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Representing classes in xml. hmmm.
Shameless plug here, but it sounds like what you're looking for is MyXaml (see sig).
Marc
MyXaml
Advanced Unit Testing
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I want to load xml file data into a tree view in .NET using DOM. The thing is that if there are multiple "book" nodes in the xml file. xml tree shows only one instance of "book". If one book node in xml file contains a child node say "publisher" which the other book node doesn't contain, the tree view still show the "publisher" node. You can say that tree view should show the union of all the child nodes for the element "book". The way stylus does or the way xmlspy does. Any solution??
@!$h@
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One solution is to transform the original document into your desired format through xslt first.
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I need to consume a web service that was not developed in .NET. This makes it difficult because the author does not supply a WSDL document. Without the WSDL, I can't generate the proxy needed to connect and use the web service.
I am assuming the way to get this done is to generate my own WSDL. Does anyone know how to go about this or have any idea where to even start on something like this?
Thanks in advance....
-Scott
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hi,
Microsoft eXentsible Application Markup Language.
In which manner it keep difference from XmL.
Only tag or scripting(xaml scripting).
**************************
S r e e j i t h N a i r
**************************
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I have a VB.NET application that is using an XmlDataDocument to store data in, this is created using an xml schema and the xml looks something like this:
<?xml version="1.0" standalone="yes"?>
<Root xmlns="http://tempuri.org/XXX.xsd">
<Node1>
Elements...
The problem is that I need to transform this using an xsl document, to get a formatted html page of the data. To do this I have to add a reference to the xsl document in the xml and remove the schema reference for the transformation to work.
The end result I need to change the xml to is:
<?xml version="1.0" standalone="yes"?>
<?xml-stylesheet type='text/xsl' href='XXX.xsl'?>
<Root>
<Node1>
Elements...
I can add the xsl reference by adding a processing instruction to the XmlDataDocument, but I can't find a way of removing the NamespaceURI from the root node.
I have also tried creating a new XmlDoc, manually creating the declaration, processing instruction and root node without the xsd reference, then copying the inner xml from the original doc root node to the new root node. The problem here is that the xsd reference is then added to every child node.
Or am I missing something, is there a way to transform the XmlDataDocument using the xsl without removing the xsd reference.
Any advice on how to clear the NamespaceURI would be appreciated.
Regards
Jason
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TeleMessage Multi-Alert API
XML API to enable automated notifications to multiple communication devices. Send and receive interactive messages to: SMS, Mobile and Landline phone calls, Faxes and Emails.
Track message delivery and deliver real-time automated transactions.
Automating business processes could substantially reduce costs and increase efficiency.
For more information and sample scripts visit http://xml.telemessage.com/multialert
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I would like to create some dynamic help for a DLL I have written. I know that I need to create the XML file and plonk it in some directory, and I know what tags to use within the XML file, only problem is I can't seem to get it to display when my DLL project is selected.
this is what I have so far, please help if u can
<?xml version="1.0" encoding="utf-8"?>
<DynamicHelp xmlns="http://msdn.microsoft.com/vsdata/xsd/vsdh.xsd" xmlns:xsi="http://www.w3.org/2000/10/XMLSchema-instance" xsi:schemaLocation="http://msdn.microsoft.com/vsdata/xsd/vsdh.xsd vsdh.xsd">
<LinkGroup ID="TierXHelp" Title="TierX Help" Priority="600">
<Glyph Expanded="vs:/ctxhelp_opn.gif" Collapsed="vs:/ctxhelp_cls.gif"/>
</LinkGroup>
<Context>
<Keywords>
<KItem Name="VS.SolutionExplorer"/>
<KItem Name="VS.TextEditor"/>
</Keywords>
<Attributes>
<AItem Name="Product" Value="C#"/>
</Attributes>
<Links>
<LItem URL="c:\TierX.htm" LinkGroup="TierXHelp">Sample TierX Help Page</LItem>
</Links>
</Context>
</DynamicHelp>
Christo Van Niekerk
(South Africa)
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Hello,I am trying to create <xsl:value-of select="....."> element(... means any string value) in a XML document.I used xmldocument.createElement("xsl:value-of select=\".... "); command.But it is not correct.how can I create xsl instructions in xml document with this method?Or should I try another way?Please help
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1) create element takes an element name, not attributes as well xmldocument.createElement("value-of")
2) you need to create and associate a namespace for the document for xsl to the xsl uri
3) when you do 1) above, pass 2) as the second parameter
4) you need to call setattibute on the element create to add the select.
"When the only tool you have is a hammer, a sore thumb you will have."
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Hello buddies,
Can you guid me thru sending a file to Webservice so it can save it somewhere on the server?
Thank you so much
- Den 2 fly
---
"Art happens when you least expect it."
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If the file u r refering is in xml u can use xmlnode /
xmldocument else u can send as an array of bytes
and create the file on the server.
cool man
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hi!
why does the code below not work -
IXMLDOMDocument * iXMLDoc;
VARIANT_BOOL bSuccess=false;
if (!PyArg_ParseTuple(args, "s", &command))
return NULL;
// specify xml file name
//iXMLDoc->loadXML(command);
iXMLDoc->loadXML(command,&bSuccess);
the error i get is
C:\hons\pocketpc\testXML2\testXML2.c(12) : error C2065: 'false' : undeclared identifier
C:\hons\pocketpc\testXML2\testXML2.c(20) : error C2039: 'IXMLDOMDocument_loadXML' : is not a member of 'IXMLDOMDocument'
C:\Windows CE Tools\wce300\Pocket PC 2002\include\msxml.h(2230) : see declaration of 'IXMLDOMDocument'
thanks
cheers
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I think you should try using VARIANT_FALSE instead of just "false", and I believe to load an XML document you should use "load" instead of "loadXML".
Dave
"You can say that again." -- Dept. of Redundancy Dept.
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I am making XML comments with the Build Comment Web Pages tool is VS Studio .NET 2003. When a <see cref="xxx"> tag is used it appears in the HTML created by the tool in the xxx.html file but is not rendered by my IE6 browser.|
Any clues? ...
Gary Hyslop
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Post a small demonstration of the output and I'll look at it.
--
Aaron Eldreth
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The following is an exerpt of the HTML produced by the "Build Comment Web Pages" tool in VS Studio.NET 2003:
<title>ZedGraph.CurveItem
...
This class contains the data and methods for an individual curve within
a graph pane. It carries the settings for the curve including the
key and item names, colors, symbols and sizes, linetypes, etc.
The array of independent (X Axis) values that define this
<see cref="CurveItem">.
The size of this array determines the number of points that are
plotted. Note that values defined as
System.Double.MaxValue are considered "missing" values,
and are not plotted. The curve will have a break at these points
to indicate values are missing.
When I display this HTML with my IE6 browser the "<see cref="CurveItem">" tag is not rendered.
Thanks for your help
Gary Hyslop
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I want to create a XSLT file in C#.NET manually.I mean that according to the user choice ,XSLT file will be created in background.But I know that there is not any class like XmlDocument,XmlTextWriter,XmlTextTeader for XSLT Document.How can I create this document?Should I use to File I/O class and how?I am waiting for your help...Thanks a lot...
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an XSLT file is just a normal xml file in a different namespace (http://www.w3.org/1999/XSL/Transform) so you can use any of the Xml classes to create it
"When the only tool you have is a hammer, a sore thumb you will have."
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What is the difference between <xsl:include> and <xsl:import>?
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I have the following xml:
<configuration>
<configObj>
<name>aaa</name>
<value>1234</value>
</configObj>
<configObj>
<name>bbb</name>
<value>5678</value>
</configObj>
</configuration>
I know the expression to get all the values, but I need to get for example the value for name aaa, is there an Expression string to do this?
Thanks in advance!
Cristina
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This should do the job:
/configuration/configObj[name='aaa']/value
Select the correct configObj with the predicate name='aaa', then select the child element you want.
HTH.
Stuart Dootson
'Java, Basic, who cares - it's all a bunch of tree-hugging hippy cr*p'
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