Re: Android USB Detection - Android Discussion Boards

Simple HTTP Post Request - application/json

Django_Untaken27-Jan-17 9:21

27-Jan-17 9:21

Hello there. I am trying to make a simple http POST request using HttpUrlConnection. Problem is that response code is 200 but the response message NOT success.

You can see that I set all the necessary header parameters. I am supposed to get success message. But I get {"status":false,"message":"Invalid access"} with responseCode = 200.

Below is the code (I am developing against Lollipop)

Java

protected SubmitRequestTask.ResponseObject doInBackground(Object... object)
{
	String encodedStr = URLEncoder.encode(object.getDataToSendRAW(), "UTF-8");

	BufferedReader reader = null;
        int responseCode = -1;
	try
        {
            URL url = new URL(/*My SERVER URL*/);  //Converting address String to URL

	      Map<String, String> headerParams = new HashMap<String, String>();
	      headerParams.put("Accept", "application/json");
            headerParams.put("Content-Type", "application/json");

            HttpUrlConnection networkConnection = MakeRequest(
                    url,
                    "POST",
                    headerParams,
                    null);

            if(networkConnection == null)
                return new ResponseObject(-1, "Uknown Error");

            StringBuilder sb = new StringBuilder();
            reader = new BufferedReader(new InputStreamReader(networkConnection.getInputStream()));

            while ((response = reader.readLine()) != null)
                sb.append(response + "\n");

            response = sb.toString();
	}
	catch(Exception ex) {}
        finally { 
            responseCode = networkConnection.getResponseCode();
            networkConnection.disconnect();
        }

return new ResponseObject(responseCode, response);
}

private HttpUrlConnection MakeRequest(URL url, String method, Map<String, String> headerParams, NetworkConfig config)
{
	HttpURLConnection htp_url_connection = (HttpURLConnection) url.openConnection();
	htp_url_connection.setRequestMethod(method);
    
        if (headerParams != null && method.trim().toLowerCase().equals("post"))
        {
                htp_url_connection.setDoOutput(true);

                for (Map.Entry<String, String> entry : headerParams.entrySet()) {
                   (htp_url_connection.setRequestProperty(entry.getKey(), entry.getValue());
                }

                if (encodedStr.trim().length() > 0) {
                    OutputStreamWriter writer = new OutputStreamWriter(htp_url_connection.getOutputStream());
                    writer.write(encodedStr);
                    writer.flush();
                }
	}

	htp_url_connection.setConnectTimeout(5000);
	int responseCode = htp_url_connection.getResponseCode();

        if(responseCode == HttpURLConnection.HTTP_OK /*200*/)
                return htp_url_connection;
}

Sample JSON data (which I encode in doInBackground).

HTML

{
"plot_unique_id":"355618",
"plot_physical_address":"owner",
"plot_id":"355617",
"location":"31.475885,74.3422574",
"action_type":"1",
"plot_sub_id":"1",
"apk_version":"1.0",
"imei_no":"862037029044152",
"owners":[......]
}

What could be the problem?? Thanks for any input.

Re: Simple HTTP Post Request - application/json

Richard MacCutchan27-Jan-17 22:03

Richard MacCutchan

27-Jan-17 22:03

That is correct; the HTTP response is 200 telling you that the server responded with some data. The response data is a JSON reply which contains information about the JSON request. You need to contact the owners of the website, or the documentation, to find out why it returned the "Invalid access" status.

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