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Hi findtango,
If you access the cache via the indexer, i.e.,
1. Cache["Key"] = value;
a. the value remains in the cache indefinitely.
Instead while you are using
2. cache.add():
a. It will accept some more parameters for expiration and all
b. Also, calling the Add method returns an object that represents the cached item.
If the key already exists in the Cache the method will fail.
Thanks & Regards,
Jeneesh k. v.
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Please give me a link or explain how will i write the code for checking duplicate user name is existing while trying to insert new one by using core ajax coding
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I think you can do it in Database by making query,
like in sqlserver
IF EXISTS(SELECT Id FROM user WHERE username = @username)
Duplicate
else
No Duplicate
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I have taken a DetailsView . Now I want to retrieve the details shown in detailsview in the panel in which there are many textboxes of respective fields.
like GridView in which we use "RowCommand" event , which event should i take to retrieve the details??
modified on Wednesday, January 6, 2010 7:02 AM
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Hi,
Could someone tell me how to open the .msg file as how we double click and open the .msg file. Please send code. Thanks for your help in advance
With Regards,
Samson
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Whats Your Requirement Here..!
1)You need to open .msg file and convert into txt file
2)Send the .msg file as Email..!
3)?????????????????
samsonx wrote: Please send code.
This is Considered as rude in here..!
Check This Link..!
http://dotnet.dzone.com/articles/how-parse-and-view-outloook-ms[^]
LatestArticle :Log4Net
Why Do Some People Forget To Mark as Answer .If It Helps.
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I am using a crystal report developed separately with crystal report developer ie BI.
I am going to use that report for my application.
i have loaded that report in the report document and i have set the same to the crystal report viewer.
but my concern here is while developing the report i have used a database and a server.
but while using the application the server and the database may come dynamically , i have used the ReportDoc.SetDatabaseLogon() but its of no use its asking me the same database which i used while developing the report,
how to change the same..
thanks for helping in advance
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Hi,
I have two buttons(BUTTON1,BUTTON2) and one object tag to display the video. Now when i click BUTTON1 i want to update the video. So <object> tag should be effected. But when i click BUTTON2, it should not effect the video. Here i used the update panel to achieve this.
<asp:updatepanel id="UpdatePanel1" runat="server" updatemode="Conditional">
<contenttemplate>
<object>
<tiggers>
<asp:asyncpostbacktrigger controlid="Button1" eventname="Click">
<asp:button id="Button1" runat="server" onclick="Button1_Click">
<asp:button id="Button2" runat="server" onclick="Button2_Click" >="">
In the above code i specified that - object tag(VIDEO) should be effected when we click on Button1 only. But it is blinking when we click on Button2 also. How can we prevent the blinking or refresh of the video when we click on Button2? Can anybody help us? Thanks in advance.
Padmaja N
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Hi Ravi Adabala,
where is your '</asp:updatepanel>' closing tag ?
The controls which needs to show the ajax effect, which should be
placed inside the updatepanel. others are exclude from the update
panel. second thing, you just replace Eventname='click' to 'Button1_click'
please try it....
Thanks & Regards,
Jeneesh k. v.
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Hi,
How to get the visitor's actual IP address.
I have tried all the possible solution like HttpContext.Current.Request.ServerVariables["HTTP_X_FORWARDED_FOR"],
UserHostAddress, Remote_ADDR etc etc. But all are returning the same IP that is I think proxy ip.
If we are behind the firewall/proxy then is there any way to get the local IP of the system like 100.100.100.27.
Please confirm.
Pankaj
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You don't. Thats exactly the purpose of proxy's.
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The below given code gives you the IP address of the User Accessing the site:
HttpContext.Current.Request.UserHostAddress;
OR
HttpContext.Current.Request.ServerVariables["REMOTE_ADDR"];
To get the IP address of the machine and not the proxy use the following code:
HttpContext.Current.Request.ServerVariables["HTTP_X_FORWARDED_FOR"];
I hope this was useful !!!
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I think he already mentioned these are not working for him.
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Hi pkp001,
As pd69 said,
HttpContext.Current.Request.UserHostAddress;
this code will return the IP of the requested machine.
Thanks & Regards,
Jeneesh k. v.
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Get the visitor's actual IP address?
Do you mean the visitor is using proxy?
Try this function:
Private Function getIP()
Dim strIPAddr
If Request.ServerVariables("HTTP_X_FORWARDED_FOR") = "" OR InStr(Request.ServerVariables("HTTP_X_FORWARDED_FOR"), "unknown") > 0 Then
strIPAddr = Request.ServerVariables("REMOTE_ADDR")
ElseIf InStr(Request.ServerVariables("HTTP_X_FORWARDED_FOR"), ",") > 0 Then
strIPAddr = Mid(Request.ServerVariables("HTTP_X_FORWARDED_FOR"), 1, InStr(Request.ServerVariables("HTTP_X_FORWARDED_FOR"), ",")-1)
ElseIf InStr(Request.ServerVariables("HTTP_X_FORWARDED_FOR"), ";") > 0 Then
strIPAddr = Mid(Request.ServerVariables("HTTP_X_FORWARDED_FOR"), 1, InStr(Request.ServerVariables("HTTP_X_FORWARDED_FOR"), ";")-1)
Else
strIPAddr = Request.ServerVariables("HTTP_X_FORWARDED_FOR")
End If
getIP = Trim(Mid(strIPAddr, 1, 30))
End Function
You can also get the visitor's IP by Request.UserHostAddress.
modified 27-May-14 5:05am.
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how to create Forum with ASP.net And C# coding for Persian (Farsi) Language ?
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Hi,
You will get some example of forums with source code, use google for it.To make it in Farsi language you have to use a concept of Localization. There are lot of tutorials are available for it.
Rock Star
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I have some controls that I want displayed if a manager see the form but not when non managers view the form.
How can I either make a complete row be invisible or generate the the row with the control on it when the manager is logged in? (yes I know if a manager has logged in or not) Please show sample code.
My preference is to have the row appear to not exist when non-manager is viewing the form with no blank space.
Then when a manager is viewing it would look like the manager row has been inserted into the proper place with all other rows being pushed down, so it appears that the row was always there.
thanks in advance...
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Hi Everybody,
I have developed a WCF Web Service using http and c# in VS 2008. But I needed to copy the application in to another folder in the machine. Then the .sln and .csproj files both were missing.
By searching on the machine I could able to get the .sln file. But .csproj file is still missing. I am unable to open the proejct.
Can anybody suggest me how to get it. And are there any settings avaible in VS 2008 IDE to give the current path as the path for these files.
Any link or blog is also very welcoming.
Thanks & Regards,
Md. Abdul Aleem
NIIT technologies
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Hi,
as far as I know there isn't a csproj-file for websites. I guess you are hosting the wcf-service as website so it is a website. Do the following:
1. Open the sln-file
2. Go to "Add Website" and select the root-directory of the wcf-service.
Let me know if this helped you.
Regards
Sebastian
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Yep. Its working fine.
Let me tell all steps to help others
1. Open the .sln file by using VS.Net version selector.
2. Then go the File menu -> Add -> Existing Web site
Thats it u r done. Save this solution where ever neccessary.
Thanks Sebastian its a great help.
Thanks & Regards,
Md. Abdul Aleem
NIIT technologies
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Hi,
I am having trouble coding something using visual web developer. I am trying to create an undirected, unweighted graph using an adjacency list of vertices. I have defined classes for Graph, GraphVertex and VertexList. Edges are to be laid out by each GraphVertex having a VertexList of its neighbouring vertices.
I can add vertices to my graph and access properties of the vertices but i run into a problem when i try to either add an edge to the graph or add a neighbour to an individual graph vertex, (essentially the same thing but i have tried both ways to no avail!).
If i try to add an edge to my graph i get the following error - "Value of type 'String' cannot be converted to 'GraphVertex(Of String)'."
And if i try to add a neighbour to another Vertices VertexList i get this - "Unable to cast object of type 'System.Int32' to type 'Vertex`1[System.String]'." (I have tried many data types and still get this error, it is not just because in this case i am using an integer.)
I imagine both problems stem from how my classes are coded but being a somewhat inexperienced programmer cant figure out what the problem is. I can post any of my implementation or class code if needed.
Any help on this would be appreciated.
Cheers.
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I have problem with this line of code in my asp.net page. Its showing error. Can anyone help me?
my Soucre Code is as follows:
<asp:datagrid style="Z-INDEX: 101; POSITION: absolute; TOP: 136px; LEFT: 192px" id="DataGrid1"
runat="server" AutoGenerateColumns="False">
<Columns>
<asp:TemplateColumn HeaderText="test">
<ItemTemplate>
<a href="www.yahoo.com?id=12" runat="server" id="h1">click</a>
<asp:TextBox runat="server" ID="Textbox1" NAME="Textbox1" Visible="False"></asp:TextBox>
</ItemTemplate>
</asp:TemplateColumn>
<asp:ButtonColumn Text="Button" HeaderText="edit" CommandName="ed"></asp:ButtonColumn>
<asp:TemplateColumn HeaderText="Invoice No">
<ItemTemplate>
<a id ="h2" runat="server" href= "frmViewInvoiceDetails.aspx?invoiceID=<%#DataBinder.Eval(Container,"DataItem.InvoiceID")%>">Click Here</a>
</ItemTemplate>
</asp:TemplateColumn>
</Columns>
</asp:datagrid>
Iam using VS 2003
When i changed to Design View i got the following error
Could not open in Design view. Quote values differently inside a '<% ..."value"... %>' block.
modified on Wednesday, January 6, 2010 1:23 AM
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It would be really helpful if you can provide the error message. Are you using any server control along with this? Can you provide full html source code?
Success is the good fortune that comes from aspiration, desperation, perspiration and inspiration.
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<asp:datagrid style="Z-INDEX: 101; POSITION: absolute; TOP: 136px; LEFT: 192px" id="DataGrid1"
runat="server" AutoGenerateColumns="False">
<Columns>
<asp:TemplateColumn HeaderText="test">
<ItemTemplate>
<a href="www.yahoo.com?id=12" runat="server" id="h1">click</a>
<asp:TextBox runat="server" ID="Textbox1" NAME="Textbox1" Visible="False"></asp:TextBox>
</ItemTemplate>
</asp:TemplateColumn>
<asp:ButtonColumn Text="Button" HeaderText="edit" CommandName="ed"></asp:ButtonColumn>
<asp:TemplateColumn HeaderText="Invoice No">
<ItemTemplate>
<a id ="h2" runat="server" href= "frmViewInvoiceDetails.aspx?invoiceID=<%#DataBinder.Eval(Container,"DataItem.InvoiceID")%>">Click Here</a>
</ItemTemplate>
</asp:TemplateColumn>
</Columns>
</asp:datagrid>
Iam using VS 2003
When i changed to Design View i got the following error
Could not open in Design view. Quote values differently inside a '<% ..."value"... %>' block.
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