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Hi,
I would like to ask how can I use a $_SESSION["domain_name"] with window.location so this:
$('#btnBizHome').click(function() { window.location = 'passwordreset'; });
will look like this:
$('#btnBizHome').click(function() { window.location = $_SESSION["domain_name"] + 'passwordreset'; });
How can I do that?
Thanks,
Jassim
Technology News @ www.JassimRahma.com
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Hereafter please post all your PHP questions in PHP forum[^](which is suitable one).
Thank you.
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Your twelfth question in as many days. Don't you think a bit of learning would be of benefit?
Veni, vidi, abiit domum
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Try this out
$('#btnBizHome').click(function() { window.location = <?php echo $_SESSION["domain_name"] ?> + 'passwordreset'; });
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I am trying to have a share feature for the current page in my project but I am getting:
An error occurred. Please try again later.
can any one help please..
here is the page where you can try to share on facebook (using the Select an action) button:
http://www.xoompage.com/profile?id=347692ca-47a8-11e3-bea0-782bcb3e3838[^]
and here is the href for the facebook share:
https://www.facebook.com/dialog/feed?app_id=256274477853888&display=popup&caption=&link=&redirect_uri=
Technology News @ www.JassimRahma.com
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Can You let me know how your share need to be..?
For a basic share it is very easy you can give image title etc in the below code
$imageforfb ="Some image path";
$titlefor_fb="Some title for the page";
encodeURIComponent(location.href) = will automatically get the url of ur page
<a href="#" class="facebook social-provider-icon"
onclick="
window.open(
'http://www.facebook.com/sharer/sharer.php?s=100&p[url]=' + encodeURIComponent(location.href) + '&p[images][0]=<?php echo $imageforfb; ?>&p[title]=<?php echo $titlefor_fb; ?>',
'facebook-share-dialog',
'width=626,height=436');
return false;">
</a>
Just use this
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Have a look at this link.
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If you see this link now:
http://www.xoompage.com/profile?id=347692ca-47a8-11e3-bea0-782bcb3e3838[^]
the dropdown button is working fine but when I click on or MouseOver it and when the list appears it will move some elements on the page (e.g. profile photo).
I contacted the developers who said it's because the dropdown is inside a td and I should take it our of the td
Is there any solution? taking it out of the td is a major change.
I want the list to appear over the content without having to move other elements.
Please help..
Thanks
Jassim
Technology News @ www.JassimRahma.com
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HELLO
I am new to PHP and web based environment (noob), previously i was facing a problem with my code which is i cannot update the mysql table row when checkbox is checked... the idea is when checkbox is checked, then the value is +1. This is somehow likely to update the row on the table..
here is the code: (sorry if the code are messy because i also find the code in internet and edit it)
PHP code:
<html><body>
= mysql_connect(= array(= $_POST[= array();
= 1;= 0;= "UPDATE admin SET candidate1=candidate1 +1 WHERE candidate = candidate1.
mysql_query($sql,$con) or die('<br/>Error reading database: '.mysql_error($con));
header("
</body></html>
AND HERE IS THE INDEX:
VotePage.php
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>VOTING PAGE</title>
<script language="JavaScript" type="text/javascript">
function checkTheBox() {
var flag = 0;
for (var i = 0; i< 4; i++) {
if(document.form1["candidate[]"][i].checked){
flag ++;
}
}
if (flag != 5) {
alert ("PLEASE SELECT 5 CANDIDATE ONLY");
return false;
}
return true;
}
</script>
</head>
<body>
<center>
<div class="checkbox" data-toggle="false" data-min="2">
<table width="800" height="600" bgcolor="#28b6ee" border="0" align="center">
<h1>LIST OF CANDIDATE</h1>
<form name="form1" method="Post" action="CheckCandidate.php">
<tr width="800" height="600" >
<td width="160" height="50">
<img src="Voter.jpg" alt="Vote 1" align="top">
<input type="checkbox" name="candidate[]" value="1" />
</td>
<td width="160" height="50">
<img src="Voter.jpg" alt="Vote 2">
<input type="checkbox" name="candidate[]" value="1" />
</td>
<td width="160" height="50">
<img src="Voter.jpg" alt="Vote 3">
<input type="checkbox" name="candidate[]" value="1" />
</td>
<td width="160" height="50">
<img src="Voter.jpg" alt="Vote 4">
<input type="checkbox" name="candidate[]" value="1" />
</td>
<td width="160" height="50">
<img src="Voter.jpg" alt="Vote 5">
<input type="checkbox" name="candidate[]" value="1" />
</td></tr>
<tr>
<td width="160" height="50">
<img src="Voter.jpg" alt="Vote 6">
<input type="checkbox" name="candidate[]" value="1" />
</td>
<td width="160" height="50">
<img src="Voter.jpg" alt="Vote 7">
<input type="checkbox" name="candidate[]" value="1" />
</td>
<td width="160" height="50">
<img src="Voter.jpg" alt="Vote 8">
<input type="checkbox" name="candidate[]" value="1" />
</td>
<td width="160" height="50">
<img src="Voter.jpg" alt="Vote 9">
<input type="checkbox" name="candidate[]" value="1" />
</td>
<td width="160" height="50">
<img src="Voter.jpg" alt="Vote 10">
<input type="checkbox" name="candidate[]" value="1" />
</td>
</tr>
</table>
</div>
<div>
<table align="center">
<tr >
<td align="center" width="800" height="50">
<input type="Submit" name="Submit" value="Submit" onclick="checkTheBox();" />
</td>
</tr>
</table>
</div>
</table>
</div>
</form>
</center>
</body>
</html>
I'll BE GLAD IF THERE IS SOME ONE CAN SPEND SOMETIME TO LOOK AT THIS PROBLEM..THANK YOU
modified 20-Nov-13 0:45am.
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There are a lot of mistakes, some trivial, some logical, some syntatic, and there are others just did not make sense. Just to mention a few:
for the html part:
1. The values of checkboxes are all 1, in that way, we would not be able to know which ones are being voted.
2. The checkTheBox function only check up to 5 selections but there are 10 checkboxes and yet the subsequent code that followed is suggesting that one can only vote exactly 5 candidates. I am confused.
3. ...
for the php part:
1. The $values is never used after the foreach.
2. The sql statement does not make sense.
3. The header is incomplete and in the wrong place.
4. ...
May I take a look at the database table admin, what are the fields and their data types?
I will try to suggest sometime if it is not too time consuming.
modified 20-Nov-13 12:29pm.
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Did you try with the checkbox value="true" ?? i think it should be working if this is the only problem of your code...
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Try asking in the support forum[^] for that project.
"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer
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i typed
firefox -P in run but it open firefox home page
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You might have better luck on the Mozilla support site[^]. However, a quick search turns up this article[^], which suggests that Firefox is still running in the background.
"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer
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thanks that's helped me firefox was working in the background
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i'm really worried that if i enable GZIP Compression many consideration 1-
Older browsers
2-
CPU-load also i wanna i ask should compress minified css and js ????
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i searched google before i ask that question i need developers whom already work with gzip advice me
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The links I found contain a wealth of information that will help you make a decision.
Veni, vidi, abiit domum
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you just provide google search link
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And did you bother to follow that link and read any of the articles?
Veni, vidi, abiit domum
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i read them
Quickly it's using asp.net and for IIS not APACHE
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