Send soap request and capture the response

Question

1.00/5 (1 vote)

See more:

Hi there,
Iam trying to build WPF program to create Soap requests as xml files according to the WSDL which is added as service reference, the problem is that i could not configure the proxy class to use that xml file and send it as a request as well as receiving the response .it gives me an exception :
An unhandled exception of type 'System.ServiceModel.FaultException`1' occurred in mscorlib.dll Additional information: APPLICATION ERROR

public string returnSerializedxml(object input)
{
XmlSerializer xmlSerializer = new XmlSerializer(input.GetType());

using (StringWriter textWriter = new StringWriter())
{
xmlSerializer.Serialize(textWriter, input);
return textWriter.ToString();
}
}

private void button1_Click(object sender, RoutedEventArgs e)
{
ConsignmentEndpointClient proxy = new ConsignmentEndpointClient();
save sv = new save();
saveResponse response = new saveResponse();
XmlDocument doc = new XmlDocument();
doc.Load(PATH);
response= proxy.save(sv); /*Here occur the exception*/

try
{
Output.Text = "Response : \n" + returnSerializedxml(response);
}
catch (Exception error)
{
Output.Text = "Error in Request : \n" + error;
}

What I have tried:

Iam not sure but something is missing like FileStream or similar, I would be thankful for any hint .

Posted 7-Apr-16 2:26am

Member 12442825

Updated 11-Oct-16 2:04am

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

dabuskol · Answer 1 · 2016-10-11T02:04:00

Try below code, If I understand your query correctly.
pass your xml to Soapcommand

C#

private string ProcessRequest(string SoapCommand)
   {
       string soapResult = string.Empty;
       try
       {
           WebRequest webRequest = CreateWebRequest();
           XmlDocument soapEnvelopeXml = new XmlDocument();
           soapEnvelopeXml.LoadXml(SoapCommand);


           using (Stream stream = webRequest.GetRequestStream())
           {
               soapEnvelopeXml.Save(stream);
           }

           using (WebResponse response = webRequest.GetResponse())
           {
               using (StreamReader rd = new StreamReader(response.GetResponseStream()))
               {
                   soapResult = rd.ReadToEnd();
               }
           }
       }
       catch (Exception)
       {
           throw;
       }
       return soapResult;
   }

   public static HttpWebRequest CreateWebRequest()
   {
       HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create(@"http://111.11.31.116:45259/ilws/LinkSOAP");
       webRequest.Headers.Add(@"SOAP:Action");
       webRequest.ContentType = "text/xml;charset=\"utf-8\"";
       webRequest.Accept = "text/xml";
       webRequest.Method = "POST";
       return webRequest;
   }