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professionalEddy Vluggen4-Oct-18 2:15 
--edit

Didn't see the "already solved" part Smile | :)

From the code you shown;
VB
Sub Main()
    Const DEFAULTTEXT As String = "1, 0, 0, 1"
    Dim buf() As Byte = {49, 44, 32, 48, 44, 32, 48, 44, 32, 49, 0}
    Dim sReturn As String = System.Text.Encoding.UTF8.GetString(buf)

    ' This test is False, not equal
    If DEFAULTTEXT = sReturn Then
        sReturn = ""
    End If

    ' This test evaluates to true.
    If DEFAULTTEXT.CompareTo(sReturn) = 0 Then
        sReturn = "equal to default"
    End If

    Console.WriteLine(sReturn)
    Console.ReadLine()
End Sub
Outputs 1, 0, 0, 1

There's no quotes, because they aren't in the string. The Bytebuf starts with ascii 49, which means "1". 44 is a comma, 32 a space.
Bastard Programmer from Hell Suspicious | :suss:
If you can't read my code, try converting it here[^]
"If you just follow the bacon Eddy, wherever it leads you, then you won't have to think about politics." -- Some Bell.


modified 4-Oct-18 8:36am.

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