DatabaseName = "MyDbName";
connCrystal.IntegratedSecurity = false;
connCrystal.UserID = "MyUserName";
connCrystal.Password = "MyPassword";

ReportDocument rptDoc = new ReportDocument();
rptDoc.Load(Server.MapPath("Path.rpt")):
CrystalDecisions.CrystalReports.Engine.Tables tblsReport = rptDoc.Database.Tables;
for(int i = 0; i < tblsReport.Count; i++)
{
    CrystalDecisions.CrystalReports.Engine.Table tblRpt = tblsRpt[i];
    TableLogOnInfo infoTable = tblRpt.LogOnInfo;
    infoTable.ConnectionInfo = connCrystal;
    tblRpt.ApplyLogOnInfo(infoTable);
}
// if you have sub reports you need to loop through them and apply the same log on info
if(rptDoc.SubReports.Count > 0)
{
    for(int i = 0; i < rptDoc.SubReports.Count; i++)
    {
        ReportDocument subReport = rptDoc.OpenSubReport(rptDoc.Subreports[i].Name);
        CrystalDecisions.CrystalReports.Engine.Tables tblsSubReport = subReport.Database.Tables;
        for(int ii = 0; ii < tblsSubReport.Count; ii++)
        {
            CrystalDecisions.CrystalReports.Engine.Table tblSubRpt = tblsSubReport[ii];
            TableLogOnInfo infoSubTable = tblsSubReport.LogOnInfo;
            infoSubTable.ConnectionInfo = connCrystal;
            tblsSubReport.ApplyLogOnInfo(infoSubTable);
        }
}

Kind Regards