Launching jar file from different directory

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Hi all,

I'm after some fairly trivial information. I've put in some good effort to Google as much as possible but I don't seem to be getting anywhere.

Essentially, I have a system which requires launching a JAR file from a different directory than the current working directory. Under Windows, from command prompt, this is the command line I'm attempting to get working:

C:\a\b\c>java -Djava.library.path=. -jar C:\x\y\z\name.jar

However this does not retain the current working directory. Instead, the working directory is changed to "C:\x\y\z". This is behaviour which I don't want to happen, I need the current working directory to remain the directory where the command was called from.

The few results I have come across have specified that this should be the case. Java should retain the working directory of the parent process (in this case, the command prompt) however I'm finding this doesn't work.

Do I need to do anything in particular to retain the current working directory?

Thanks

What I have tried:

Googled answers for retaining working directory.
Attempted many different combinations of the Java command line with different parameters.

Posted 21-Feb-16 23:21pm

Chris Copeland

Updated 22-Feb-16 0:42am

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Richard MacCutchan 22-Feb-16 5:56am

How do you determine that the cwd has been changed?

Mohibur Rashid 22-Feb-16 6:15am

have try cp or classpath?
java -cp C:/x/y/z/class1.jar;c:/some_directory/

above example C:/x/y/z/class1jar. absolute path
c:/some_directory/ all class

Chris Copeland 22-Feb-16 6:44am

Thanks for the input, I managed to resolve this using the classpath parameter and manually specifying the JAR path and lib directory.

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Chris Copeland · Accepted Answer · 2016-02-22T00:42:00

Solution 1

I managed to get this working by using the class-path command line in place of the -jar argument. In order to get this working I used:

C:\a\b\c>java -cp "C:\x\y\z.name.jar";lib\* path.to.main.Class

Thanks to Mohibur Rashid for providing the direction!

Posted 22-Feb-16 0:42am

Chris Copeland

Comments

Richard MacCutchan 22-Feb-16 8:17am

Which is a solution to a different question.