How to Split multiple letters in c#

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Hi, there

In one of my interview; interviewer asked to write a program for following

Q :

There is a TextBox which having this predefined value as "Val1!@#$%Val2!@#$%Val3!@#$Val4!@#$%" in it.

On a button click they want to reverse this text in a label as follow.

Output : Val4!@#$%Val3!@#$%Val2!@#$%Val1!@#$%

How to do this?

N.B. Text don't having any space. They all are joined. So split function not working for this

ASP.NET

<asp:TextBox ID="txt1" Text="Val1!@#$%Val2!@#$%Val3!@#$%Val4" runat="server" 
            Width="280px">Val1!@#$%Val2!@#$%Val3!@#$%Val4</asp:TextBox>
        </br>
        <asp:Button ID="btnResult" Text="GetResult" runat="server" 
            onclick="btnResult_Click" />
        </br>
        <asp:Label ID="result" runat="server"></asp:Label>

Posted 26-Dec-15 18:07pm

Nilesh Dalvi

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PIEBALDconsult 27-Dec-15 0:50am

Regular Expressions.

[no name] 27-Dec-15 1:05am

Input : Val1!@#$%Val2!@#$%Val3!@#$Val4!@#$%
Output : Val4!@#$%Val3!@#$%Val2!@#$%Val1!@#$%

In above input and output string "%" is missing in input. Make sure that you are providing correct one.

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BillWoodruff · Accepted Answer · 2015-12-26T19:20:00

You can "split" a string into a string[] using any arbitrary string(s) as the criterion:

C#

string[] spliton = new string[]{"!@#$%"};
string test = @"Val1!@#$%Val2!@#$%Val3!@#$%Val4";

// in some method or EventHandler
// requires Linq
IEnumerable<string> splitAry = this.test.Split(spliton, StringSplitOptions.RemoveEmptyEntries).Reverse();

StringBuilder sb = new StringBuilder();

foreach (string str in splitAry)
{
    sb.Append(str);
    sb.Append(spliton[0]);
}

string final = sb.ToString();

If you want to use Linq a bit more to make this shorter:

C#

private List<string> ReverseAndAppend(string source, string appendelement)
{
    return source
        .Split(new string[]{appendelement}, StringSplitOptions.RemoveEmptyEntries)
        .Reverse()
        .Select(str => string.Concat(str, appendelement)).ToList();
}

// test like this:

// string test = @"Val1!@#$%Val2!@#$%Val3!@#$%Val4";
// List<string> testList = ReverseAndAppend(test, @"!@#$%");