Re: Question about input iterator. - ATL / WTL / STL Discussion Boards

naradaji6-Feb-03 5:25

6-Feb-03 5:25

Hi,
I'm writing a program that is supposed to detect the configuration of outlook express (installed in the machine where the application is run). When I say configuration I mean the pop and smtp servers, at least. Now, reading the registry I can get that info, but the registry keys vary according to the user (right?), because different user profiles (windows 2000) can have different outllo express configurations. What I really need is to detect the configuration for the user that is executing the application.
For Example, my reg key for this is in:
HKEY_USERS\S-1-5-21-3046562155-3082545408-3971354878-2339\Software\Microsoft\Internet Account Manager\Accounts\00000001

Now, what is this number: "S-1-5-21-3046562155-3082545408-3971354878-2339"? I don't think it's going to be the same in different machines, therefore I don't seem to be able to detect what I want using the registry.

Any ideas?

Thanks!

-- narada

Re: outlook express configuration

Michael Dunn6-Feb-03 9:43

Michael Dunn

6-Feb-03 9:43

That's what HKEY_CURRENT_USER is for, it's mapped to the current user's key in HKEY_USERS.

--Mike--
The Internet is a place where absolutely nothing happens.
-- Strong Bad

1ClickPicGrabber - Grab & organize pictures from your favorite web pages, with 1 click!
My really out-of-date homepage
Sonork-100.19012 Acid_Helm

Re: outlook express configuration

naradaji6-Feb-03 21:13

naradaji

6-Feb-03 21:13

Sorry, this is wrong forum, right? Anyway, I appreciate your answer, still I don't know if the key is going to be the same in another machine, so how could read that programmatically?

Thanks anyway,

-- narada

Re: outlook express configuration

Michael Dunn8-Feb-03 19:09

Michael Dunn

8-Feb-03 19:09

From your first post (with my emphasis):

What I really need is to detect the configuration for the user that is executing the application.

Again, that is what HKEY_CURRENT_USER is for. The system automatically maps that hive to the key under HKEY_USERS that corresponds to the user making the call. You never have to access HKEY_USERS at all.

--Mike--
The Internet is a place where absolutely nothing happens.
-- Strong Bad

1ClickPicGrabber - Grab & organize pictures from your favorite web pages, with 1 click!
My really out-of-date homepage
Sonork-100.19012 Acid_Helm

Re: outlook express configuration

naradaji9-Feb-03 21:22

naradaji

9-Feb-03 21:22

Yes, I see. Sorry about my confusion!

Thanks so much, I did it this way and its working fine!

-- narada

Problems connecting DWebBrowserEvents2

Xavyer5-Feb-03 22:43

Xavyer

5-Feb-03 22:43

I try to catch events like this

class ATL_NO_VTABLE CTBar : <br />
    public CComObjectRootEx<CComSingleThreadModel>,<br />
    public CComCoClass<CTBar, &CLSID_TBar>,<br />
    public IDispatchImpl<ITBar, &IID_ITBar, &LIBID_ATLToolBarLib, /*wMajor =*/ 1, /*wMinor =*/ 0>,<br />
    public IDispEventImpl<1,CTBar,&__uuidof(DWebBrowserEvents2),&LIBID_SHDocVw>,<br />
    public IObjectWithSiteImpl<CTBar><br />
    public ......<br />
{<br />
<br />
BEGIN_SINK_MAP(CTBar)<br />
    SINK_ENTRY_EX(1,__uuidof(DWebBrowserEvents2),DISPID_NEWWINDOW2,OnNewWindow)<br />
END_SINK_MAP()<br />
.....<br />
<br />
IUnknown* m_pSinkUnk;<br />
IWebBrowser2* m_pWebBrowser2;<br />
LPDWORD cookie;<br />
STDMETHOD (SetSite) (IUnknown*);<br />
STDMETHOD (OnNewWindow) (IDispatch** &ppDisp,VARIANT_BOOL* &Cancel);<br />
.....<br />
};<br />
<br />
<br />
STDMETHODIMP CTBar::SetSite(IUnknown* punkSite)<br />
{<br />
   .....<br />
   IServiceProviderPtr pServProv(punkSite);<br />
   pServProv->QueryService(SID_SWebBrowserApp, IID_IWebBrowser2,(void**)&m_pWebBrowser2);<br />
   this->QueryInterface (IID_IUnknown, (LPVOID*)&m_pSinkUnk);<br />
   AtlAdvise(m_pWebBrowser2,m_pSinkUnk,__uuidof(DWebBrowserEvents2),cookie);<br />
   .....<br />
}

but i can't. Where's the problem in this code?

Question about input iterator.

George25-Feb-03 21:34

George2

5-Feb-03 21:34

Hi, everyone!

I am puzzled at some words taken from my STL
tutorial. Here are the words at which I am puzzled.

--------
Note: For two input iterators a and b, a == b implies *a == *b.
For istream iterators, this condition doesn't hold.
--------

My opinion is,

--------
Two istream iterators are equal if :

both are end-of-stream iterators and this can no longer be read, or
both can read and use the same stream

from "The C++ Standard Library" by Josuttis.
--------

So I think whether a and b are equal has nothing to do
with *a and *b. Another question, "input iterators" is
different from "istream iterators"? I think they are the same.

Am I correct? Who can give me an explanation?
Better with an example. Smile | :)

Thanks in advance,
George

Re: Question about input iterator.

Joaquín M López Muñoz5-Feb-03 22:38

Joaquín M López Muñoz

5-Feb-03 22:38

Note: For two input iterators a and b, a == b implies *a == *b.

This is just false. The only requisite about == for input iterators is that it should be an equivalence relation.

both are end-of-stream iterators and this can no longer be read, or
both can read and use the same stream.

This is absolutely right.

Another question, "input iterators" is different from "istream iterators"?

No, an istream_iterator is an input iterator, but an input iterator is not necessarily an istream_iterator (for instance, a pointer is an input iterator).

Joaquín M López Muñoz
Telefónica, Investigación y Desarrollo

Re: Question about input iterator.

George26-Feb-03 0:03

George2

6-Feb-03 0:03

Hi, Joaquín buddies!

As you said,

--------
This is just false. The only requisite about == for input iterators is that it should be an equivalence relation.
--------

Do you mean that what tutorial is saying is not correct?
What puzzled me most is the meaning of "equivalence relation". What do you mean "equivalence relation"?

Because I think I can give you an example when a == b, while the same time *a != *b.

Thanks in advance,
George

Re: Question about input iterator.

Joaquín M López Muñoz6-Feb-03 7:01

Joaquín M López Muñoz

6-Feb-03 7:01

Of course you can give that example Smile | :)

An equivalence relation, if you remember from your Math classes, is just a relation being reflexive, symmetric and transitive. With regard to our particular problem, this means that

i==i always evaluates to true,
if i==j then j==i,
if i==j and j==k then i==k.

As you can see, expressions of the type *i are not involved in this definition.

Joaquín M López Muñoz
Telefónica, Investigación y Desarrollo

Re: Question about input iterator.

George26-Feb-03 15:22

George2

6-Feb-03 15:22

Hi, Joaquín buddies!

I think you mis-understand my question. My
origin question is, the tutorial said,

--------
if( (i == j) && (i and j are both input iterators) )
then
(*i == *j)
endif
--------

My question is not that I do not understand what means
"equivalence relation". Smile | :)

What is your opinion about the tutorial? Is it correct?

Thanks in advance,
George

Re: Question about input iterator.

Joaquín M López Muñoz6-Feb-03 19:48

Joaquín M López Muñoz

6-Feb-03 19:48

--------
if( (i == j) && (i and j are both input iterators) )
then
(*i == *j)
endif
--------

This is false. The tutorial is wrong. The only requisite about == for input iterators in general is the equivalence relation stuff, as you pointed out before.

Joaquín M López Muñoz
Telefónica, Investigación y Desarrollo

Re: Question about input iterator.

George27-Feb-03 2:52

George2

7-Feb-03 2:52

Thanks, Joaquín buddies!

George

Tab Control quick hiding

Leo Smith5-Feb-03 11:59

Leo Smith

5-Feb-03 11:59

I have what is probably a simple question, but I am stuck and need help. I am trying to create an Options dialog box for an app. I am using WTL to create the app. I have added the tab control, but I need a quick way to select the controls for each page. In VB I would create a group control and add the controls to the group, then show and hide the group as needed. I can't seem to make this work in WTL (probably doing something wrong with adding the controls to the group). I also, think that I might be able to use a dialog resource like a property sheet, but I am at a loss at how to get this added to the Tab Control. What is the best way to proceed?

Thanks for any help you can give.

Leo T. Smith

Re: Tab Control quick hiding

Ben Burnett7-Feb-03 13:37

Ben Burnett

7-Feb-03 13:37

This is probably not the answer you’re looking for but, as far as I know, the way groups work in VB is just that, a VB thing. There is no parallel functionality in the rest of windows programming. The closest you could come would be to store a list of all the controls in the 'group' you want to modify and simply hide/shoe them when necessary.

Besides, the thing you probably want to be doing, as you mentioned, is create a property sheet. There are some samples of this on this site:

Using DDX and DDV with WTL[^]

It does concern itself with a more advance topic, but the code for using both property sheets and property pages is in there.

cheers,
-B

Question about output iterator.

George25-Feb-03 3:16

George2

5-Feb-03 3:16

Hi, everyone!

Here are the sentences taken from my STL tutorial,

--------
Any value of an output iterator may have at most one active copy at any given time.

// i and j are output iterators
// a and b are values written to a iterator position
i = j;
*i++ = a;
*j = b;

is not a valid code sequence.
--------

I write a piece of code by myself tried the codes and
run it. I find it runs OK! So I doubted what is the tutorial
talking about. Can anyone explain it to me? (What means "at most one active copy at any given time" ?)

Here is my sample,

--------
#include <iterator>
#include <fstream>
#include <iostream>

using namespace std;

void main()
{
ofstream ofile ("c:\\file1.txt");
ostream_iterator<int> i (ofile);
ostream_iterator<int> j (ofile);
// i and j are output iterators
// a and b are values written to a iterator position
*i++ = 1;
*j = 2;
}
--------

Thanks in advance,
George

Re: Question about output iterator.

Joaquín M López Muñoz5-Feb-03 8:01

Joaquín M López Muñoz

5-Feb-03 8:01

The semantics of output iterators are simple, and it reduces to the following rule: a given position has to be accessed once and only once. Let us examine why the following pieces of code are incorrect:

*i=5;
++i;
++i;

This is incorrect as you're "skipping" a value.

*i=5;
*i=6;

Wrong, as you're assigning to the same position twice.

j=i;
*i++=1;
*j=2;

Wrong, for the same reason as before.

Joaquín M López Muñoz
Telefónica, Investigación y Desarrollo

Re: Question about output iterator.

George25-Feb-03 19:58

George2

5-Feb-03 19:58

Hi, Joaquín buddies!

In the last sample,

--------
j=i;
*i++=1;
*j=2;
--------

i and j are referencing to the same stream but
they are different iterators. I still doubted
why they are assigning to the same position twice?
Since they are different iterators and I think it
is like two pointers pointing to the same memory.

Can you give me an explanation?

Thanks in advance,
George

Re: Question about output iterator.

Joaquín M López Muñoz5-Feb-03 22:40

Joaquín M López Muñoz

5-Feb-03 22:40

No, wait. I've reread the standard and now I think the above piece of code is correct. Sorry.

Joaquín M López Muñoz
Telefónica, Investigación y Desarrollo

Re: Question about output iterator.

George25-Feb-03 23:53

George2

5-Feb-03 23:53

Hi, Joaquín buddies!

Do you mean that the tutorial is
not correct? Since the tutorial says
that the piece of code is not correct.

Thanks in advance,
George

Re: Question about output iterator.

George27-Feb-03 4:54

George2

7-Feb-03 4:54

Hi, Joaquín buddies!

Have you found the answer?

Thanks in advance,
George

Question about input iterator on the same input stream.

George24-Feb-03 19:26

George2

4-Feb-03 19:26

Hi, everyone!

Here is a simple STL program. It uses two input iterators
to use on the same input file. I do not understand why the
output is looking like this.

Here are the source codes,

--------
#include <iterator>
#include <fstream>
#include <iostream>

using namespace std;

void main()
{
// c:\\file1.txt: 0 1 2 3
ifstream ifile ("c:\\file1.txt");

istream_iterator<int> r (ifile);
istream_iterator<int> s (ifile);

(r==s) ? cout << "equal" : cout << "not equal";
cout << endl;

++r;
++s;

cout << *r << endl;
cout << *s << endl;

(r==s) ? cout << "equal" : cout << "not equal";
cout << endl;
}
--------

Here are the outputs,

--------
equal
2
3
equal
--------

Thanks in advance,
George

Re: Question about input iterator on the same input stream.

Joaquín M López Muñoz4-Feb-03 20:14

Joaquín M López Muñoz

4-Feb-03 20:14

You're twisting the semantics of istream_iterators: You only can do the following with such an iterator:

Check for the end of stream with the expression it==istream_iterator<int>().

retrieve a value from the associated istream with an expression of the form x=*it;.

Increment the iterator with ++it or it++.Moreover, after retrieving a value, you must increment the iterator previous to further retrievals. That's it, do not assume you can do much else with such iterators. Do no think these iterators are something like pointers to the data contained in the file, because they are not, hence the odd results when testing r and s for equality. istream_iterator is designed as a convenient adaptor to take advantage of generic algoritms, as such its functionality is strictly limitied to what these algorithms require.

Joaquín M López Muñoz
Telefónica, Investigación y Desarrollo

Re: Question about input iterator on the same input stream.

George25-Feb-03 1:17

George2

5-Feb-03 1:17

Thanks, Joaquín buddies!

Such piece of codes are taken from a turorial
and it is a concept-proof sample.

It really doubted me. So, if you can explain it
to me, I will be really thankful. I am a newbie
of STL.

Cheers,
George

Question about copy algorithm of STL.

George24-Feb-03 19:23

George2

4-Feb-03 19:23

Hi, everyone!

Here is a simply STL program deals with copy
algorithm of STL. I do not understand what is the
meaning of the socond parameter of my case, i.e.

--------
istream_iterator<int> ()
--------

What does it mean? Here are the source codes
and related output.

Source codes,

--------
#include <iterator>
#include <fstream>
#include <iostream>

using namespace std;

void main()
{
//0 1 2 3 are in c:\\file1.txt
ifstream ifile ("c:\\file1.txt");

copy (istream_iterator <int> (ifile),
istream_iterator<int> (),
ostream_iterator<int> (cout) );

}
--------

Output,

--------
0123
--------

Thanks in advance,
George

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