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On using mouse move event it calls every time when mouse move on the picture box. so list rectangle count gets increased. for this i used mouse click event.
When list rectangle added in Mouse down event, it's only get the values for height and width of the rectangle (if use (0,0,e.X,e.Y))and also rectangle always starts from top left corner (not able to start the rectangle point where user likes) and it's gets only X and Y values (if use(e.X, e.Y,0,0))
to over come this I used the list rectangle in the mouse click event, so I get all values.
List<Rectangle> rectangles = new List<Rectangle>();
private void pictureBox1_MouseDown(object sender, MouseEventArgs e)
{
if (stayToolStripMenuItem.Checked == true)
{
if (mybitmap == null)
{
mybitmap = new Bitmap(sz.Width, sz.Height);
}
rect = new Rectangle(e.X, e.Y, 0, 0);
this.Invalidate();
}
}
private void pictureBox1_Paint(object sender, PaintEventArgs e)
{
if (stayToolStripMenuItem.Checked == true)
{
button1.Visible = true;
button2.Visible = true;
if (mybitmap == null)
{
return;
}
using (g = Graphics.FromImage(mybitmap))
{
using (Pen pen = new Pen(Color.Red, 2))
{
e.Graphics.DrawRectangle(pen, rect);
label1.Top = rect.Top; label1.Left = rect.Left; label1.Width = rect.Width;
label1.Height = rect.Height;
if (label1.TextAlign == ContentAlignment.TopLeft)
{
e.Graphics.DrawString(label1.Text, label1.Font, new SolidBrush(label1.ForeColor), rect);
g.DrawString(label1.Text, label1.Font, new SolidBrush(label1.ForeColor), rect);
g.DrawRectangle(pen, rect);
}
}
}
private void pictureBox1_MouseClick(object sender, MouseEventArgs e)
{
if (e.Button == MouseButtons.Left)
{
rect = new Rectangle(rect.Left, rect.Top, e.X - rect.Left, e.Y - rect.Top);
rectangles.Add(rect);
pictureBox1.Invalidate();
f = 0;
}
}
thanks Griff for advising to use list rectangles.
What ever rectangle I draw get saved in the list rectangles and get saved when i saved the work (could see all the drawn rectangles when i opened the saved file).
Now the problem is, when I draw a new rectangle the previous one get disappeared (on run time. However this added in list rectangle).
How to display all the rectangles drawn on run time, so user can know how many rectangles drawn and where.
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Well done - it looks better already!
I still wouldn't draw onto your bitmap in the Paint event - don't forget the bitmap is persistent - all changes you make are kept (unlike painting on the provided graphics context in the Paint event). For the moment, just comment it out and ignore it.
You are handling the new rectangle creation a little oddly - MouseDown and MouseClick are not the events I would pick! The normal way to do it is:
MouseDown: Save the current location - you do this - but in a Point rather than a rectangle. Set a Bool to true to show you are creating a new rectangle.
MouseUp: If creating new rectangle, make new rectangle using saved point, and cancel creating mode. Add the new rectangle to the list.
You can also add MouseMove: If creating, save the current position as a new, temporary rectangle. Invalidate.
Then in Paint: if creating, paint an "elastic band" for the temporary rectangle.
I have given some sample code for this below (it is not compiled, so I can't say if it works!)
private void StoreLayoutPanel_MouseDown(object sender, MouseEventArgs e)
{
mouseDown = true;
mouseDownAt = new Point(e.X, e.Y);
Invalidate();
}
private void StoreLayoutPanel_MouseUp(object sender, MouseEventArgs e)
{
if (mouseDown)
{
Rectangle rect = MakeRect(mouseDownAt.X, mouseDownAt.Y, e.X, e.Y);
rectangles.Add(rect);
Invalidate();
}
mouseDown = false;
}
private void StoreLayoutPanel_MouseMove(object sender, MouseEventArgs e)
{
if (mouseDown)
{
mouseRect = MakeRect(mouseDownAt.X, e.X, mouseDownAt.Y, e.Y);
Invalidate();
}
}
private void StoreLayoutPanel_Paint(object sender, PaintEventArgs e)
{
Pen pen = new Pen(Color.Black);
foreach (Rectangle r in rectangles)
{
e.Graphics.DrawRectangle(pen, r);
}
if (mouseDown)
{
Pen p = new Pen(Color.Gray);
p.DashStyle = System.Drawing.Drawing2D.DashStyle.Dash;
e.Graphics.DrawRectangle(p, mouseRect);
}
}
Here are a couple of methods you may find usefull:
private Rectangle MakeRect(Point p1, Point p2)
{
return MakeRect(p1.X, p2.X, p1.Y, p2.Y);
}
private Rectangle MakeRect(int X1, int X2, int Y1, int Y2)
{
int XL = Math.Min(X1, X2);
int XR = Math.Max(X1, X2);
int YL = Math.Min(Y1, Y2);
int YR = Math.Max(Y1, Y2);
return new Rectangle(XL, YL, XR - XL, YR - YL);
}
#endregion
Did you know:
That by counting the rings on a tree trunk, you can tell how many other trees it has slept with.
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Final and full code
Image image;
Bitmap mybitmap;
Rectangle rect;
List<Rectangle> rectangles = new List<Rectangle>();
Graphics g;
private void openToolStripMenuItem_Click(object sender, EventArgs e)
{
OpenFD.FileName = "";
OpenFD.Title = "open image";
OpenFD.InitialDirectory = "C";
OpenFD.Filter = "JPEG|*.jpg|Bmp|*.bmp|All Files|*.*.*";
if (OpenFD.ShowDialog() == DialogResult.OK)
{
string file = "";
file = OpenFD.FileName;
image = Image.FromFile(file);
pictureBox1.Image = image;
sz = image.Size;
pictureBox1.Size = sz;
pictureBox1.SizeMode = PictureBoxSizeMode.Zoom;
}
private void pictureBox1_MouseDown(object sender, MouseEventArgs e)
{
if (stayToolStripMenuItem.Checked == true)
{
if (mybitmap == null)
{
mybitmap = new Bitmap(sz.Width, sz.Height);
}
rect = new Rectangle(e.X, e.Y, 0, 0);
this.Invalidate();
}
}
private void pictureBox1_MouseClick(object sender, MouseEventArgs e)
{
if (e.Button == MouseButtons.Left)
{
rect = new Rectangle(rect.Left, rect.Top, e.X - rect.Left, e.Y - rect.Top);
rectangles.Add(rect);
pictureBox1.Invalidate();
}
}
}
private void pictureBox1_Paint(object sender, PaintEventArgs e)
{
if (mybitmap == null)
{
return;
}
using (g = Graphics.FromImage(mybitmap))
{
Pen pen = new Pen(Color.Black);
foreach (Rectangle r in rectangles)
{
e.Graphics.DrawRectangle(pen, r);
label1.Top = rect.Top; label1.Left = rect.Left; label1.Width = rect.Width;
label1.Height = rect.Height;
e.Graphics.DrawString(label1.Text, label1.Font, new SolidBrush(label1.ForeColor), rect);
g.DrawString(label1.Text, label1.Font, new SolidBrush(label1.ForeColor), rect);
g.DrawRectangle(pen, r);
}
}
}
private void saveToolStripMenuItem_Click(object sender, EventArgs e)
{
SaveFileDialog SaveFD1 = new SaveFileDialog();
SaveFD1.FileName = "";
SaveFD1.InitialDirectory = "C";
SaveFD1.Title = "save file Name";
SaveFD1.Filter = "JPG|*.jpg|Bmp|*.bmp";
if (mybitmap != null)
{
if (SaveFD1.ShowDialog() == DialogResult.OK)
{
if (SaveFD1.FileName == "")
return;
else
{
System.IO.Stream filename = (System.IO.FileStream)SaveFD1.OpenFile();
using (g = Graphics.FromImage(pictureBox1.Image))
{
foreach (Rectangle r1 in rectangles)
{
g.DrawImage(mybitmap,0, 0);
}
}
pictureBox1.Image.Save(filename, ImageFormat.Jpeg);
}
}
}
}
private void textBox1_TextChanged(object sender, EventArgs e)
{
label1.Text = textBox1.Text;
}
private void button1_Click(object sender, EventArgs e)
{
fontDialog1.ShowDialog();
label1.Font = fontDialog1.Font;
Invalidate();
}
private void button2_Click(object sender, EventArgs e)
{
colorDialog1.ShowDialog();
label1.ForeColor = colorDialog1.Color;
Invalidate();
}
This code will draw rectangles with the text given in the textbox at the position where the user likes.
Thanks once again Giff......and i worked with code given by u and it also working fine and for time being i need to stick with my code. Don't mistake me.
modified on Thursday, June 3, 2010 3:03 AM
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About bitmap "persistent", I have added the (g.draw)after added the rectangle in the foreach loop (removed (g.draw) from Paint event). Thanks for ur suggestion on this regards.
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The little article[^] I provided a link to earlier still holds all that information.
Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles]
I only read formatted code with indentation, so please use PRE tags for code snippets.
I'm not participating in frackin' Q&A, so if you want my opinion, ask away in a real forum (or on my profile page).
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Hi Luc,
have saw ur animation and it look like it is increasing the size of the Image that loaded (Zoom image functions). but here I need to edit rectangle on run time. please guide me.
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the essence is in the 5-step theory; the zooming image is an example of it.
Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles]
I only read formatted code with indentation, so please use PRE tags for code snippets.
I'm not participating in frackin' Q&A, so if you want my opinion, ask away in a real forum (or on my profile page).
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I have a block of code to respond to text entry in textboxes; this exact code is working in one program, but not another. I've just noticed that in the new program, if I click on the first textbox, the cursor correctly moves there, but I can't type anything. If I then tab to the next textbox it works properly. If I tab through the elements on the page until I return to the first textbox, it then accepts characters as I type them. I think there's a problem in the tab index settings for the page elements, but I can't figure out why.
For all of the items which don't interact with the user I've set the tab index to 0. Those that accept user input are sequentially numbered from 1 to N. I expect that clicking on a textbox should give that item focus and allow it to operate correctly, but that is not what I'm seeing.
Can someone shed some light on this for me?
[EDIT]
Thanks for the helpful info! Oddly, I never found the reason for this peculiar behavior, so I shut it down and walked away for a day. When I fired it up this morning, all was working as it should. I should try this strategy at work sometime! 
[/EDIT]
"A Journey of a Thousand Rest Stops Begins with a Single Movement"
modified on Tuesday, June 1, 2010 11:15 AM
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I do not have a solution to your problem but I would like to point out a couple of things that, from your question, it seems that you might have misunderstood.
Controls that are capable of interaction with the user have a TabStop property in addition to TabIndex and if you want to disallow tabbing into them, then setting their TabStop property to false is the way to go since as far as TabIndex is concerned; C# uses zero based indexing. Therefore setting TabIndex to zero for any control would mean that it would be first in the tab order.
For controls with no user interaction (Labels for example) it does not matter what you do with TabIndex since it is ignored and they do not have a TabStop property, at least not visibly (it is hidden and set to false I believe).
Henry Minute
Do not read medical books! You could die of a misprint. - Mark Twain
Girl: (staring) "Why do you need an icy cucumber?"
“I want to report a fraud. The government is lying to us all.”
Why do programmers often confuse Halloween and Christmas?
Because 31 Oct = 25 Dec.
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Thanks, Henry - that clears up a lot of misconceptions! I'll go fix it and see what happens...
[EDIT]
By the way, labels and group boxes don't have the Tab Stop property - I just checked. Still, I learned a bunch from your answer. Two of my radiobuttons had Tab Stop set to false; I don't know why, since I didn't set them that way, but I changed them to true. The problematic textboxes all have that property set to true, so the trouble must lie elsewhere. It's 2:30AM, so this is probably a good time to shut down VS2008 and see if things behave better tomorrow. That does sometimes happen; things that didn't work suddenly start working after a shutdown and restart. I have no idea why...
[/EDIT]
"A Journey of a Thousand Rest Stops Begins with a Single Movement"
modified on Monday, May 31, 2010 5:26 AM
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Henry Minute wrote: For controls with no user interaction (Labels for example) it does not matter what you do with TabIndex since it is ignored
Not quite: If there is a shortcut key associated with the label, then it will activate the next control in the tab order. E.g. label1.TabIndex = 5, textBox1.TabIndex = 6, with label1.Text = "&Hello". ALT+H will move the input to textBox1.
Did you know:
That by counting the rings on a tree trunk, you can tell how many other trees it has slept with.
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True. I had forgotten that since I rarely use that functionality. 
Henry Minute
Do not read medical books! You could die of a misprint. - Mark Twain
Girl: (staring) "Why do you need an icy cucumber?"
“I want to report a fraud. The government is lying to us all.”
Why do programmers often confuse Halloween and Christmas?
Because 31 Oct = 25 Dec.
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Interesting. So early and I already learned my new thing of the day. Thanks.
Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles]
I only read formatted code with indentation, so please use PRE tags for code snippets.
I'm not participating in frackin' Q&A, so if you want my opinion, ask away in a real forum (or on my profile page).
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how can i declate a array of string without defining the amount of array.
Something like this.
String[] strArray = new String[];
Help plz!
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The short answer is you can't.
You can do String array; and then later say array = new String[10]; but I doubt that's what you're looking for. If you don't know at compile time the size of your collection, go for a List<String>.
Cheers,
Vikram. (Got my troika of CCCs!)
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You cannot.
There are two ways to declare an array.
One is as is mentioned in the first post.
The other is to define your contents within the array right from the start - string []a = new string[] {"1","2","3"};
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so is it possible to convert List to array string I mean (List ==> String[])
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yes.
it is also possible to read the documentation on a very interesting class.
you may discover some advantages of lists over arrays.
Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles]
I only read formatted code with indentation, so please use PRE tags for code snippets.
I'm not participating in frackin' Q&A, so if you want my opinion, ask away in a real forum (or on my profile page).
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As stated on above comments, you cannot. I assume you need what you need because you don't know the number of indices. If so you can workaround it. Use an ArrayList and populate it with your data then you can return it as a string array using its ToArray() method. Check this article.
Best regards,
Anıl Yıldız.
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You may be able to do something like this?
String[] strArray = null;
Int strArrayLength ;
strArray = new string[strArrayLength];
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my connection is:
<add name="AdNetConnectionString" connectionString="Data Source=.\SQLEXPRESS;Initial Catalog=AdNet;Integrated Security=True" providerName="System.Data.SqlClient" />
the error is
Timeout expired. The timeout period elapsed prior to completion of the operation or the server is not responding
and I try to add the proberty
ConnectionTimeout=200
to my connection but this error occurred
The Connection Timeout attribute is not declared.
so please guide me to solve this problem.
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msomar wrote: Timeout expired.
Your query is to slow to complete only for 200 seconds.You would better try to optimize it.
If your query execution time can't be reduced set ConnectionTimeout property to 0, which means no limit.It's preferred to be avoided but sometimes it's not possible.
Life is a stage and we are all actors!
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Can you post a bit more of your code? I suspect that your connection string isn't right, as the server should respond in 200 mS easily. Are you using a local installation of SQL Server Express? If so, it should have a name for the instance, not ".\SQLEXPRESS." It may be that it isn't responding because it's never notified on the request. For instance, on my setup, the SQL Server installation is named "BAAL\SQLEXPRESS" and shortening the name in the connection string never works. The shortcut ".\" may not be valid for this application, so try adding the full name of the computer that hosts the server and see if that helps.
"A Journey of a Thousand Rest Stops Begins with a Single Movement"
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Hello,
I can write code to read and write to excel and word.But I face problems with versions.A certain version works at my end and doesnt work at the client end.
I have included Microsoft Excel 12.0 Object Library at my end and found that the client didnt have this library .He had Microsoft Excel 5.0 Object Library .So I coded According to version 5.0 but still at the client end I am getting the error saying the Interop file doesnt exist.It works fine with me.
Can you tell me how do I nail down version problems and Is the COM coding for Microsoft Excel Word different for different versions.
Thanks
Pritha
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