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Does VSS come with a manual?
I doubt any version control system has that feature. Old versions should be stored as DIFFs, so they don't take up much room. You should break your code into small pieces. You should not commit a change unless you are fairly sure it is correct (and nothing that you know to be bad) -- whatever is in the repository should compile cleanly, etc.
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Hi,
how do I disable "close box" on child forms, but leave it functional for "MDI form". I tried:
private void ChildForm_FormClosing(object sender, FormClosingEventArgs e)
{
e.Cancel = true;
}
it works for child forms, but it also prevents me from closing apllication
(with X button) from main MDI form.
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The code you have shown is correct. What you need to do is: When the user closes your main form, you must notify the child forms that they are allowed to close.
Your code could look something like this;
private bool m_bAllowClose = false;
private AllowClose(bool bAllow)
{
m_bAllowClose = bAllow;
}
private void ChildForm_FormClosing(object sender, FormClosingEventArgs e)
{
if(!m_bAllowClose)
e.Cancel = true;
}
From your main form you would need to call "AllowClose(true);" for all your child forms
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On which event from main MDI form should I call AllowClose()?
If I call it from:
private void MDIMainForm_FormClosed(object sender, FormClosedEventArgs e)
OR
private void MDIMainForm_FormClosing(object sender, FormClosedEventArgs e)
ChildForm_FormClosing() is validated first and it does not close child form.
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Ok,if this is not working for you then you can try using the following code in your childs:
private void ChildForm_FormClosing(object sender, FormClosingEventArgs e)
{
if(e.CloseReason != CloseReason.MdiFormClosing)
e.Cancel = true;
}
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Or:
e.Cancel = e.CloseReason != CloseReason.MdiFormClosing;
I do never use an if for just setting a bool value.
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You might also want to look at Disable the Close box on a form[^] which might help with the visible "X" button - I haven;t tried it with MDI children, but it should still work.
Real men don't use instructions. They are only the manufacturers opinion on how to put the thing together.
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I want to design a pop up appication , where i want to display it near a system tray, how to get the height and width of the screen so that i have to exactly display in the same location and it should be adjustable to all monitors resolutions(i mean multiple systems).
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You REALLY need to learn to use the research tools, this problem has been solved [^]many time before.
Never underestimate the power of human stupidity
RAH
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Thank.. i solved it and how to set a .bmp skin of forms and perform actions (what iam saying here is i want to add skin for a windows form), please let me know... thanks in advance..
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hello, I am able to get all the colors of an image in RGB format is there anway i can do it to get the main colors of the image?
for example:
http://i55.tinypic.com/2mq0vgk.jpg[^]
Main colors detected will be green and red
needing help!
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So, if you are able to get all the colors of the image, you could easily sum up their occurence. The one color with the highest sum is then your main color. You might also want to threshold the colors a bit so that you evaluate {255,0,0} and e.g. {255,15,15} as being Red and {0,255,0} as well as e.g. {47,255,47} as being green.
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i tried averaging the colors however it only gave me the color red but not red and green in the example of the image given above.
THe range for RGB is very wide meaning i have to use if statements?
how to you sum up occurence?
modified on Tuesday, November 23, 2010 1:34 AM
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While JF2015 suggest to predefine colors and their RGB ranges, I think the main color(s) could be anywhere in the RGB range - hence predefined ranges do not help.
Beyond counting the occurrences of every color, I would add a weighted amount for pixels whose color is "similar" to the color in question.
My suggestion for getting the main colors is hence a very slow one - you will need a specialist for fast algorithms to get it optimized!
- define how far the second (third etc.) color must be away from the main color
- create an array of doubles for all RGB values (oh yes, some 16 million)....
- iterate through all the pixels of the image:
- - add 1.0 at the array position of the pixel's color
- - for the array positions of "similar" colors, add the weighted amount, e.g. 1.0/(1.0+delta R)/(1.0+delta G)/(1.0+delta B) (ehm, that's another nested loop(s)...)
- now iterate through your array of RGB values, and select the highest value (you may sort the array): this is the main color.
- take the RGB value with the next highest value
- - if it is "close" to the main color, repeat the step above
- - otherwise, it is the second color.
- with third (forth etc) color, do as outlined for the second color, but do not forget that it must be sufficiently away from all previously selected colors.
When you test this "naive" algorithm with your example image, bear in mind that it is not at all optimized, and surely terribly slow! Better test with a very small image first.
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hi all
please can someone tell me how to hack the password of yahoo ID?
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inayathussaintoori wrote: please can someone tell me how to hack the password of yahoo ID?
sure, if you post your e-mail address, all 7+ million of us will send you password candidates for you to try.
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And here I thought you were just another troll, you know account created less than 1 month, 1st post and you ask a question designed to irritate the development community. But no you've been here some months so what does that make you - ????
If it is your account then reset it, if not your an idiot.
Never underestimate the power of human stupidity
RAH
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That's a very dangerous question. It made me laugh so much that I almost fell from my chair!
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I had to read that a couple times to make sure I wasn't missing part of the question. Truly amusing that some people assume that all developers are a bunch of hackers.
I wasn't, now I am, then I won't be anymore.
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Nobody is going to tell you how to do this you little scriptkiddy. Now run along and go play with your marbles.
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Your own password? 
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
[My articles]
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Errr, send me your yahoo ID and password and I'll see what I can do... 
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