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select
EmployeeID,
EmployeeName,
YearStarted,
case
when YearStarted < 2007 then 'Veteran'
else 'Spring Chicken'
end NewColumn
from
Employees
me, me, me
"The dinosaurs became extinct because they didn't have a space program. And if we become extinct because we don't have a space program, it'll serve us right!"
Larry Niven
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Wouldn't only string functions work? Just guessing.
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Hi!
I was wondering what edition of SQL server i can install in win 7 ultimate!
Thanx.
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I use SQL Server 2008, if that helps.
me, me, me
"The dinosaurs became extinct because they didn't have a space program. And if we become extinct because we don't have a space program, it'll serve us right!"
Larry Niven
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yeah i forgot to say sql 2008!
but what i meant was which edition? standard? enterprise? ....?
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The OS has very little relevance of the edition you should use, it depends on your database requirements, This may help http://www.microsoft.com/sqlserver/2008/en/us/editions.aspx[^]
If you are asking about a development environment then use either developer or express versions.
Never underestimate the power of human stupidity
RAH
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For many years I have been using vb6 with Access Database as back end. In many cases while returning record sets Access is omitting the very first record and it returns the rest of the records. I am really baffled. Please help.
Hi all of you, I have corrected my mistake and got the answer for this question.
Here is how I got it solved. The records were stored with time field. When querying up I did not mention the begining of the starting day (like 00:01 - which implies the start time of the day) and the end of the day in the finishing date. (Thought up this solution very late.) And so I was getting a few records eliminated from the query result set.
Thanks for all of you who tried to help and you can consider my question closed.
Hope this helps somebody.
-- modified 1-Apr-16 12:47pm.
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Are you confusing zero-based and one-based indexing for arrays?
Otherwise, showing some code might help us help you.
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Whatever it returns first is the first. Or maybe you're using it wrong.
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Dear,
Can anyone help me to make good database structure?
What i have are some locations where I have some machines. Every machines have 2 counters (IN and OUT). I need to be able to enter state of that counters and after that to compare that values with previous entry IN and OUT counters.
How I see it seams that somewere I need to keep information wich machine is on wich location. Beside that I need to track information about date and time of entries.
Situation:
Location 1 -> machine1, machine2, machine3
Location 2 -> machine4
Location 3 -> machine5, machine6, machine7, machine8
....
I need 3 kind of reports:
○ Deference between new IN / OUT and some old IN/OUT counters for every machine
○ Total IN/OUT for some location
○ Total IN/OUT for all location
How I need to organize this datas?
Thanks for helping me,
akioki
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3 tables
Location
LocationID int identity(1,1)
Location varchar(20)
Machine
MachineID int identity (1,1)
LocationID int
Machine varchar(20)
TranTable
TranID identity (1,1)
MachineID
Direction
Date
This assumes a machine can have only 1 location and the machine can be checked in/out many times. Using a date on the transaction table will allow you to get durations, and state on a given date
Never underestimate the power of human stupidity
RAH
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Hi All,
I am using SQL Server 2005. My problem is that I am unable to start MSSQL Server. When I go to services.msc, i found that the state of MSSQLServer is stopped. When I click on start, it gives me this error:
The SQL Server (MSSQLSERVER) service on Local Computer started and then stopped. Some services stop automatically if they have no work to do, for example, the Performance Logs and Alerts Service.
I try all possible things, google it and atlast re-install SQL Server but nothing happen. So please help me??
Thanks
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Have you checked the event log to see if there are any messages relating to this in there?
me, me, me
"The dinosaurs became extinct because they didn't have a space program. And if we become extinct because we don't have a space program, it'll serve us right!"
Larry Niven
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2010-03-25 18:55:55.53 Server Microsoft SQL Server 2005 - 9.00.1399.06 (Intel X86)
Oct 14 2005 00:33:37
Copyright (c) 1988-2005 Microsoft Corporation
Developer Edition on Windows NT 5.1 (Build 2600: Service Pack 2)
2010-03-25 18:55:55.53 Server (c) 2005 Microsoft Corporation.
2010-03-25 18:55:55.53 Server All rights reserved.
2010-03-25 18:55:55.53 Server Server process ID is 2772.
2010-03-25 18:55:55.53 Server Logging SQL Server messages in file 'C:\Program Files\Microsoft SQL Server\MSSQL.2\MSSQL\LOG\ERRORLOG'.
2010-03-25 18:55:55.53 Server This instance of SQL Server last reported using a process ID of 212 at 3/25/2010 6:40:35 PM (local) 3/25/2010 1:10:35 PM (UTC). This is an informational message only; no user action is required.
2010-03-25 18:55:55.53 Server Registry startup parameters:
2010-03-25 18:55:55.53 Server -d C:\Program Files\Microsoft SQL Server\MSSQL.2\MSSQL\DATA\master.mdf
2010-03-25 18:55:55.53 Server -e C:\Program Files\Microsoft SQL Server\MSSQL.2\MSSQL\LOG\ERRORLOG
2010-03-25 18:55:55.53 Server -l C:\Program Files\Microsoft SQL Server\MSSQL.2\MSSQL\DATA\mastlog.ldf
2010-03-25 18:55:55.54 Server SQL Server is starting at normal priority base (=7). This is an informational message only. No user action is required.
2010-03-25 18:55:55.54 Server Detected 2 CPUs. This is an informational message; no user action is required.
2010-03-25 18:55:55.85 Server Using dynamic lock allocation. Initial allocation of 2500 Lock blocks and 5000 Lock Owner blocks per node. This is an informational message only. No user action is required.
2010-03-25 18:55:55.87 Server Attempting to initialize Microsoft Distributed Transaction Coordinator (MS DTC). This is an informational message only. No user action is required.
2010-03-25 18:55:56.90 Server Attempting to recover in-doubt distributed transactions involving Microsoft Distributed Transaction Coordinator (MS DTC). This is an informational message only. No user action is required.
2010-03-25 18:55:56.90 Server Database Mirroring Transport is disabled in the endpoint configuration.
2010-03-25 18:55:56.90 spid4s Starting up database 'master'.
2010-03-25 18:55:56.90 spid4s Error: 17207, Severity: 16, State: 1.
2010-03-25 18:55:56.90 spid4s FCB::RemoveAlternateStreams: Operating system error 6(The handle is invalid.) occurred while creating or opening file 'C:\Program Files\Microsoft SQL Server\MSSQL.2\MSSQL\DATA\master.mdf'. Diagnose and correct the operating system error, and retry the operation.
2010-03-25 18:55:57.07 spid4s SQL Trace ID 1 was started by login "sa".
2010-03-25 18:55:57.09 spid4s Starting up database 'mssqlsystemresource'.
2010-03-25 18:55:57.24 spid4s Server name is 'MAC5'. This is an informational message only. No user action is required.
2010-03-25 18:55:57.24 spid9s Starting up database 'model'.
2010-03-25 18:55:57.24 spid9s Error: 17207, Severity: 16, State: 1.
2010-03-25 18:55:57.24 spid9s FCB::RemoveAlternateStreams: Operating system error 6(The handle is invalid.) occurred while creating or opening file 'C:\Program Files\Microsoft SQL Server\MSSQL.2\MSSQL\DATA\model.mdf'. Diagnose and correct the operating system error, and retry the operation.
2010-03-25 18:55:57.37 spid9s Clearing tempdb database.
2010-03-25 18:55:57.42 Server A self-generated certificate was successfully loaded for encryption.
2010-03-25 18:55:57.42 Server Error: 17182, Severity: 16, State: 1.
2010-03-25 18:55:57.42 Server TDSSNIClient initialization failed with error 0x7e, status code 0x60.
2010-03-25 18:55:57.42 Server Error: 17182, Severity: 16, State: 1.
2010-03-25 18:55:57.42 Server TDSSNIClient initialization failed with error 0x7e, status code 0x1.
2010-03-25 18:55:57.42 Server Error: 17826, Severity: 18, State: 3.
2010-03-25 18:55:57.42 Server Could not start the network library because of an internal error in the network library. To determine the cause, review the errors immediately preceding this one in the error log.
2010-03-25 18:55:57.42 Server Error: 17120, Severity: 16, State: 1.
2010-03-25 18:55:57.42 Server SQL Server could not spawn FRunCM thread. Check the SQL Server error log and the Windows event logs for information about possible related problems.
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Yikes - wish I hadn't asked.
Okay, well, I'd be looking for the first reported error and concentrate on that:
Starting up database 'master'.<br />
Error: 17207, Severity: 16, State: 1.
Start with that and see how far you get. (If anyone else has a better suggestion now would be the time...)
me, me, me
"The dinosaurs became extinct because they didn't have a space program. And if we become extinct because we don't have a space program, it'll serve us right!"
Larry Niven
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Hello,
let's have the following simple example. An SQL table consists of three columns:
RecordId,
GenerationId,
Fitness.
RecordId is a unique key. GenerationId and Fitness columns contain values that might and do repeat themselves over many rows.
Now how to do a simple select of the unique RecordId which has the highest Fitness, grouped by GenerationId?
Obviously,
SELECT max(Fitness) FROM myTable GROUP BY GenerationId
returns the highest Fitness for each GenerationId, but how to get the particular row which has this highest Fitness?
Fitness values might repeat themselves for the same GenerationId values, so an aggregate function also has to be used to select a distinct RecordId for a particular GenerationId. It doesn't matter which RecordId is selected as long as it has the highest Fitness for the particular GenerationId.
Thank you very much for any ideas!
Michal
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the result should look something like this:
GenerationId, Fitness, RecordId
0,312.53,12
1,365.42,18
2,412.56,28
3,418.26,34
4,526.79,41
5,528.,48
...
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Do you have some sample data for the table that would be used to get the result you're looking for?
Scott
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yes, let's use the following sample data.
source table:
RecordId GenerationId Fitness
0 0 150.5
1 0 148.2
2 0 172.5
3 1 183.2
4 1 189.8
5 1 183.2
6 1 215.1
7 1 221.3
8 2 208.4
9 2 232.1
10 3 225.1
11 3 236.4
12 3 231.5
13 3 236.4
14 4 236.4
15 4 245.1
16 5 251.9
17 5 250.4
18 6 251.9
19 6 262.4
based on how one aggregates multiple rows with the same Fitness for the same GenerationId, one of the possible outcomes should look like the following. here I used max(RecordId), but it doesn't really matter:
GenerationId maxFitness RecordId
0 172.5 2
1 221.3 7
2 232.1 9
3 236.4 13
4 245.1 15
5 251.9 16
6 262.4 19
I'm able to achieve this result with joining the source table to itself, but I hope there has to be a more elegant way on how to do this without breaking one's neck with multiple lines of SQL code.
thanks for any help and ideas!
Michal
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SELECT g.GenerationId,
d.Fitness,
d.RecordId
FROM
(
SELECT DISTINCT GenerationId
FROM [Source]
) AS g
CROSS APPLY
(
SELECT TOP 1 s.RecordId, s.Fitness
FROM [Source] AS s
WHERE s.GenerationId = g.GenerationId
ORDER BY s.Fitness DESC
) AS d
ORDER BY g.GenerationId ASC
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Personally, I don't see a problem with joining to the source table itself, or an inline view built off of the source table, so I came up with this which returns your desired result:
SELECT cp.generationid, cp.fitness, MAX(cp.recordid)
FROM cp,
(SELECT generationid, MAX(fitness) maxfitness
FROM cp
GROUP BY generationid) view1
WHERE cp.fitness = view1.maxfitness AND cp.generationid = view1.generationid
GROUP BY cp.generationid, cp.fitness
ORDER BY 1, 2, 3
view1 is an inline view off of the original table that I'm joining to.
I saw i.j.russell's response, but I'm not familiar with it (I'll need to read up on it).
Scott
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Thank you very much for all your replies!
I used my original code with joining the table to itself at last. I was looking for some really simple way on how to handle this, but it looks there's no free lunch in T-SQL 
Thanks again for all your valuable input!
Michal
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Let's assume I have such table:
Pictures:
p_id
p_name
p_path
p_userId_mobile_addition [int]
p_userId_mobile_modification [int]
p_userId_www_addition [uniqueidentifier]
p_userId_www_modification [uniqueidentifier]
p_userId_mobile keys reference UsersMobile table.
p_userId_www keys reference UsersWWW table.
These keys give us information about the user that added or modified the picture. There are 4 keys as addition and modification can be performed with www or PocketPC interface.
How to create a view presenting:
1. p_id,
2. p_name,
3. p_path
4. username (from UsersMobile or UsersWWW) for addition
5. username for modification through www
6. username for modification through PocketPc
Platform: MS SQL Server 2005
Best regards,
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