Re: overlap - C# Discussion Boards

6-Nov-13 4:01

The first thing you need to do is look at the interface provided by the sensor, and how it communicates with a computer. It's most unlikely that this would be via a COM port.

Veni, vidi, abiit domum

overlap

Member 103812095-Nov-13 23:10

5-Nov-13 23:10

DateTime[] start = new DateTime[] { new DateTime(1990, 1, 1), new DateTime(1995, 1, 1), new DateTime(1995, 1, 1),new DateTime(2003, 1, 1) };
        DateTime[] end = new DateTime[] {   new DateTime(2000, 1, 1), new DateTime(2005, 1, 1), new DateTime(2005, 1, 1), new DateTime(2007, 1, 1)};
        i cannot explain what i what to do in earlier question so i have array that contain start days and another array contain end day. and i should calculate lenght of days i dont need calculate overlap days

|-------------------|
            |-----------------------|
            |-----------------------|
                    |---------------------|

Abhinav S5-Nov-13 23:53

Abhinav S

5-Nov-13 23:53

You can do this very easily using LINQ and TimeSpan.

First, get the minimum DateTime from the array(Min()).
Then get the maxumim DateTime from the array (Max()).

Using TimeSpan get the difference.

Apps - Color Analyzer | Arctic | XKCD | Sound Meter | Speed Dial

Member 103812095-Nov-13 23:58

5-Nov-13 23:58

sorry but i did not understand you

Abhinav S6-Nov-13 0:13

Abhinav S

6-Nov-13 0:13

Something like
accepted

If you want to find the earliest or latest Date:

DateTime earliest = arr.Min(record => record.Date);
DateTime latest   = arr.Max(record => record.Date);

TimeSpan examples to calculate datetime difference - http://www.dotnetperls.com/timespan[^].

Apps - Color Analyzer | Arctic | XKCD | Sound Meter | Speed Dial

BillWoodruff6-Nov-13 0:37

BillWoodruff

6-Nov-13 0:37

Try this:

List<TimeSpan> dateIntervals = endDates.Select((eDate, ndx) => eDate - startDates[ndx]).ToList();

The Linq 'Select function overload that supplies an index is available as of .NET FrameWork 3.5.

Google CEO, Erich Schmidt: "I keep asking for a product called Serendipity. This product would have access to everything ever written or recorded, know everything the user ever worked on and saved to his or her personal hard drive, and know a whole lot about the user's tastes, friends and predilections." 2004, USA Today interview

Richard MacCutchan6-Nov-13 0:38

6-Nov-13 0:38

Try this:

for (int i = start.Length - 2; i > -1; --i)
{
    if (start[i+1] >= start[i] && start[i+1] <= end[i])
    {
        start[i + 1] = end[i];
    }
}
for (int i = 0; i < start.Length; ++i)
{
    timespan = end[i] - start[i];
    timeDifference += timespan.Days;
}

Veni, vidi, abiit domum

Member 1038120911-Nov-13 8:38

11-Nov-13 8:38

yes but it is not remove overlap for the next time i mean for this one it is good |-----------|
|-------------|
but here |--------1-----|
}-----------2---------|
}==========3==========} here it should not add 3 because value od 3 contains in 2 one

Richard MacCutchan11-Nov-13 22:28

radTreeListView - allow selection of items only at the same hierarchy

11-Nov-13 22:28

I tried my suggested code with your original data and it produced the correct answer.

Veni, vidi, abiit domum

devenv.exe5-Nov-13 19:57

devenv.exe

5-Nov-13 19:57

how can make the telerik radTreeListView only allow selection of items under the same rootItem/ParentItem?

UK
  -london
      -london 1
      -london --
      -london 100
  -Newcastle
      -Newcastle 1
      -Newcastle 2
      -Newcastle 3
  -liverpool
USA
  -New york
  -califonia
China
  -one
  -two

From above sample menu of a radTreeListView, user should be allowed to select only

UK, USA or China. OR London, Newcastle, Liverpool, OR Newcastle 1, Newcastle 2, Newcastle 3 BUT NOT Newcastle 1, London 1, UK ALSO NOT UK, Newcastle, Newcastle 1.

User should only select things/items at the same hierarchy. Basically, they should not select a parent and a child, THEY either select from parents or children or sub-children.

This is the control am using : http://www.telerik.com/help/silverlight/radtreelistview-overview.html

"Coming soon"

Re: radTreeListView - allow selection of items only at the same hierarchy

Mycroft Holmes5-Nov-13 20:23

Mycroft Holmes

5-Nov-13 20:23

Presumably you have a TreeNode object that you stuff your objects into (you are displaying Country and City here). I would put a Nodelevel property on the TreeNode object and manage your SelectedItems collection using that property.

We use the HeirarchyID concept in our TreeNode that automatically knows it's level.

Take a read through some of Mr Smiths articles[^] I have quite a few bits of his code in my apps.

Never underestimate the power of human stupidity
RAH

Re: radTreeListView - allow selection of items only at the same hierarchy

BillWoodruff5-Nov-13 21:56

BillWoodruff

5-Nov-13 21:56

Hi Mycroft,

I use a TreeView (the excellent IntegralUI TreeView from Lidor Systems) that also has a "Level" property for every Node; it's very useful.

However, in this case, knowing the Level would not be adequate to determine which are "acceptable" selected nodes: "-california" and "-liverpool," for example, are at the same level; while that may have some "historic poetic truth" in terms of the music scene Smile | :)

... that would not work for the OP.

Bill

Re: radTreeListView - allow selection of items only at the same hierarchy

Mycroft Holmes5-Nov-13 23:11

Mycroft Holmes

5-Nov-13 23:11

Ok now I see where you are coming from, however I would bet the OP (coming from Uganda) may have considered california a city rather than a state. Certainly I did not pick it up until you pointed it out Blush | :O

Never underestimate the power of human stupidity
RAH

Re: radTreeListView - allow selection of items only at the same hierarchy

BillWoodruff5-Nov-13 20:51

BillWoodruff

5-Nov-13 20:51

I don't use the Telerik Treeview (I use one from Lidor Systems), so I don't know exactly what special features ... compared to any other Control ... it offers, or the exact syntax of Events it exposes, but this is pretty simple to do.

The Microsoft TreeView does not, of course, offer multiple selection, but the following code for the MS TreeView will demonstrate a general solution:

TreeNode firstSelectedNode;
TreeNode firstSelectedNodeParent;

private void treeView1_BeforeSelect(object sender, TreeViewCancelEventArgs e)
{
    if (firstSelectedNode == null)
    {
        firstSelectedNode = e.Node;
        firstSelectedNodeParent = firstSelectedNode.Parent;
    }
    else
    {
        if (e.Node.Parent != firstSelectedNodeParent) e.Cancel = true;
    }
}

This code will confine selection to the sibling nodes of the first selected TreeNode. Obviously, in real-world use, you will need to reset the variable 'firstSelectedNode to null after you have "handled" the current selection.

datetime overlap there result should be 2192 not 2923

Member 103812095-Nov-13 1:11

Re: datetime overlap there result should be 2192 not 2923

5-Nov-13 1:11

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;

namespace WindowsFormsApplication7
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }

        DateTime[] start = new DateTime[] { new DateTime(2000, 1, 1), new DateTime(2004, 1, 1),  
                                         new DateTime(2004, 1, 1), new DateTime(2008, 1, 1) };
        DateTime[] end   = new DateTime[] { new DateTime(2002, 1, 1), new DateTime(2006, 1, 1),           
                                            new DateTime(2006, 1, 1), new DateTime(2010, 1, 1) };

        int timeDifference = 0;
        TimeSpan timespan;

     
        private void button1_Click(object sender, EventArgs e)
        {
            for (int i=0; i<end.Length-2; i++)
            {
    if (end[i] < end[i + 1] && start[i] <start[i +="" 1]="" &&="" start[i="" 1]<="end[i])
" {
="" timespan="(end[i]" -="" start[i])="" (end[i="" end[i]);
="" }

="" if="" (end[i]="">= end[i + 1] && start[i] <= start[i + 1])          
                {
                    timespan = (end[i] - start[i]);
                }
    if (end[i] > end[i + 1] && start[i] > start[i + 1] && start[i] <= end[i + 1])         
                {
                    timespan = (end[i] - start[i]) + (end[i + 1] - end[i]);
                }
           
    if (end[i] <= end[i + 1] && start[i] >= start[i + 1])
                {        timespan = (end[i + 1] - start[i + 1]);
                }

                timeDifference = timespan.Days + timeDifference;

            }
                MessageBox.Show(timeDifference.ToString());

            }

        }
    }

Richard MacCutchan5-Nov-13 1:19

Re: datetime overlap there result should be 2192 not 2923

5-Nov-13 1:19

What is the question?

Veni, vidi, abiit domum

Member 103812095-Nov-13 1:28

Re: datetime overlap there result should be 2192 not 2923

5-Nov-13 1:28

i should find the length of days in the array but in my code |--- Date 1 ---|
|--- Date 2 ---| dont calculate in right way

|--- Date 1 ---|
| --- Date 2 --- |

| --- Date 1 --- |
| --- Date 2 ---- |

| -------- Date 1 -------- |
| --- Date 2 --- |

| --- Date 1 --- |
| -------- Date 2 -------- |

|--- Date 1 ---|
|--- Date 2 ---|

| --- Date 2 --- |
| --- Date 1 ----|

| --- Date 1 --- |
| -------- Date 2 -------- |

| --- Date 1 --- |
| --- Date 2 --- |

Member 103812095-Nov-13 1:30

Re: datetime overlap there result should be 2192 not 2923

5-Nov-13 1:30

i should find the length of days in the array but in my code |--- Date 1 ---|
|--- Date 2 ---| dont calculate in right way

Richard MacCutchan5-Nov-13 1:37

Re: datetime overlap there result should be 2192 not 2923

5-Nov-13 1:37

I have no idea what all these pictures are supposed to mean, please try explaining your problem in better detail.

Veni, vidi, abiit domum

Member 103812095-Nov-13 1:45

Re: datetime overlap there result should be 2192 not 2923

5-Nov-13 1:45

ok i will explain in this way you worked from
DateTime[] start = new DateTime[] { new DateTime(2000, 1, 1), new DateTime(2004, 1, 1), new DateTime(2004, 1, 1), new DateTime(2008, 1, 1) };

to
DateTime[] end = new DateTime[] { new DateTime(2002, 1, 1), new DateTime(2006, 1, 1), new DateTime(2006, 1, 1), new DateTime(2010, 1, 1) };

and find how long you worked from 200years to 2010? as you see here i have overlap datetime and when i calculate in my program the lenght of working days i found it is not true

did you understand now?

Richard MacCutchan5-Nov-13 1:56

Re: datetime overlap there result should be 2192 not 2923

5-Nov-13 1:56

if (end[i] < end[i + 1] && start[i] = end[i + 1] && start[i] <= start[i + 1])

should be

if (end[i] < end[i + 1] && start[i] == end[i + 1] && start[i] <= start[i + 1])

Veni, vidi, abiit domum

Member 103812095-Nov-13 2:43