Introduction
In SQL Server, there is no database management view which can help us to find a list of all database indexes with their involved columns names.
Using the Code
Here is a script from my library which can help you to get a list of all indexes of database with its involved (key or include) column names.
SELECT '['+Sch.name+'].['+ Tab.[name]+']' AS TableName,
Ind.[name] AS IndexName,
SUBSTRING(( SELECT ', ' + AC.name
FROM sys.[tables] AS T
INNER JOIN sys.[indexes] I
ON T.[object_id] = I.[object_id]
INNER JOIN sys.[index_columns] IC
ON I.[object_id] = IC.[object_id]
AND I.[index_id] = IC.[index_id]
INNER JOIN sys.[all_columns] AC
ON T.[object_id] = AC.[object_id]
AND IC.[column_id] = AC.[column_id]
WHERE Ind.[object_id] = I.[object_id]
AND Ind.index_id = I.index_id
AND IC.is_included_column = 0
ORDER BY IC.key_ordinal
FOR
XML PATH('')
), 2, 8000) AS KeyCols,
SUBSTRING(( SELECT ', ' + AC.name
FROM sys.[tables] AS T
INNER JOIN sys.[indexes] I
ON T.[object_id] = I.[object_id]
INNER JOIN sys.[index_columns] IC
ON I.[object_id] = IC.[object_id]
AND I.[index_id] = IC.[index_id]
INNER JOIN sys.[all_columns] AC
ON T.[object_id] = AC.[object_id]
AND IC.[column_id] = AC.[column_id]
WHERE Ind.[object_id] = I.[object_id]
AND Ind.index_id = I.index_id
AND IC.is_included_column = 1
ORDER BY IC.key_ordinal
FOR
XML PATH('')
), 2, 8000) AS IncludeCols
FROM sys.[indexes] Ind
INNER JOIN sys.[tables] AS Tab
ON Tab.[object_id] = Ind.[object_id]
INNER JOIN sys.[schemas] AS Sch
ON Sch.[schema_id] = Tab.[schema_id]
ORDER BY TableName
Aasim Abdullah is working as SQL Server DBA with CureMD (www.curemd.com) based in NY, USA. He has been working with SQL Server since 2007 (Version 2005) and has used it in many projects as a developer, administrator, database designer. Aasim's primary interest is SQL Server performance tuning. If he finds the time, he like to sketch faces with graphite pencils.