How to intercept ajax call in PHP

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I have been having this trouble for several days and at my wits end now, I am frustrated! I tried making an ajax call to a script using jQuery's post method but it posts nothing and does not touch the script. I had $.post('server_script.php', $("form").serialize()); and after trying repeatedly, it neither touches/runs the script nor returns any errors. Any functions placed in the done method often run still the php script shows it was not touched.

What I have tried:

Now I switched to .ajax:

JavaScript

$('form').on("submit", function(){
				$.ajax({
				type: "POST",
				url: "test.php",
				data: $("form").serialize()
				});
	});

test.php

PHP

$name = $_POST["name"];
$email = $_POST["email"];
$rand = mt_rand();

echo $name . "\n" . $email . "\n" . $rand;
var_dump($_POST);

The above outputs the `rand` alone and my error log shows undefined index for the rest when I run the script on its own.
I also tried passing the data manually as an object {email: "vainglory7@gmail.com"}, didn't work. Tried parsing it as json, didn't work. Please someone help me as I am desperate. I have tried asking friends but no one seems forthcoming and I've been at this for days now

Posted 17-Apr-16 22:33pm

nmeri17

Updated 18-Apr-16 1:52am

v3

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Comments

Mohibur Rashid 18-Apr-16 4:56am

try print_r($_POST) and see whats happen
$("form").serialize()<- seems incorrect
Your form should have a name or id better try to give your form an id. Say "brandnewform"
now write that code
$("#brandnewform").serialize()

also try this:
if(isset($_POST["name"])==true){
$name=$_POST["name"];
}
else {
log("Name value is missing from POST"); // make a function to write everything in log file
exit;
}

nmeri17 18-Apr-16 6:45am

I tried both var_dump and print_r but they all returned empty arrays. Your code did nothing too which means the variables are not picked from the ajax methods.
By the way, the form serializes. When I do

.done(function() {
console.log($("form-div form").serialize());
});

It logs a key/value pair string but the php code remains stagnant i.e. it does not grab the variables thrown by either .post or .ajax

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W∴ Balboos, *GHB* · Answer 1 · 2016-04-18T01:52:00

First, I always use $_REQUEST for retrieving values from a form. It works in place of both $_POST and $_GET.

Secondly, just for the sake of argument, try to build an ajax posting without the jQuery (I use 'raw' php/javaScript). Here's a link to what should give you a working example. Get that to work and then modify it to your needs (this should also point out where you went wrong).

AJAX Tutorial[^]