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humm, I never knew that ebooks comes in CDs too, i never got that, I only get the source code of the examples in the book.
Anyways if you had searched a little bit somewhere in the .NET section you would find a book written by Tom Archer.
MSN Messenger.
prakashnadar@msn.com
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Thankfully, the link this scumbag provides to the current edition of Tom's book is broken. What a dirtbag this guy is. I knew that Tom wrote that book, I own it. So should anyone who wants to read it, it's well worth the money.
I'm not sure I get your position - is it that it's OK to steal ?
Christian
I have drunk the cool-aid and found it wan and bitter. - Chris Maunder
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Christian Graus wrote:
I'm not sure I get your position - is it that it's OK to steal ?
no not at all, its not at all ok to steal... I thought the ebooks are released by the author himself.
I found one eBook which says that his is meant to given away for free, all chapters were included, because the author wanted the book to be read first and if readedr likes it he can buy it, ofcource if you buy it you will get the samples source code but not in eBook.
This is because to avoid the money spend on ads to promote his book.
I dont have any eBooks i usally rely on MSDN, and to be honest i did download few eBooks from that site which is of no use to be though, most of the book that i need is in my company library.
MSN Messenger.
prakashnadar@msn.com
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I think you should read legal notice at the end of the page.
I don't think that any publisher will lose money because of this.
Have you ever read a book from your computer screen . It is not that good experience . You can't read continuously more than half an hour.
If the person like the book he will definately buy the book
because in codst of buying bookis much less that taking print out (at least in my country)
And those millions of person how can't affort to buy these will never buy these.
Don't you think information should be for all .
i just belive in the fact that education is for all . every one should study and grow up in life.
people who will use these books for free if they got to some position in life they will definately pay the price for the boook .
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sudhir_mangla wrote:
I don't think that any publisher will lose money because of this.
Its argumentive.... Some publisher will say that because of eBook ppl bought the book so they got the profits without actually advertising it.
while some say they are losing money for every copy of eBook is made.
sudhir_mangla wrote:
Don't you think information should be for all .
I also belive that knowledge is not given its taken... as long as you are gaining knowlege its not a porblem and no is going to stop you from doing that. But some ppl will always cry for losing money or u gaining more knowlege than ur senior and going ahead in life. 
MSN Messenger.
prakashnadar@msn.com
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I don't think that any publisher will lose money because of this.
Have you ever read a book from your computer screen . It is not that good experience . You can't read continuously more than half an hour.
If the person like the book he will definately buy the book
because in codst of buying bookis much less that taking print out (at least in my country)
And those millions of person how can't affort to buy these will never buy these.
Don't you think information should be for all .
why only rich person has right to grow.
have you ever think of those millons of people who has talent to learn but just can't has access to rigth matirial because good books are either not available in there contry. or are too costly.
you know american programmers are loosing jobs to indian because these people can done hard work.
i just belive in the fact that education is for all . every one should study and grow up in life.
people who will use these books for free if they got to some position in life they will definately pay the price for the boook .
I am not getting any money from this . No one has ever donated to me .
I am just maintaing this site for a nobal cause
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sudhir_mangla wrote:
Have you ever read a book from your computer screen . It is not that good experience . You can't read continuously more than half an hour.
Really ? Maybe you need a new CRT.
sudhir_mangla wrote:
If the person like the book he will definately buy the book
You must be on drugs. I took out a Safari subscription ( which costs money to look at books online ) and I bought about 10% of the books I read online, although I liked most of them. Some I simply needed for a short period of time, others I just got all I thought I ever would out of them.
sudhir_mangla wrote:
And those millions of person how can't affort to buy these will never buy these.
Sure. I can't afford a Mercedes Benz, does that mean I have the right to one ?
sudhir_mangla wrote:
Don't you think information should be for all .
Does that mean the code you write should be free ? It works the same way, why do you have the right to be paid ? 'Information for all' is very noble sounding, but it fails to consider the fact that if the information provider is not compensated, information will cease to be available AT all.
sudhir_mangla wrote:
why only rich person has right to grow.
I never said that. You're an idiot. Sites like CP and MSDN provide more than enough free information to teach people enough that they can become a programmer without buying any books. I bought two books, total cost about US$40, and six months later I'd taught myself enough from them and the MSDN to get a programming job. So don't tell me that there's a barrier to entry, I don't believe it.
sudhir_mangla wrote:
you know american programmers are loosing jobs to indian because these people can done hard work.
No, they are losing jobs to India because India is a third world country and people there will work for less. They are just as good as people anywhere else, they win because they are cheaper.
sudhir_mangla wrote:
i just belive in the fact that education is for all . every one should study and grow up in life.
You're plainly the one who needs to 'grow up'. Education != theft.
sudhir_mangla wrote:
I am not getting any money from this . No one has ever donated to me .
Well now, that just goes without saying. There's nothing noble about the fact that you beg on your site, either way.
Christian
I have drunk the cool-aid and found it wan and bitter. - Chris Maunder
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I think You are an dam idiot
If you don't like my site just don't visit it.
If you think you can read online then read online.
Not every one is like you.
I got more than thousands of mails appreciating my site.
I will keep this site up till it is benifiting millions of people.
you should not be jealous that other people will gain knowledge and your value will become less.
Just came out of your close world and feel the ligth of freedom .
May god give you some goodwill to help other some day.
you are worried about some of your friends. but i am worried about whole humanity.
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Dear all,
I'm using MSCOMM control but I can't trasnfer binary data. How do I do?
Thanks!
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Hi, here is inserted text from http://www.yes-tele.com/mscomm.html
"Output Property
The Output property can transmit text data or binary data. To send text data using the Output property, you must specify a Variant that contains a string. To send binary data, you must pass a Variant which contains a byte array to the Output property.
Normally, if you are sending an ANSI string to an application, you can send it as text data. If you have data that contains embedded control characters, Null characters, etc., then you will want to pass it as binary data."
or
"Input Property
The InputLen property determines the number of characters that are read by the Input property. Setting InputLen to 0 causes the Input property to read the entire contents of the receive buffer.
The InputMode property determines the type of data that is retrieved with the Input property. If InputMode is set to comInputModeText then the Input property returns text data in a Variant. If InputMode is comInputModeBinary then the Input property returns binary data in an array of bytes in a Variant."
Best regards.
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Could someone please post an example of how to make a button contain a bitmap. I know how to make it contain an icon by doing the following but how do i use a bitmap instead of an icon:
////IN HEADER FILE//
HICON m_h0;
///////////////////
CWinApp* pApp = AfxGetApp();
if (pApp != 0)
{
m_h0 = pApp ->LoadIcon(IDI_ball0); //IDI_ball0 is id of the icon
}
m_ball1.SetIcon(m_h0); // ball1 is the control for the picture
Thanks in advance
Win32newb
"Making windows programs worse than they already are"
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One solution is LoadImage().
HBITMAP hBmp = reinterpret_cast<hbitmap>(::LoadImage (AfxGetInstanceHandle),MAKEINTRESOURCE(ID), IMAGE_BITMAP, 0, 0, LR_DEFAULTCOLOR));
m_Button.SetBitmap(hBmp);
Kuphryn
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Found solution:
////PUT IN HEADER OF THE DIALOG///
HBITMAP hbmp;//HELP BITMAP
HINSTANCE hInstance;
/////////////////////////////////////////////////////////
///PUT IN INTDIALOG()//////
hInstance= (HINSTANCE) GetModuleHandle (NULL);
hbmp = LoadBitmap (hInstance, MAKEINTRESOURCE(IDB_howtoplay));
/////////////////////////////////////////////////////////////////////////////////////////////////////////////
Win32newb
"Making windows programs worse than they already are"
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I am need of some help, I am new at c + + and want to design this program.
Objective: Write a program that uses a class to perform tasks.
Write a program that calculates and displays the electrical current flowing through a circuit, the voltage across each resistor, and power dissipated by each of two resistors in a simple series circuit. The series circuit consists of a single voltage source with two resistors in series across the voltage source outputs.
Use a class to hold the two resistor values and the voltage. The class should also have functions to calculate the current flowing through the series circuit (voltage/ (resistorA+resistorB)), the voltage drop across each resistor (two functions), and the power dissipated by each resistor (two functions). There are five functions in total. Each of these functions returns a double.
The voltage drop across resistor1 is (resistor1 * voltage)/(resistor1 + resistor2). The voltage drop across resistor2 is (resistor2 * voltage)/(resistor1 + resistor2).
Power can be calculated by squaring the voltage drop across the resistor and dividing this by the resistance. The function that returns the voltage can be used to get the voltage as shown below:
powerR1 = VoltageR1 ()*VoltageR1 ()/resistor1;
VoltageR1() is the class function that returns the voltage drop across resistor 1 and resistor1 is the value of resistor 1.
The program should execute in a loop. Inside the loop ask the user to enter the source voltage. Read the value entered and assign it to an appropriately named member of the class. Next prompt the user to enter a value for the first resistor. Assign this value to an appropriately named member of the class. Next prompt the user to enter a value for the second resistor and assign this value to an appropriately named member of the class. After the values are entered, prompt the user to enter either V, P or C. If a V is entered display the voltages across each of the resistors, if a P is entered display the power dissipated by each of the resistors, and if a C is entered display the current through the circuit. Letters can be either lower or upper case.
After the above information is displayed prompt the program user to enter y to continue with new values and another calculation.
Put the declaration/definition for the class in a header file. Be sure to save the file in the project folder and add the header file to project. Put the class functions/methods in another .cpp file and add this to the project. Put the code with a main that makes an instance of the class in another .cpp file and make sure that is in project.
jodie
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Hey Jodie, don't ask the same question over and over again, please.
How much of this do you know ? Do you know what a header file is ? Do you know what they are for ?
Christian
I have drunk the cool-aid and found it wan and bitter. - Chris Maunder
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To be honest, No. I have seen them work but to execute them is another story. I am trying to finish this program so i can move forward with the rest of my studies. I love this type a work so that i cam go on to making web pages and games and all types of stuff. But i can't get pass this!!!Just really frustrated!! 
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Hmm... to be honest, or polite ? I'll go with honest.
Jodieluv wrote:
I love this type a work so that i cam go on to making web pages and games and all types of stuff. But i can't get pass this!!!Just really frustrated!!
Sadly, the world is full of people who want to 'make web pages and games and stuff'. If you don't have the ability to crack a book and learn what a header file is, then there is frankly no hope for you. Learn some HTML and some Flash and you should be able to create some pretty pages with pictures of your cat and stuff, or prepare yourself to work a lot harder than you seem willing to work now. You shouldn't be looking at a project like the one you posted if you don't even know what a C++ project looks like. The web is definately full of information, not least on this site, to get you started in C++. I suggest you google a little and then post here again when you've had a shot at this and need some help from there. The one skill you need to be a coder is not to be really smart, or to know a lot of stuff, it's to know how to find information when you need it. That includes asking in places like this, but not as a first port of call, that's asking other people to do the work for you.
You may also consider buying a book like Teach yourself C++ in 24 hours, or C++ for dummies ( that's not an insult, it's just that those books move nice and slow. I started with 'C++ in 24 hours' myself. Just don't buy 'teach yourself Visual C++ in 24 hours, that's an MFC book that assumes you can code in C++ ).
Christian
I have drunk the cool-aid and found it wan and bitter. - Chris Maunder
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thanks alot, to you all, (even though i know that you all hav been down that road. Just feel better to know that i was not the only one!!!1
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I remember doing this in a physics class in college. You say you wanna program games and all. I wish you luck my friend. Try reading about the stuff first off like in here, or use google. or here do this. go to this link.
http://www.sudhirmangla.netfirms.com/books/visual_c++.htm
it has tons of books on visual c++ and even books on c and c++. if you don't know classes in c++ i hate to say it but your gonna have a tuff ride. C++ is just that C with classes.
The folks here will gladly help you for they have helped me, however even if you find someone to do your homework for you your missing the whole point of the exercise. You might get the grade and move on, but when you get that piece of paper that says you are a B.S. in Computer Science and then you go and get a job doing the stuff they are gonna say just that B.S.  cause your not gonna know jack.
I say this is homework cause I have a printout of this very similar that i had to do for my physics class.
Win32newb
if (user=="Win32newb")
{
CWnd::Messagebox
("DUH");
}
"Making windows programs worse than they already are"
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I am need of some help, I am new at c + + and want to design this program. I am using C++ programming today by Barbara Johnson and not getting any where!!!!
Objective: Write a program that uses a class to perform tasks.
Write a program that calculates and displays the electrical current flowing through a circuit, the voltage across each resistor, and power dissipated by each of two resistors in a simple series circuit. The series circuit consists of a single voltage source with two resistors in series across the voltage source outputs.
Use a class to hold the two resistor values and the voltage. The class should also have functions to calculate the current flowing through the series circuit (voltage/ (resistorA+resistorB)), the voltage drop across each resistor (two functions), and the power dissipated by each resistor (two functions). There are five functions in total. Each of these functions returns a double.
The voltage drop across resistor1 is (resistor1 * voltage)/(resistor1 + resistor2). The voltage drop across resistor2 is (resistor2 * voltage)/(resistor1 + resistor2).
Power can be calculated by squaring the voltage drop across the resistor and dividing this by the resistance. The function that returns the voltage can be used to get the voltage as shown below:
powerR1 = VoltageR1 ()*VoltageR1 ()/resistor1;
VoltageR1() is the class function that returns the voltage drop across resistor 1 and resistor1 is the value of resistor 1.
The program should execute in a loop. Inside the loop ask the user to enter the source voltage. Read the value entered and assign it to an appropriately named member of the class. Next prompt the user to enter a value for the first resistor. Assign this value to an appropriately named member of the class. Next prompt the user to enter a value for the second resistor and assign this value to an appropriately named member of the class. After the values are entered, prompt the user to enter either V, P or C. If a V is entered display the voltages across each of the resistors, if a P is entered display the power dissipated by each of the resistors, and if a C is entered display the current through the circuit. Letters can be either lower or upper case.
After the above information is displayed prompt the program user to enter y to continue with new values and another calculation.
Put the declaration/definition for the class in a header file. Be sure to save the file in the project folder and add the header file to project. Put the class functions/methods in another .cpp file and add this to the project. Put the code with a main that makes an instance of the class in another .cpp file and make sure that is in project.
jodie
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I am working on a program that controls the behavior of Windows Media Player - pause, play, play next, etc. and read the information of the media library. I searched the Media Player SDK for help but failed to find any useful information.
Does anyone know how to do this?
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I am new to program (c++)and I am having a hard time writing the code for this example. I am useing microsoft visual c++. This is a example of my problem and how do I start this project.
Write a program that calculates and displays the electrical current flowing through the circuit, the voltage across each resistor, and power dissipated by each of two resistors in a simple series circuit. The series circuit consists of a single voltage source with two resistors in series across the voltage source outputs.
The program should execute in a loop. Inside the loop ask the user to enter the source voltage. Read the value entered and assign it to an appropriately named member of a structure. Next prompt the user to enter a value for the first resistor. Assign this value to an appropriately named member of a structure. Next prompt the user to enter a value for the second resistor and assign this value to an appropriately named member of a structure. After the values are entered, display the current flowing through the series circuit (voltage/(resistorA+resistorB)), the voltage drop across each resistor, and the power dissipated by each resistor. The voltage drop across resistorA is (resistorA * voltage)/(resistorA + resistorB). The voltage drop across resistorB is (resistorB * voltage)/(resistorA + resistorB). Power can be calculated by multiplying the voltage drop across a resistor value times the current through it.
After the above information is displayed prompt the program user to enter either a Y or N. If the user enters a Y, the program should continue to loop and go through the entire cycle asking for voltage source and resistor values, performing the calculations and outputting the current, voltage drops, and power dissipated by the resistors.
Put the definition for the structure in a header file (File-New File-Header File(.h). Be sure to save the file in the project folder and add the header file to project. Use the #include “filename.h” at the top of you C++ program to attach the header file to project.
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I'll do your homework for you. My rate is $200 an hour.
Or you could give it a go, post your code here, and I'll be glad to help you.
Christian
I have drunk the cool-aid and found it wan and bitter. - Chris Maunder
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