Re: How to deserialize this one - C# Discussion Boards

19-Dec-10 10:45

Hello,
I'll be glad to get some help with this XML Schema

<?xml version="1.0" encoding="utf-8"?>
<ArrayOfElems xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <Element Attribute1="1">
	<ChildElement Attribute2="1">
		<elem1> blablabla </elem1>
		<elem2> blablabla </elem2>
		<elem3> blablabla </elem3>
		<elem4> blablabla </elem4>
	</ChildElement>
	<ChildElement Attribute2="2">
		<elem1> blablabla </elem1>
		<elem2> blablabla </elem2>
		<elem3> blablabla </elem3>
		<elem4> blablabla </elem4>
	</ChildElement>
  </Element>
  
  <Element Attribute1="2">
	<ChildElement Attribute2="1">
		<elem1> blablabla </elem1>
		<elem2> blablabla </elem2>
		<elem3> blablabla </elem3>
		<elem4> blablabla </elem4>
	</ChildElement>
	<ChildElement Attribute2="2">
		<elem1> blablabla </elem1>
		<elem2> blablabla </elem2>
		<elem3> blablabla </elem3>
		<elem4> blablabla </elem4>
	</ChildElement>
  </Element>
  .
  .
  .
  .
  <Element Attribute1="n">
	<ChildElement Attribute2="1">
		<elem1> blablabla </elem1>
		<elem2> blablabla </elem2>
		<elem3> blablabla </elem3>
		<elem4> blablabla </elem4>
	</ChildElement>
	<ChildElement Attribute2="2">
		<elem1> blablabla </elem1>
		<elem2> blablabla </elem2>
		<elem3> blablabla </elem3>
		<elem4> blablabla </elem4>
	</ChildElement>
  </Element>
</ArrayOfElems>

i have here two different collection... how to handle them ?

Thanks

RaviRanjanKr19-Dec-10 17:43

RaviRanjanKr

19-Dec-10 17:43

It would be better to post this question in the XML/XSL forum.

igalep13219-Dec-10 19:10

19-Dec-10 19:10

ok, i'll try there

thanks

igalep13220-Dec-10 11:00

20-Dec-10 11:00

guys no1 can help here ?

maybe this one will be easier.
i need to serialize this list

Class A
{
        Int _a,_b,_c;

        InsertData(a,b,c);
        { _a=a.._c=c;}
}

Class B
{
        List of A _l
        
        Public B()
        {
                Loop 1 to 3
               {
                       A a = new A();
                        _l.add(a.insertData(i+10,i+20,i+30);
               }
        }
}

Class Main
{
        List of B _l;
        
        Loop 1 to 3
        _l.add(new Class B());
}

but got some trouble to serialize list in list

Luc Pattyn20-Dec-10 11:35

Re: How to deserialize this one [modified]

20-Dec-10 11:35

I don't understand your code.

I have a little article on XML serialization here[^].

I did a little extra experiment, and it worked right from the start. Here it goes.

the inner list:

public class StringList : List<string> {
    public StringList() { }
    public StringList(int count) {
        for (int i=0; i<count; i++) this.Add("item"+i);
    }
}

the serializer:

List<StringList> list=new List<StringList>();
list.Add(new StringList(2));
list.Add(new StringList(5));
list.Add(new StringList(3));
xSer=new XmlSerializer(typeof(List<StringList>));
xSer.Serialize(sw, list);

the deserializer:

List<StringList> list=(List<StringList>)xSer.Deserialize(sr);
foreach (StringList sl in list) {
    log("***");
    foreach (string s in sl) log(s);
}

Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles] Nil Volentibus Arduum

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igalep13220-Dec-10 11:42

20-Dec-10 11:42

first, thanks for the answer !!
second, your second example seems to be what i need, but it a bit different...
instead of declaring 2 aggregated object of Class Mini inside Class Combo, i've a list of Mini inside Combo...
and also i've a list of Combo... (and here i fail...)

third, why do you use private ctor in this example ? (for both classes)

modified on Monday, December 20, 2010 5:49 PM

Luc Pattyn20-Dec-10 12:03

20-Dec-10 12:03

igalep132 wrote:
why do you use private ctor

The access attributes aren't really relevant. Some of the default constructors are not used explicitly by my code, however they are needed by the serialization; making them private suits this, as serialization is based on reflection, it can access anything it finds!

Smile | :)

Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles] Nil Volentibus Arduum

Please use <PRE> tags for code snippets, they preserve indentation, improve readability, and make me actually look at the code.

igalep13220-Dec-10 12:41

20-Dec-10 12:41

I see...

Your examples are helped me a lot Smile | :)

small thing, how can i add an attributes to combo class ?
in order to see it like

<Combo num ="1">...</Combo> 
<Combo num ="2">...</Combo>

Thanks again

Luc Pattyn20-Dec-10 12:51

20-Dec-10 12:51

I don't know. Are the ComboBox properties insufficient? they have Name, Tag, etc.

Smile | :)

Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles] Nil Volentibus Arduum

Please use <PRE> tags for code snippets, they preserve indentation, improve readability, and make me actually look at the code.

igalep13220-Dec-10 12:54

20-Dec-10 12:54

you didn't understand me correctly...

Combo is your example (second example in your article)

Luc Pattyn20-Dec-10 13:06

20-Dec-10 13:06

I have no experience with XML attributes. You're on your own. Try something like:

[XmlAttribute(DataType="int", AttributeName="myInteger")]

Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles] Nil Volentibus Arduum

Please use <PRE> tags for code snippets, they preserve indentation, improve readability, and make me actually look at the code.

igalep13227-Dec-10 9:23