C#

manustone wrote:

The point is that in doing this way ... the image includes also the open menu;

manustone wrote:

I need to call the function right after the menu item gets close

private Bitmap bmpScreenShot;
private Graphics gfxScreenShot;

private void takeScreenshotToolStripMenuItem_Click(object sender, EventArgs e)
{
    bmpScreenShot.Save(@"D:\temp\screenshot.png", System.Drawing.Imaging.ImageFormat.Png);
}

private void takeScreenshotToolStripMenuItem_MouseDown(object sender, MouseEventArgs e)
{
    bmpScreenShot = new Bitmap(Screen.PrimaryScreen.Bounds.Width, Screen.PrimaryScreen.Bounds.Height,
                                      System.Drawing.Imaging.PixelFormat.Format32bppArgb);

    gfxScreenShot = Graphics.FromImage(bmpScreenShot);

    gfxScreenShot.CopyFromScreen(Screen.PrimaryScreen.Bounds.X, Screen.PrimaryScreen.Bounds.Y, 0, 0,
                                 Screen.PrimaryScreen.Bounds.Size, CopyPixelOperation.SourceCopy);
}

rvdenden wrote:

var r = records.OrderByDescending(sort => sort.name1).OrderBy(sort2 => sort2.name2);;

MSDN - OrderBy[^]:

Because IOrderedEnumerable<telement> inherits from IEnumerable<t>, you can call OrderBy or OrderByDescending on the results of a call to OrderBy, OrderByDescending, ThenBy or ThenByDescending. Doing this introduces a new primary ordering that ignores the previously established ordering.

var r = records.OrderByDescending(sort => sort.name1).ThenBy(sort2 => sort2.name2);

Ramkithepower wrote:

Now I have to sort this class first by name1 and then by name2.

public int CompareTo(Record other)
{
   int res = name1.CompareTo(other.name1);
   
   if(res == 0)
       res = name2.CompareTo(other.name2);

   return res;
}

var sortedData = records.OrderBy(r => r.name1 + r.name2);

var sortedData = records.OrderBy(sort => sort.name1).ThenBy(sort2 => sort2.name2);

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