Security Access Error - C# Discussion Boards

12-Jul-04 17:22

dbetting wrote:
Are there some other links available to identify what I need to do to the executable and associated .dlls to allow/control network access?

I would recommend you read about Code Access Security on MSDN, they have a lot of great information, check this[^] out.

dbetting wrote:
With 100+ people in the company, is there a better way to manage the executables? Right now, when an update is done, it is a process of going to each workstation and copying it down. This is the primary reason to switching to network access.

Perform a network install, and with your users, place them in a Group, that way you can perform security checks like IPrincipal.IsInRole, etc.

- Nick Parker
My Blog | My Articles

code for adding

stevemasters2212-Jul-04 13:58

stevemasters22

12-Jul-04 13:58

Hi,

I've got three textbox's in my form, total(textbox1), hours(textbox2), material(textbox3). Does anybody know the event handler code to add hours(textbox2) + material(textbox3) to get a value in the total(textbox1). It must be done during runtime.

cheers
SM

KevinMac12-Jul-04 17:01

KevinMac

12-Jul-04 17:01

Hey Steve I am a little vague on what you are wanting to do.

Do you plan on using the standard TextChanged event or are you trying to build your own event.

this.textBox3.TextChanged += new System.EventHandler(this.CalcTotal);

private void CalcTotal(object sender, System.EventArgs e)
{
textBox1.Text =Convert.ToString(Convert.ToDecimal(textBox2.Text) + Convert.ToDecimal(textBox3.Text));

Now if you are wanting to add the textboxes at runtime and code the event that a little more fun. Create a member variable then initialize it. Be sure and add it to the Controls collection.

private System.Windows.Forms.TextBox textBox4 = new TextBox();

private System.ComponentModel.Container components = null;

public Form2()
{// initilize it in the constructor

textBox4.Location = new System.Drawing.Point(184, 154);
textBox4.Name = "textBox4";
textBox4.TabIndex = 3;
textBox4.Text = "0.00";
textBox4.TextChanged += new System.EventHandler(this.CalcTotal);
this.Controls.Add(textBox4);

InitializeComponent();
}

I don't know if this helps but good luck.

stevemasters2212-Jul-04 17:27

stevemasters22

12-Jul-04 17:27

Kevin

thx so much...your a star

cheers
SM

Nick Parker12-Jul-04 17:50

12-Jul-04 17:50

While I think Kevin helped you, it is important to understand that there is no specific event handler to do what you said, event handlers do just that; handle events. In your case, you might want to write a single function UpdateTotal(), that gets called when either values of your textboxes change. So when a certain event fires, you will call UpdateTotal(). This way you can perform additional error check to make sure valid data was submitted.

- Nick Parker
My Blog | My Articles

stevemasters2212-Jul-04 20:54

stevemasters22

12-Jul-04 20:54

Hi Nick,

ok, so what would be the code for my example?

cheers
SM

Nick Parker13-Jul-04 7:10

13-Jul-04 7:10

stevemasters22 wrote:
ok, so what would be the code for my example?

I am not going to write the code for this example, that is for you to do. You need to look into Int32.Parse[^] and TextBox.Text[^]. The MSDN[^] is a great source for information, if you have a specific question please feel free to post it. Good luck.

- Nick Parker
My Blog | My Articles

EventHandler problem

Jae Sammy12-Jul-04 13:33

12-Jul-04 13:33

Forgive me but I am very new to C# and VS.NET.

I have a number of submenu items that are created at run-time. When any of these items are clicked I want it to call the same function but with some sort of argument.

I have extended the System.EventArgs class to include a private member. Do I need to declare a delegate or can I use the System.EventHandler?

When I try declaring a delegate like this:
public delegate void OpenPortEventHandler(object sender, OpenPortEventArgs e);

And then add this eventhandler to a menu item like this:
this.OpenPort.MenuItems[index].Click += new OpenPortEventHandler(this.COM_Click);

I get this error: Cannot implicitly convert type 'Serial_Communicator.Terminal.OpenPortEventHandler' to 'System.EventHandler'

Confused | :confused:

Nick Parker12-Jul-04 14:21

12-Jul-04 14:21

What you can do is subclass the MenuItem and add your event and delegate there.

class OpenPortMenuItem : MenuItem
{
    public delegate void OpenPortEventHandler(object o, OpenPortEventArgs e);
    public event OpenPortEventHandler PortClick;

    public OpenPortMenuItem()
    {
        this.PortClick += new OpenPortEventHandler(OnPortClick);
    }

    protected override void OnClick(EventArgs e)
    {
        if(PortClick != null)
        {
            OpenPortEventArgs args = new OpenPortEventArgs();
            args.Port = 80; //default value
            PortClick(this, args);
        }
    }

    protected void OnPortClick(object sender, OpenPortEventArgs e)
    {
        base.OnClick(e);
    }
}
     class OpenPortEventArgs : EventArgs
{
    private int _port;
    public int Port
    {
        get{return _port;}
        set{_port = value;}
    }

    public OpenPortEventArgs(){}
}



    // using it somewhere...
    OpenPortMenuItem m = new OpenPortMenuItem();
    OpenPortMenuItem m2 = new OpenPortMenuItem();
    m.Click += new EventHandler(this.COM_Click);
    m2.Click += new EventHandler(this.COM_Click);
    this.mainMenu1.MenuItems.AddRange(new OpenPortMenuItem[] {m, m2});
    // more...
    private void COM_Click(object sender, OpenPortEventArgs e)
    {
        // Get the menu item.
        MenuItem m = sender as MenuItem;
        if(m != null)
        {
            // use m here.....
        }
        OpenPortEventArgs a = e as OpenPortEventArgs;
    if(a != null)
        {
            // use a here...
        }
     }

- Nick Parker
My Blog | My Articles

Jae Sammy12-Jul-04 18:19

12-Jul-04 18:19

Nick:

I can't thank you enough. Works like a charm. I'll have to examine a little closer to see exactly what you did.

Thanks again.

-Jae

Jae Sammy13-Jul-04 5:39

13-Jul-04 5:39

Nick:

I was actually able to get it working with less code that you gave me there. Any idea why the code still works when I change the class to the following:

public class OpenPortMenuItem : System.Windows.Forms.MenuItem
{
//public delegate void OpenPortEventHandler(object o, OpenPortEventArgs e);
//public event OpenPortEventHandler PortClick;
private int index;

public OpenPortMenuItem(int index)
{
this.index = index;
//this.PortClick += new OpenPortEventHandler(OnPortClick);
}

protected override void OnClick(EventArgs e)
{
//if(PortClick != null)
//{
OpenPortEventArgs args = new OpenPortEventArgs(this.index);
OnPortClick(this, args);
//}
}

protected void OnPortClick(object sender, OpenPortEventArgs e)
{
base.OnClick(e);
}
}

And I use the menuitem like this:

this.OpenPort.MenuItems.Add(index,m);
this.OpenPort.MenuItems[index].Click += new System.EventHandler(this.COM_Click);

Let me know if that check for PortClick != null is there for some sort of error catching.

-Jae

Nick Parker13-Jul-04 7:16

13-Jul-04 7:16

Jae,
The check of if(PortClick != null) checks to see if the events' internal linked-list of handlers has any registered handlers or not, otherwise there is no reason to call anything if no one is listening. Others could use your OpenPortMenuItem class and attach their own event handlers to the PortClick event.

- Nick Parker
My Blog | My Articles

Jae Sammy13-Jul-04 7:40

13-Jul-04 7:40

Nick:

Does that mean that the following:
protected override void OnClick(EventArgs e)
{
if(PortClick != null)
{
OpenPortEventArgs args = new OpenPortEventArgs(this.index);
OnPortClick(this, args); //Function call
}
}

Would be better written as this:
protected override void OnClick(EventArgs e)
{
if(PortClick != null)
{
OpenPortEventArgs args = new OpenPortEventArgs(this.index);
PortClick(this, args); //Raise the event
}
}

That way anyone else who has attached delegates to the PortClick event will be triggered when the menu item is clicked? Unsure | :~

-Jae

my blog

Nick Parker13-Jul-04 8:29

13-Jul-04 8:29

Yes, sorry, the correct way would be to fire the event after you have checked if it was null. I will correct my initial posting. Wink | ;)

- Nick Parker
My Blog | My Articles