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int n = i;

In this example c# code "i" can equal 11. can you fix it?

for (int i=0; i <= 10; i++)
{
    var task = Task.Run(async () =>
    {
      var convertResp = await StartTestConvert(i);
      ... other stuff
    });
}

Yes, in the provided code, the variable i is captured by the async lambda expression, which means by the time the async operations inside the lambda complete, the value of i may have changed. To fix this, you need to capture the loop variable correctly. Here's a way to do it:

for (int i = 0; i <= 10; i++)
{
    int current = i; // Capture the current value of i
    var task = Task.Run(async () =>
    {
        var convertResp = await StartTestConvert(current);
        // ... other stuff
    });
}

By capturing the loop variable inside the loop, you ensure that each async operation receives its own copy of the loop variable, preventing the issue where the value of i changes before the async operation completes.

dandy72 wrote:

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mspad wrote:

a camera and an 8-core parallel processor

MarkTJohnson wrote:

Could they get Ryan Reynolds to do their ads?