|
If it is controlled only through browser, it's enough to send correct http requests, which can be easily done by opening tcp connection to the device and sending the request. You should see then in captured data something like GET /image HTTP/1.0 followed by crlf and some set of headers, ended by 2*crlf
If there's some ActiveX or whatever that keeps separate tcp connection there can be a problem, that the protocol inside doesn't allow simple replaying, but I don't see a reason for doing that. Maybe that you just missed something or add some more data or whatever that your protocol differs from the protocol of device.
|
|
|
|
|
Hi
Thanks for ur reply. As you said, the http header is there in the captured packet. But what I did is I sent the data after the http (ended by 2 ctrlf) thinking as that payload is having the control signal. Beacause when I captured packets (in four directions top,left,bottom,right) they are differing only in the content after the http header.
So what I can do, any clues??
Regards,
SatyaDY
|
|
|
|
|
Hmm then I assume that the header contains POST on beginning and these are the POST data. Then there's only one URL and the 'commands' are transferred to the camera inside the POST data.
I think, that if you try to do left, left, left, capture the packets, and these three packets doesn't differ in their content, you have to do something wrong in your sending side - try to capture your packets as well and compare the data at this binary level with originally captured 'left command'
If the data in these three commands differ, it will be much more difficult, because then you have really to hack the protocol. Even that can be done, but before I'd recommend to contact the vendor asking for the description. They are usually willing to do it, if you're doing something serious with that hw - like integrating that to your application or whatever.
We'll see what it will do 
|
|
|
|
|
Hi,
I could not understand what u told, sorry. Can U explain in detail??
I am trying to integrate this IP camera to my existing application, which plots the path of a falling object whose coordinates(x,y,z) are given by radars. I just want control this IP camera to track the falling object from the inputs given by the radars in addtion to plotting it on bitmap, so that people can view the object with their web browsers.
Thanks a lot for ur help.
Regards, 
SatyaDY
|
|
|
|
|
well, so again
I would check this:
- send and capture 3x left command sent from webbrowser.
- compare these captured packet, if they are the same
- if yes, construct my packet (the same as the original)
- send it and capture it
- compare my captured packet with original captured, shouldn't differ
if the three packets generated by the 3x left commands differs in a data section, this will be more complicated to do and first think I would do is to contact the vendor of the hardware to get the protocol
|
|
|
|
|
Hi again,
I have given the 3 left commands, and saw the packets.
The packets details are like this:
One command is having the following packets twice.
1.368 byte packet (with http header)(from my pc to IP camera)
2.60 byte packet (without http header)(from IP camera to mypc)
3.121 byte packet(with http header)(from IP camera to mypc)
And there is a change in the payload of 368 byte packet.
I thought, the first 368 is the control signal, 60 is the ack, and this 121 I could not guess?? What it could be?? Any guess.
Thanks again,
SatyaDY
|
|
|
|
|
Normally the ACK should be only on TCP level, therefore every data you receive are supposed to be delivered to the application. For that reason I assume that there must be something that understands the data returned back.
How about content of the control packets (PC to IPcam) - does it changes between the three left commands?
|
|
|
|
|
Yeah you right it's not pure browser it's opening an applet for viewing the picture and one more for showing the controls.
As I told the control(left) is sending sequence of 368,60,121 byte packets. For one control(left button) it is sending two sets of the above sequence. And the 368 byte packet is having only one byte change in the payload(that is after the http content).
Satya
|
|
|
|
|
Hmm then they are open to use any sort of custom protocol they want...
That means you have to analyse the content of the packets, not only their length - hack the protocol .
This means taking a piece of paper, changing the input conditions (left command, right command or other combinations) and make notes what and how was changed - even in replies, trying to figure out the whole system.
Or, the easier method, you can try to contact the vendor of the hardware, simply asking for a protocol, I'm doing that time to time and it works. Sometimes only you need to sign an NDA, but it's OK as long as the project is working . If this is not an option we can go on and try to hack it, but, you know, I would try it at least.
|
|
|
|
|
Hi,
Definetely I will contact the vendor, meanwhile I will continue to analyse the packets. What shall I do now ?? Shall I try to send the 368 byte packets and see what happens?? How shall I proceed ?? Shall I see if I get the same response (60,121 byte) packets ?? What is NDA 
One more doubt, sending the packet (368 byte) is it not sufficient?? (Is that no hacking??). What we have to do exactly??
Regards ![Rose | [Rose]](https://codeproject.global.ssl.fastly.net/script/Forums/Images/rose.gif)
SatyaDY.
|
|
|
|
|
NDA = Non Disclosure Agreement - something in general saying that if they tell you something, you're not allowed to tell it someone else, except written permisson...
OK, let's rock it!
To make things easy I would try to send the first 368 byte packet and see what's on. If the camera makes what it should, we're on the safe side, else it means that the protocol between needs deeper analysis.
What I do usually is to try to send the same command under exactly the same conditions and then analysing the content of the data flow if there are some changes. If the nature of protocol alows it, I'm usually focusing on one command and continue with another commands in a moment, when the first one works.
During that I usually makes a notes regarding what byte/string on which position mean - or what I think it can mean. This includes command bytes, parameters, checksums, sequence numbers, timestamps and other parts usually used in protocols. For that you need to catch the same command (move left for example) several times under the same conditions (camera position etc) that you can compare the content of the packet - what changes and when.
This makes a some homemade protocol description, that I can use later for constructing my own packets or whole communication.
|
|
|
|
|
Yes geo,
I will try it and get back to U.
Satya
|
|
|
|
|
Just started having to use C++ again after quite a bit of time of using Visual Basic, and going back is quite a pain.
I'm needing to zero-pad some hex output that my program spits out... problem is, I don't have a clue how to do it without using loops. Is there a simple way to zero-pad all information outputted by printf, or not?
|
|
|
|
|
|
Yep, that did it. Thanks a lot for the quick reply.
|
|
|
|
|
Hello all,
I would like to know how can I check whether the folder is exist or not? Which function should I use in visual C++? and which library should I included into my program?
Thanks!
Nachi
|
|
|
|
|
try using chdir function.
i.e., set the current directory to the required folder. if it fails then the folder does not exist (or atlease unusable)
|
|
|
|
|
_access() can Determine file-access permission.
Return Value
Each of these functions returns 0 if the file has the given mode. The function returns –1 if the named file does not exist or is not accessible in the given mode; in this case, errno is set as follows:
EACCES
Access denied: file’s permission setting does not allow specified access.
ENOENT
Filename or path not found.
Thinking in difference!
|
|
|
|
|
I like using _access() myself, but GetFileAttributes() is also available.
|
|
|
|
|
how to use WINDOWINFO ,I can not use it.
|
|
|
|
|
china_nn wrote:
I can not use it.
Because why? Are you receiving compiler, linker, or run-time errors? How about a small code snippet of what you have that is not working.
WINDOWINFO wi;<br />
GetWindowInfo(handle_to_some_window, &wi);
|
|
|
|
|
i want to synchronize the keyboard input of two windows.that is ,
i have two windows(window1 and window2).window1 is the top window on the desktop,window2 is behind window1. there is a edit control on both windows.
when i input char in the edit of window1.i want window2 change with window1.juse like i both input char in edit of window2.
the function AttachThreadInput seems to resolve my problem, but it does not work as i expected.
anyone can tell me other solutions.
here i should tell that window1 and window2 are in deffrent processes.window2 is an existent third-party program. i can do nothing about it.all i can do is in window1.
gucy
|
|
|
|
|
What about using some API calls to find the hWnd of the textbox in Window2. Take a look at:
- FindWindow
- GetDlgItem
Use it somewhat as follows:
HWND hMainWindow = FindWindow("[ClassName of main window]", NULL);
if(hMainWindow != NULL)
{
HWND hTextbox = GetDlgItem(hMainWindow, [ID of the textbox]);
...
}
You can find out the classname of the main window and the ID of the textbox using Greatis Windowse (google on it, I don't have the link just like that).
Once you figured out the hWnd of the textbox, you can use SetWindowText or a SendMessage WM_SETTEXT to put the text in the box in dialog 2.
Another option might be SetDlgItemText, but then you can't check the hTextBox hWnd to be valid or not before sending.
Good luck!
- Fahr
|
|
|
|
|
i want to synchronize the keyboard input of two windows.that is ,
i have two windows(window1 and window2).window1 is the top window on the desktop,window2 is behind window1. there is a edit control on both windows.
when i input char in the edit of window1.i want window2 change with window1.juse like i both input char in edit of window2.
the function AttachThreadInput seems to resolve my problem, but it does not work as i expected.
anyone can tell me other solutions.
here i should tell that window1 and window2 are in deffrent processes.window2 is an existent third-party program. i can do nothing about it.all i can do is in window1.
gucy
|
|
|
|
|
I download a software from:http://www.dachshundsoftware.com/download.html
It can defrag the Memory. How does it work?
Let's roll!
|
|
|
|
General 
News 
Suggestion 
Question 
Bug 
Answer 
Joke 
Praise 
Rant 
Admin 
Submit an article or tip
