Reading dat file and display it on textbox

Question

1.00/5 (1 vote)

See more:

Hi there, i have a problem to display my data in textbox, i use this code

C#

StreamReader file = new StreamReader(@"\Folder\y.dat");

         string line;

         while ((line = file.ReadLine()) != null)
         {
             if (line.Contains("ok"))
             {

             }
             else
             {
                 MessageBox.Show("ok not found);
                 goto z;
             }
             textBox1.Text = line;
         }

this code work good if i created a .txt file. but with .dat ot if i change the .dat to .txt i see nothing in my textbox.
i use compact framwork visual studio 2008 smartdevice application.
please could you tell me how we display data of .dat file in a textbox
thanks

Posted 13-Jun-16 2:47am

Jammes_Ca

Updated 13-Jun-16 4:17am

v2

Add a Solution

Comments

CHill60 13-Jun-16 8:51am

What are the contents of the file?
If there is more than one line you are just going to overwrite the textbox text on each loop. And if each line does not contain "ok" you are going to not display anything
Why on earth do you have a goto (and where is the target code for it?)

phil.o 13-Jun-16 9:00am

A .dat file usually contains binary data, i.e. data that is not directly usable and displayable in a text control.
Without knowing the format of your .dat file; it will be hard to help.
Moreover, what if you started a debug session and see what is going on?

Jammes_Ca 13-Jun-16 9:00am

hi, the textbox is in multiline, in compcat framwork richtextbox does'nt exist.
i said if the file is in .txt i read all teh data, but if the file is in .dat , i can't read all the data

CHill60 13-Jun-16 9:33am

It doesn't matter if the textbox is multi-line - you are overwriting the entire text on each loop.
If the .dat file is binary then how can ReadLine work? And it is highly unlikely that the check if(line.Contains("ok")) would ever pass.
Without a sample of the data I can't help further

Jammes_Ca 13-Jun-16 9:59am

i understand now, the data is a char, so how do i to show all those data in my textbox in assci format and searching for ok,

2 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Dave Kreskowiak · Answer 1 · 2016-06-13T04:15:00

Changing the file extension doesn't do anything to the file content at all. If you change the file extension and suddenly your code can't open the file, did you make the mistake of hard coding the filename in your code and not change the extension in the code?

It sounds like you're trying to read a file and display it like in a hex editor? If so, you cannot use a StreamReader. It treats all files as text files and that's just not the case for all files. "ReadLine" will not work with anything other than a text file. You have to use a FileStream instead. That treats all files the same and you can use the Read methods to get the byte data.

Richard MacCutchan · Answer 2 · 2016-06-13T04:17:00

Solution 2

Firstly you need to know what the .dat file contains, and how that data is structured. You cannot just assume it contains lines of text unless you have verified it. Secondly, if it contains more than one line then you need to concatenate all the text together using a StringBuilder or similar construct. When you have read all the text then you can display it in your text box. Of course, if the contents of the file are not simple lines of text then you need to use some transform process first, in order to make it readable.

Posted 13-Jun-16 4:17am

Richard MacCutchan

Comments

Jammes_Ca 13-Jun-16 10:28am

my .dat file contain chars.
here is a screen shot of my file http://postimg.org/image/qj21i7tef/

Richard MacCutchan 13-Jun-16 10:36am

Then you need to find out how all that data is structured and what it is supposed to mean. And the only people who can give you that information are the ones who created the file.

Jammes_Ca 13-Jun-16 10:40am

i have an information, befero every number "2129" hase owne data so each number have the same number of data and the data equale 52 byte. me i want juste to display all those data in my textbox. after i i look for a number i have to grab all those 52 bytes

Richard MacCutchan 13-Jun-16 10:45am

Then you need to read each 52-byte block, extract the number and add it to your display. See https://msdn.microsoft.com/en-us/library/system.io.binaryreader.readbytes(v=vs.110).aspx.

Jammes_Ca 13-Jun-16 10:49am

first of all, how do i look if a number exist ???, for example the number 2036
please help

Richard MacCutchan 13-Jun-16 11:24am

Read each block of 52 bytes.
Extract the bytes in the position where the number is.
Convert those ASCII bytes to a string.
Process the resulting string as required.

Jammes_Ca 13-Jun-16 11:31am

i want to point the index of the beging of a number, but i don't how do this with binary. and after a grabe all the 52 byte

Richard MacCutchan 13-Jun-16 11:38am

Do you not know how to index a byte array?

Jammes_Ca 13-Jun-16 13:05pm

i did this code, i can get the position of my numbere, but it took very very long time
int index=0;
FileStream fs = new FileStream(@"\Folder\data.DAT", FileMode.Open);
BinaryReader br = new BinaryReader(fs);
textBox1.Text += br.ReadSByte();

for (int y = 0; y < 70000; y++)
{
textBox1.Text += br.ReadSByte();
index = textBox1.Text.IndexOf("50555056"); //2728
if (index != -1)
goto a;

}
a: ;
MessageBox.Show("The position =" +index.ToString());

is there a way to search fast ?

Richard MacCutchan 13-Jun-16 13:33pm

I cannot see how that is anywhere near what you need. I showed you the pseudo code in ma previous reply, why not use that? Firstly do not read the entire file into the textbox. Read 52 bytes into a byte[]. Find the number from the offset into the array, since it is at the same position in each blcok. Convert thos few bytes to a string,

Jammes_Ca 14-Jun-16 4:41am

yes this is what i want to do, but i don't know how to program it , plese could you help ?

Richard MacCutchan 14-Jun-16 9:13am

How many times do you need me to post the same answer? I have explained what you need to do to read each 52 byte block and extract the number from it. What more help are you expecting?

Jammes_Ca 14-Jun-16 9:18am

I agree with your idea, but it took verry long time. imagine if the number that i search locatid in byte number 60000 !!!!!
so you will take hours to finde this number. this is why i pose if there i way to search faster. i did this

using (BinaryReader br = new BinaryReader(File.Open(@"\FOLDER\data.DAT", FileMode.Open)))
{

byte[] v = br.ReadBytes(length);</pre>
..
..
}
but now i want how to search faster for a specific number that is stored in this array ??
please help :(

Richard MacCutchan 14-Jun-16 9:21am

You did not mention that you are searching for a particular number. However, it makes very little difference, you will still need to read each block and check when you have found the required number. If that takes a long time then there is not much you can do to change it.